Chapter 8.7, Problem 2CE

To determine

Find the value of given algebraic function at the different value of x.

Answer to Problem 2CE

The solution is

  $f(x=0,1,-1,-2)=\text{[2,6,0,0]}$

  

Explanation of Solution

Given: The function is given

  $f(x)=x^2+3x+2$

Calculation:

The function is given

  $f(x)=x^2+3x+2$

The put the value of x into the function and get the solution

Let’s take $x=0$ , then

  $f(x=-2)=0+0+2=2$

Similarly, we will repeat the process for all value of x the sketch a graph to show the variation of function at different x.

program:

clc
clear
close all
symsx
f=x^2+3*x+2;
a=[0 1 -1 -2];
fori=1:4
    b(i)=double(subs(f,x,a(i)));
end
plot(a,b,'linewidth',1.2)
set(gca,'linewidth',1.2,'Fontsize',12)
axis square

Query:

• First, we have defined the given algebraic relation.
• Then define the value of x.
• Put the value of x into the equation and solve.
• After solving we get the solution then sketch a graph.