Chapter 8.7, Problem 16E

To determine

To find:

The value of $f(4)+g(-3)$ .

Answer to Problem 16E

Thevalue of $f(4)+g(-3)$ would be $-45$ .

Explanation of Solution

Given:

Two functions: $f(x)=-3x+1$ and $g(x)=10x-4$

Calculation:

We will find our indicated valuesas shown below:

  $\begin{array}{l}f(x)=-3x+1\left(\text{Given function}\right)\\ f(4)=-3(4)+1\left(\text{Substituting }x=4\right)\\ f(4)=-12+1\\ f(4)=-11\end{array}$

  $\begin{array}{l}g(x)=10x-4\left(\text{Given function}\right)\\ g(-3)=10(-3)-4\left(\text{Substituting }x=-3\right)\\ g(-3)=-30-4\\ g(-3)=-34\end{array}$

Now we will add $f(4)\text{and }g(-3)$ as:

  $\begin{array}{l}f(4)+g(-3)=-11+(-34)\\ f(4)+g(-3)=-11-34\\ f(4)+g(-3)=-45\end{array}$

Therefore, the value $f(4)+g(-3)$ would be $-45$ .