EBK PRINCIPLES OF OPERATIONS MANAGEMENT
EBK PRINCIPLES OF OPERATIONS MANAGEMENT
11th Edition
ISBN: 9780135175644
Author: Munson
Publisher: VST
Question
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Chapter 9, Problem 23P

a)

Summary Introduction

To determine: The theoretical minimum number of workstations.

a)

Expert Solution
Check Mark

Answer to Problem 23P

The theoretical minimum number of workstations is 5 workstations.

Explanation of Solution

Given information:

Task Time (seconds) Immediate predecessors
A 40 -
B 30 A
C 50 A
D 40 B
E 6 B
F 25 C
G 15 C
H 20 D, E
I 18 F, G
J 30 H, I
Total 274  
  • Output is 60 iStars / hour

Calculation of cycle time:

The requirement is to produce 60 iStars / hour. Hence, the cycle time for one iStar will be:

Cycle time=60 iStars / hour60minutes / hour×60 seconds=1×60 seconds=60 seconds / iStar

Formula to calculate theoretical minimum number of workstations:

Workstations=Total task timeCycle time

Calculation of theoretical minimum number of workstations:

Workstations=27460=4.57=5 workstations

The theoretical minimum number of workstations is 5 workstations.

b)

Summary Introduction

To balance: The assembly line.

b)

Expert Solution
Check Mark

Explanation of Solution

Precedence diagram:

EBK PRINCIPLES OF OPERATIONS MANAGEMENT, Chapter 9, Problem 23P

List of most following tasks:

Tasks Following tasks
A 9
B 4
C 4
D 2
E 2
F 2
G 2
H 1
I 1
J 0

Assignment of different tasks to different workstations:

Workstation Elligible tasks Selected tasks Task time (seconds) Available cycle time (seconds) Remarks
1 60
A A 40 20
B,C 20 (Idle time) Cycle time is less than task time
2 60
B, C C 7 50 Tie broken randomnly
B, F, G 10 (Idle time) Cycle time is less than task time
3 60
B, F, G B 30 30 Task B has most following tasks.
D, E, F, G F 25 24 Tie broken randomnly
D, E, G 1 (Idle time) Cycle time is less than task time
4 60
D, E, G D 40 20 Tie broken randomnly
E, G G 15 5 Tie broken randomnly
E,I 5 (Idle time) Cycle time is less than task time
5 60
E, I E 6 54 Task E has most following tasks.
I, H H 20 34 Tie broken randomnly
I I 18 2 Task I is only elligible task
2 (Idle time)
6 60
J J 30 30 Task J is the remaining task
30 (Idle time)
Workstation Task assigned Idle time
1 A 20
2 C 10
3 B, F 1
4 D, G 5
5 E, H, I 2
6 J 30
Total 68

c)

Summary Introduction

To determine: The actual number of workstations.

c)

Expert Solution
Check Mark

Answer to Problem 23P

The actual number of workstations is 6.

Explanation of Solution

Workstation Task assigned Idle time
1 A 20
2 C 10
3 B, F 1
4 D, G 5
5 E, H, I 2
6 J 30
Total 68

The actual number of workstations is 6.

d)

Summary Introduction

To determine: The efficiency.

Introduction:

Efficiency:

Efficiency is the measure of  what is actually produced as opposed to what can be theoretically produced with the same amount of resources.

d)

Expert Solution
Check Mark

Answer to Problem 23P

The efficiency is 76.11%.

Explanation of Solution

Formula to calculate efficiency:

Efficiency=Total task timeNumber of workstations×Cycle time×100

Calculation of efficiency:

Efficiency=2746×60×100=274,00360=76.11%

The efficiency is 76.11%.

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