Chapter 8, Problem 14MS

To determine

To find: The complete factor and writ “prime” if polynomial cannot be factored.

Answer to Problem 14MS

The complete factor of polynomial is $\left(4n-8\right)\left(n-2\right)$ .

Explanation of Solution

Given information:

The given polynomial is $4n^2-16n+16$ .

Calculation:

Consider the polynomial.

  $4n^2-16n+16$

Factorize the equation.

  $\begin{array}{l}4n^2-16n+16=4n^2-8n-8n+16\\ =4n\left(n-2\right)-8\left(n-2\right)\\ =\left(4n-8\right)\left(n-2\right)\end{array}$

Therefore, the factor of polynomial is $\left(4n-8\right)\left(n-2\right)$ .