Chapter 8.7, Problem 4CE

To determine

Find the value of given algebraic function at the different value of x.

Answer to Problem 4CE

The solution is

  $f(x=-3)=-12+27=\text{15}$

  

Explanation of Solution

Given: The function is given

  $f(x)=4x-x^3$

Calculation:

The function is given

  $f(x)=4x-x^3$

The put the value of x into the function and get the solution

Let’s take $x=-3$ , then

  $f(x=-3)=-12+27=\text{15}$

Similarly, we will repeat the process for all value of x the sketch a graph to show the variation of function at different x.

program:

clc
clear
close all
symsx
f=4*x-x^3;
a=[-3,-2,-1,0,1,2,3];
fori=1:7
    b(i)=double(subs(f,x,a(i)));
end
plot(a,b,'linewidth',1.2)
set(gca,'linewidth',1.2,'Fontsize',12)
axis square

Query:

• First, we have defined the given algebraic relation.
• Then define the value of x.
• Put the value of x into the equation and solve.
• After solving we get the solution then sketch a graph.