Chapter 8.1, Problem 3CE

To determine

Find the value of given algebraic function.

Answer to Problem 3CE

The solution is

  $\begin{array}{l}f(1,2)=0\\ f(6,0)=-6\end{array}$

Explanation of Solution

Given: The functions are given

  $f(x,y)=xy+y^2-6$

And the value of pairs is

  $(x,y)=(1,2),(6,0)$

Calculation:

Let’s put the value of each pair into the function

We know that the function

  $f(x,y)=xy+y^2-6$

Just Put the value and get

  $f(1,2)=2+4-6=0$

Then similarly for

  $f(6,0)=0+0-6=-6$

program:

clc
clear
close all
symsxy
f=y*x+y^2-6;
a=subs(f,[x,y],[1,2])
b=subs(f,[x,y],[6,0])

Query:

• First, we have defined the given algebraic relation.
• Then define the value of x and y.
• Get the solution.