Chapter 8.7, Problem 3CE

To determine

Find the value of given algebraic function at the different value of x.

Answer to Problem 3CE

The solution is

  $f(x=-10,-2,0,2,10)=\text{[0}\text{.0099,0}\text{.2000,1,0}\text{.2000,0}\text{.0099]}$

  

Explanation of Solution

Given: The function is given

  $f(x)=\frac{1}{x^2+1}$

Calculation:

The function is given

  $f(x)=\frac{1}{x^2+1}$

The put the value of x into the function and get the solution

Let’s take $x=-10$ , then

  $f(x=-10)=\frac{1}{100+1}=0.0099$

Similarly, we will repeat the process for all value of x the sketch a graph to show the variation of function at different x.

program:

clc
clear
close all
symsx
f=1/(x^2+1);
a=[-10 -2 0 2 10];
fori=1:5
    b(i)=double(subs(f,x,a(i)));
end
plot(a,b,'linewidth',1.2)
set(gca,'linewidth',1.2,'Fontsize',12)
axis square

Query:

• First, we have defined the given algebraic relation.
• Then define the value of x.
• Put the value of x into the equation and solve.
• After solving we get the solution then sketch a graph.