Chapter 8.1, Problem 6CE

To determine

Find the value of given algebraic function.

Answer to Problem 6CE

The solution is

  $\begin{array}{l}f(3,-2)=0\\ f(3,2)=0\end{array}$

Explanation of Solution

Given: The functions are given

  $f(x,y)=x^2+{\left(xy\right)}^2-45$

And the value of pairs is

  $(x,y)=(3,-2),(3,2)$

Calculation:

Let’s put the value of each pair into the function

We know that the function

  $f(x,y)=x^2+{\left(xy\right)}^2-45$

Just Put the value and get

  $f(3,-2)=9+36-45=0$

Then similarly for

  $f(3,2)=9+36-45=0$

program:

clc
clear
close all
symsxy
f=x^2+(x*y)^2-45;
a=subs(f,[x,y],[3,-2])
b=subs(f,[x,y],[3,2])

Query:

• First, we have defined the given algebraic relation.
• Then define the value of x and y.
• Get the solution.