To determine Motor output power using the efficiency of motor. Explanation Write the expression to calculate the area of pipe. A = π 4 D 2 (I) Here, the diameter of pipe is D . Write the expression for the discharge. Q = A V (II) Here, velocity is V . Write the equation for Reynolds number. Re = ρ V D μ (III) Here, the density of the fluid is ρ , the velocity of the fluid is V and the dynamic viscosity of fluid is μ . Write the expression for the major head loss ( h L ) m a j o r . ( h L ) m a j o r = f l V 2 2 g D (IV) Here, friction factor is f , length of the pipe is l , velocity is v , acceleration due to gravity is g , and diameter of the pipe is D . Write the head loss due to the square edge entrance. h e n = 0.5 V 2 2 g (V) Write the expression for the total head loss of the pump. h L = ( Δ h ) + h f + h e n (VI) Here, head difference is Δ h . Write the expression for the power input. P i n = ρ g Q h l o s s (VII) Write the expression for the efficiency of the motor. η P = P input P ourput (VIII) Here, power input is P i n p u t and power output is p o u t . Conclusion: Substitute 30 cm for D in equation (I). A = π 4 ( 30 cm ) 2 A = π 4 ( 30 mm × 1 m 100 cm ) 2 = 0 .071 m 2 Substitute 10 m 3 /min for Q and 0.071 m 2 for V in equation (II). 10 m 3 min × 1 min 60 s = 0.071 m 2 × V V = 10 60 × 0.071 V = 2.35 m/s Refer table B.1, “Physical properties of water” at a temperature of 15 ° C , ρ = 999.2 kg/m 3 μ = 0.001139 × 10 − 3 kg / m ⋅ s Substitute 999.2 kg/m 3 for ρ , 2.35 m/s for v , 0.3 m for D , and 0.001139 × 10 − 3 kg / m ⋅ s for μ in equation (III). Re = 999.2 kg/m 3 × 2.35 m/s × 30 cm 0.001139 × 10 − 3 kg / m ⋅ s Re = 999

Munson, Young and Okiishi's Fundamentals of Fluid Mechanics, Binder Ready Version

8th Edition

ISBN: 9781119080701

Author: Philip M. Gerhart, Andrew L. Gerhart, John I. Hochstein

Publisher: WILEY

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Chapter 8.5, Problem 75P

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Motor output power using the efficiency of motor.

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Chapter 8.5, Problem 74P

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Munson, Young and Okiishi's Fundamentals of Fluid Mechanics, Binder Ready Version

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