To solve the following system of linear equations using inverse matrix
{0.2x−0.6y=2.4−x+1.4y=−8.8

Answer to Problem 50E
x=6,y=−2
Explanation of Solution
Given:
{0.2x−0.6y=2.4−x+1.4y=−8.8
Concept used:
To find inverse of a square matrix A, following steps should be followed.
- Augment given matrix with the identity matrix
- Perform row operations to make the identity matrix to the left and the right matrix becomes inverse matrix.
In this way, inverse matrix of a matrix can be obtained.
Formula used:
AX=B⇔X=A−1B
Calculation:
Consider given system of equations,
{0.2x−0.6y=2.4−x+1.4y=−8.8
Writing above system of linear equations in matrix form (AX=B) ,
[0.2−0.6−11.4][xy]=[2.4−8.8]
Here,
A=[0.2−0.6−11.4]X=[xy]B=[2.4−8.8]
Now, find the inverse matrix of matrix A.
Step 1: Augmenting matrix A with the identity matrix
[0.2−0.6−11.41001]
Step 2: Performing row operations to make the identity matrix to the left.
[0.2−0.6−11.41001]Performing R2=R2+5R1[0.2−0.60−1.61051]Performing R1=5R1[1−30−1.65051]Performing R2=−0.625R2[1−30150−3.125−0.625]
Performing R1=R1+3R2[1001−4.375−1.875−3.125−0.625]
So, inverse matrix is,
A−1=[−4.375−1.875−3.125−0.625]
Now, applying the formula AX=B⇔X=A−1B ,
[0.2−0.6−11.4][xy]=[2.4−8.8]⇔[xy]=[−4.375−1.875−3.125−0.625][2.4−8.8]
Finding the solutions,
⇒[xy]=[−4.375−1.875−3.125−0.625][2.4−8.8]⇒[xy]=[−4.375×2.4−1.875×(−8.8)−3.125×2.4−0.625×(−8.8)]⇒[xy]=[−10.5+16.5−7.5+5.5]⇒[xy]=[6−2]
Conclusion:
Therefore, the solution to given system of equations is x=6,y=−2.
Chapter 8 Solutions
EBK PRECALCULUS W/LIMITS
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