Chapter 8.2, Problem 76E

To determine

To find:Compute $BA$ and interpret the result.

Answer to Problem 76E

  $BA=\left[\begin{array}{cc}17699050& 17299050\end{array}\right]$

The total price for all three models that were shipped to warehouse 1 is $\$17,699,050$ and that were shipped to warehouse 2 is $\$17,299,050$ .

Explanation of Solution

Given information:

An electronics manufacturer produces three models of high-definition televisions, which are shipped to two warehouses. The shipment levels are represented by $A$ .

  

The prices per unit are represented by the matrix

  $B=\left[\begin{array}{ccc}\$699.95& \$899.95& \$1099.95\end{array}\right]$

Calculations:

Computing $BA$ :

  $\begin{array}{l}BA=\left[\begin{array}{ccc}699.95& 899.95& 1099.95\end{array}\right]\left[\begin{array}{cc}5000& 4000\\ 6000& 10000\\ 8000& 5000\end{array}\right]\\ =\left[\begin{array}{cc}699.95\times 5000+899.95\times 6000+1099.95\times 8000& 699.95\times 4000+899.95\times 10000+1099.95\times 5000\end{array}\right]\\ =\left[\begin{array}{cc}17699050& 17299050\end{array}\right]\end{array}$

Conclusion:

Thus, the total price for all three models that were shipped to warehouse 1 is $\$17,699,050$ and that were shipped to warehouse 2 is $\$17,299,050$ .