(a) Interpretation: To draw the mixture of enantiomers A and B obtained from cis and Trans isomers of 1-bromo-4-tert-butylcyclohexane with KOC (CH 3 ) 3 . Concept introduction: The most common mechanism for dehydrohalogenation is the E2 mechanism. An E2 reaction exhibits a second-order kinetics, in which the reaction is bimolecular and both the alkyl halide and the base appear in the rate equation. The most straightforward explanation for the second-order kinetics is a concerted reaction: all bonds are broken and formed in a single step. In other words simultaneously all bonds are broken and formed. The transition state of an E2 reaction consists of four atoms from the alkyl halide-one hydrogen atom, two carbon atoms, and the leaving group (X)-all aligned in the same plane. There are two ways for the C-H and C-x bonds to be coplanar. When the H and X atoms oriented on the same side of the molecule. This geometry is called syn periplanar. While the H and X atoms oriented on opposite sides of the molecule. This geometry is called anti periplanar. The dihedral angle for the C-H and C-X bonds equals 0° for the syn periplanar arrangement and 180° for the anti periplanar arrangement. Whereas the E1 reaction is a twostep reaction of first order kinetics. The two steps reaction is the bond to the leaving group breaks first before the π bond is formed.

Question

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Answer 1

Question

Chapter 8, Problem 8.57P

Interpretation Introduction

(a)

Interpretation:

To draw the mixture of enantiomers A and B obtained from cis and Trans isomers of 1-bromo-4-tert-butylcyclohexane with KOC (CH₃)₃.

Concept introduction:

The most common mechanism for dehydrohalogenation is the E2 mechanism. An E2 reaction exhibits a second-order kinetics, in which the reaction is bimolecular and both the alkyl halide and the base appear in the rate equation. The most straightforward explanation for the second-order kinetics is a concerted reaction: all bonds are broken and formed in a single step. In other words simultaneously all bonds are broken and formed.

The transition state of an E2 reaction consists of four atoms from the alkyl halide-one hydrogen atom, two carbon atoms, and the leaving group (X)-all aligned in the same plane. There are two ways for the C-H and C-x bonds to be coplanar. When the H and X atoms oriented on the same side of the molecule. This geometry is called syn periplanar. While the H and X atoms oriented on opposite sides of the molecule. This geometry is called anti periplanar. The dihedral angle for the C-H and C-X bonds equals 0° for the syn periplanar arrangement and 180° for the anti periplanar arrangement.

Whereas the E1 reaction is a twostep reaction of first order kinetics. The two steps reaction is the bond to the leaving group breaks first before the π bond is formed.

Expert Solution

Answer to Problem 8.57P

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 1

Explanation of Solution

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 2

The elimination of the Br from the reactant using base to form the respective alkene.

Conclusion

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 3

Interpretation Introduction

(b)

Interpretation:

To determine the isomer that reacts faster with KOC(CH₃)₃.

Concept introduction:

The most common mechanism for dehydrohalogenation is the E2 mechanism. An E2 reaction exhibits a second-order kinetics, in which the reaction is bimolecular and both the alkyl halide and the base appear in the rate equation. The most straightforward explanation for the second-order kinetics is a concerted reaction: all bonds are broken and formed in a single step. In other words simultaneously all bonds are broken and formed.

The transition state of an E2 reaction consists of four atoms from the alkyl halide-one hydrogen atom, two carbon atoms, and the leaving group (X)-all aligned in the same plane. There are two ways for the C-H and C-x bonds to be coplanar. When the H and X atoms oriented on the same side of the molecule. This geometry is called syn periplanar. While the H and X atoms oriented on opposite sides of the molecule. This geometry is called anti periplanar. The dihedral angle for the C-H and C-X bonds equals 0° for the syn periplanar arrangement and 180° for the anti periplanar arrangement.

Whereas the E1 reaction is a twostep reaction of first order kinetics. The two steps reaction is the bond to the leaving group breaks first before the π bond is formed.

Expert Solution

Answer to Problem 8.57P

The bulky tert-butyl group in the cyclohexane ring is in the equatorial position.

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 4

In the cis-isomer, the Br is in the axial position. So cis-isomer is faster than the trans-isomer.

Explanation of Solution

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 5

The bulky tert-butyl group in the cyclohexane ring is in the equatorial position. The cis isomer has the Br in the axial position while in the trans isomer the Br is in the equatorial position. For the dehydrogenation to occur, the halogen must be in the axial position to afford trans diaxial elimination of H and X. Thus the cis isomer react faster than trans where the Br lies in the equatorial position.

Conclusion

Thus cis-isomer is faster than the trans-isomer due to axial position of Br in the structure.

Interpretation Introduction

(c)

Interpretation:

To draw the structures for C and D from cis and trans-1-bromo-4-tert-butylcyclohexane with NaOCH_3.

Concept introduction:

The most common mechanism for dehydrohalogenation is the E2 mechanism. An E2 reaction exhibits a second-order kinetics, in which the reaction is bimolecular and both the alkyl halide and the base appear in the rate equation. The most straightforward explanation for the second-order kinetics is a concerted reaction: all bonds are broken and formed in a single step. In other words simultaneously all bonds are broken and formed.

The transition state of an E2 reaction consists of four atoms from the alkyl halide-one hydrogen atom, two carbon atoms, and the leaving group (X)-all aligned in the same plane. There are two ways for the C-H and C-x bonds to be coplanar. When the H and X atoms oriented on the same side of the molecule. This geometry is called syn periplanar. While the H and X atoms oriented on opposite sides of the molecule. This geometry is called anti periplanar. The dihedral angle for the C-H and C-X bonds equals 0° for the syn periplanar arrangement and 180° for the anti periplanar arrangement.

Whereas the E1 reaction is a twostep reaction of first order kinetics. The two steps reaction is the bond to the leaving group breaks first before the π bond is formed.

Expert Solution

Answer to Problem 8.57P

cis -1-bromo-4-tert-butylcyclohexane with NaOCH₃ forms the product

trans-1-bromo-4-tert-butylcyclohexane with NaOCH₃ forms the product

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 7

Explanation of Solution

The major products C and D formed when cis and trans-1-bromo-4-tert-butylcyclohexane reacts with NaOCH₃ is shown. The respective reaction takes place by SN2 reaction mechanism that is by backside attack of the nucleophile.

.

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 8

Conclusion

cis -1-bromo-4-tert-butylcyclohexane with NaOCH₃ forms the product.

trans-1-bromo-4-tert-butylcyclohexane with NaOCH₃ forms the product.

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 10

Interpretation Introduction

(d)

Interpretation:

To determine the isomer that reacts faster with NaOCH₃.

Concept introduction:

The most common mechanism for dehydrohalogenation is the E2 mechanism. An E2 reaction exhibits a second-order kinetics, in which the reaction is bimolecular and both the alkyl halide and the base appear in the rate equation. The most straightforward explanation for the second-order kinetics is a concerted reaction: all bonds are broken and formed in a single step. In other words simultaneously all bonds are broken and formed.

The transition state of an E2 reaction consists of four atoms from the alkyl halide-one hydrogen atom, two carbon atoms, and the leaving group (X)-all aligned in the same plane. There are two ways for the C-H and C-x bonds to be coplanar. When the H and X atoms oriented on the same side of the molecule. This geometry is called syn periplanar. While the H and X atoms oriented on opposite sides of the molecule. This geometry is called anti periplanar. The dihedral angle for the C-H and C-X bonds equals 0° for the syn periplanar arrangement and 180° for the anti periplanar arrangement.

Whereas the E1 reaction is a twostep reaction of first order kinetics. The two steps reaction is the bond to the leaving group breaks first before the π bond is formed.

Expert Solution

Answer to Problem 8.57P

The cis -1-bromo-4-tert-butylcyclohexane reacts faster when compared to trans-1-bromo-4-tert-butylcyclohexane.

cis -1-bromo-4-tert-butylcyclohexane with NaOCH₃.

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 11

trans-1-bromo-4-tert-butylcyclohexane with NaOCH₃

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 12

Explanation of Solution

NaOCH_3, is a strong nucleophile. The reaction follows the SN2 in which the backside attack occurs. With the cis isomer the nucleophile can attack by the equatorial position to avoid the 1, 3-diaxial interaction. Moreover only the cis isomer has the Br and Β carbon in the anti periplanar that is in trans diaxial arrangement when compared to trans isomer. Thus the cis isomer reacts faster than trans isomer.

cis -1-bromo-4-tert-butylcyclohexane with NaOCH₃

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 13

trans-1-bromo-4-tert-butylcyclohexane with NaOCH₃

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 14

Conclusion

Thus the cis -1-bromo-4-tert-butylcyclohexane reacts faster when compared to trans-1-bromo-4-tert-butylcyclohexane

Interpretation Introduction

(e)

Interpretation:

To explain why there is different products formed when the alkyl halides uses two different alkoxides.

Concept introduction:

The most common mechanism for dehydrohalogenation is the E2 mechanism. An E2 reaction exhibits a second-order kinetics, in which the reaction is bimolecular and both the alkyl halide and the base appear in the rate equation. The most straightforward explanation for the second-order kinetics is a concerted reaction: all bonds are broken and formed in a single step. In other words simultaneously all bonds are broken and formed.

The transition state of an E2 reaction consists of four atoms from the alkyl halide-one hydrogen atom, two carbon atoms, and the leaving group (X)-all aligned in the same plane. There are two ways for the C-H and C-x bonds to be coplanar. When the H and X atoms oriented on the same side of the molecule. This geometry is called syn periplanar. While the H and X atoms oriented on opposite sides of the molecule. This geometry is called anti periplanar. The dihedral angle for the C-H and C-X bonds equals 0° for the syn periplanar arrangement and 180° for the anti periplanar arrangement.

Whereas the E1 reaction is a twostep reaction of first order kinetics. The two steps reaction is the bond to the leaving group breaks first before the π bond is formed.

Expert Solution

Answer to Problem 8.57P

The bulky base ^–OC(CH₃)₃ favours the elimination by an E2 reaction mechanism, to get a mixture of enantiomers A and B. The strong nucleophile ^–OCH₃ favours nucleophile substitution by an SN2 mechanism. Inversion of configuration results from backside attack of the nucleophile. Thus different product are formed.

Explanation of Solution

^-OCH_3, is a strong nucleophile. The reaction follows the SN2 in which the backside attack occurs. With the cis isomer the nucleophile can attack by the equatorial position to avoid the 1, 3-diaxial interaction. Moreover only the cis isomer has the Br and Β carbon in the anti periplanar that is in trans diaxial arrangement when compared to trans isomer. Thus the cis isomer reacts faster than trans isomer. The bulky base ^–OC(CH₃)₃ favours the elimination by an E2 reaction mechanism, to get a mixture of enantiomers A and B.

Conclusion

Thus different product are formed when the alkyl halides uses two different alkoxides are used.

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Students have asked these similar questions

Draw the structures of the products obtained from the reaction of each enantiomer of cis-1-chloro-2-isopropylcyclopentane with sodium methoxide in methanol. b. Are all the products optically active? c. How would the products differ if the starting material were the trans isomer? Are these products optically active? d. Will the cis enantiomers or the trans enantiomers form substitution products more rapidly? e. Will the cis enantiomers or the trans enantiomers form elimination products more rapidly?

Substitution and Elimination (Please draw the structures involved in the reactions) A. Which will react more rapidly via SN1? 1-bromo-2,2-dimethylpropane or 2-bromo-2- methylbutane? Explain. B. Which will react faster via SN2? 1-chlorocyclohexane or 1-chloro-1-methylcyclohexane? Explain.

Pick the reactant or solvent in each part that gives the faster elimination reaction.a. reaction of -OH with 1-chloro-1-methylcyclohexane or 1-chloro-3-methylcyclohexaneb. reaction of H2O with CH3CH(Cl)CH2CH3 or (CH3)2C(Cl)CH2CH3c. reaction of (CH3)3CCl with -OH in H2O or DMSO

Answer 2

Question

Chapter 8, Problem 8.57P

Interpretation Introduction

(a)

Interpretation:

To draw the mixture of enantiomers A and B obtained from cis and Trans isomers of 1-bromo-4-tert-butylcyclohexane with KOC (CH₃)₃.

Concept introduction:

The most common mechanism for dehydrohalogenation is the E2 mechanism. An E2 reaction exhibits a second-order kinetics, in which the reaction is bimolecular and both the alkyl halide and the base appear in the rate equation. The most straightforward explanation for the second-order kinetics is a concerted reaction: all bonds are broken and formed in a single step. In other words simultaneously all bonds are broken and formed.

The transition state of an E2 reaction consists of four atoms from the alkyl halide-one hydrogen atom, two carbon atoms, and the leaving group (X)-all aligned in the same plane. There are two ways for the C-H and C-x bonds to be coplanar. When the H and X atoms oriented on the same side of the molecule. This geometry is called syn periplanar. While the H and X atoms oriented on opposite sides of the molecule. This geometry is called anti periplanar. The dihedral angle for the C-H and C-X bonds equals 0° for the syn periplanar arrangement and 180° for the anti periplanar arrangement.

Whereas the E1 reaction is a twostep reaction of first order kinetics. The two steps reaction is the bond to the leaving group breaks first before the π bond is formed.

Expert Solution

Answer to Problem 8.57P

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 1

Explanation of Solution

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 2

The elimination of the Br from the reactant using base to form the respective alkene.

Conclusion

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 3

Interpretation Introduction

(b)

Interpretation:

To determine the isomer that reacts faster with KOC(CH₃)₃.

Concept introduction:

The most common mechanism for dehydrohalogenation is the E2 mechanism. An E2 reaction exhibits a second-order kinetics, in which the reaction is bimolecular and both the alkyl halide and the base appear in the rate equation. The most straightforward explanation for the second-order kinetics is a concerted reaction: all bonds are broken and formed in a single step. In other words simultaneously all bonds are broken and formed.

The transition state of an E2 reaction consists of four atoms from the alkyl halide-one hydrogen atom, two carbon atoms, and the leaving group (X)-all aligned in the same plane. There are two ways for the C-H and C-x bonds to be coplanar. When the H and X atoms oriented on the same side of the molecule. This geometry is called syn periplanar. While the H and X atoms oriented on opposite sides of the molecule. This geometry is called anti periplanar. The dihedral angle for the C-H and C-X bonds equals 0° for the syn periplanar arrangement and 180° for the anti periplanar arrangement.

Whereas the E1 reaction is a twostep reaction of first order kinetics. The two steps reaction is the bond to the leaving group breaks first before the π bond is formed.

Expert Solution

Answer to Problem 8.57P

The bulky tert-butyl group in the cyclohexane ring is in the equatorial position.

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 4

In the cis-isomer, the Br is in the axial position. So cis-isomer is faster than the trans-isomer.

Explanation of Solution

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 5

The bulky tert-butyl group in the cyclohexane ring is in the equatorial position. The cis isomer has the Br in the axial position while in the trans isomer the Br is in the equatorial position. For the dehydrogenation to occur, the halogen must be in the axial position to afford trans diaxial elimination of H and X. Thus the cis isomer react faster than trans where the Br lies in the equatorial position.

Conclusion

Thus cis-isomer is faster than the trans-isomer due to axial position of Br in the structure.

Interpretation Introduction

(c)

Interpretation:

To draw the structures for C and D from cis and trans-1-bromo-4-tert-butylcyclohexane with NaOCH_3.

Concept introduction:

The most common mechanism for dehydrohalogenation is the E2 mechanism. An E2 reaction exhibits a second-order kinetics, in which the reaction is bimolecular and both the alkyl halide and the base appear in the rate equation. The most straightforward explanation for the second-order kinetics is a concerted reaction: all bonds are broken and formed in a single step. In other words simultaneously all bonds are broken and formed.

The transition state of an E2 reaction consists of four atoms from the alkyl halide-one hydrogen atom, two carbon atoms, and the leaving group (X)-all aligned in the same plane. There are two ways for the C-H and C-x bonds to be coplanar. When the H and X atoms oriented on the same side of the molecule. This geometry is called syn periplanar. While the H and X atoms oriented on opposite sides of the molecule. This geometry is called anti periplanar. The dihedral angle for the C-H and C-X bonds equals 0° for the syn periplanar arrangement and 180° for the anti periplanar arrangement.

Whereas the E1 reaction is a twostep reaction of first order kinetics. The two steps reaction is the bond to the leaving group breaks first before the π bond is formed.

Expert Solution

Answer to Problem 8.57P

cis -1-bromo-4-tert-butylcyclohexane with NaOCH₃ forms the product

trans-1-bromo-4-tert-butylcyclohexane with NaOCH₃ forms the product

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 7

Explanation of Solution

The major products C and D formed when cis and trans-1-bromo-4-tert-butylcyclohexane reacts with NaOCH₃ is shown. The respective reaction takes place by SN2 reaction mechanism that is by backside attack of the nucleophile.

.

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 8

Conclusion

cis -1-bromo-4-tert-butylcyclohexane with NaOCH₃ forms the product.

trans-1-bromo-4-tert-butylcyclohexane with NaOCH₃ forms the product.

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 10

Interpretation Introduction

(d)

Interpretation:

To determine the isomer that reacts faster with NaOCH₃.

Concept introduction:

The most common mechanism for dehydrohalogenation is the E2 mechanism. An E2 reaction exhibits a second-order kinetics, in which the reaction is bimolecular and both the alkyl halide and the base appear in the rate equation. The most straightforward explanation for the second-order kinetics is a concerted reaction: all bonds are broken and formed in a single step. In other words simultaneously all bonds are broken and formed.

The transition state of an E2 reaction consists of four atoms from the alkyl halide-one hydrogen atom, two carbon atoms, and the leaving group (X)-all aligned in the same plane. There are two ways for the C-H and C-x bonds to be coplanar. When the H and X atoms oriented on the same side of the molecule. This geometry is called syn periplanar. While the H and X atoms oriented on opposite sides of the molecule. This geometry is called anti periplanar. The dihedral angle for the C-H and C-X bonds equals 0° for the syn periplanar arrangement and 180° for the anti periplanar arrangement.

Whereas the E1 reaction is a twostep reaction of first order kinetics. The two steps reaction is the bond to the leaving group breaks first before the π bond is formed.

Expert Solution

Answer to Problem 8.57P

The cis -1-bromo-4-tert-butylcyclohexane reacts faster when compared to trans-1-bromo-4-tert-butylcyclohexane.

cis -1-bromo-4-tert-butylcyclohexane with NaOCH₃.

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 11

trans-1-bromo-4-tert-butylcyclohexane with NaOCH₃

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 12

Explanation of Solution

NaOCH_3, is a strong nucleophile. The reaction follows the SN2 in which the backside attack occurs. With the cis isomer the nucleophile can attack by the equatorial position to avoid the 1, 3-diaxial interaction. Moreover only the cis isomer has the Br and Β carbon in the anti periplanar that is in trans diaxial arrangement when compared to trans isomer. Thus the cis isomer reacts faster than trans isomer.

cis -1-bromo-4-tert-butylcyclohexane with NaOCH₃

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 13

trans-1-bromo-4-tert-butylcyclohexane with NaOCH₃

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 14

Conclusion

Thus the cis -1-bromo-4-tert-butylcyclohexane reacts faster when compared to trans-1-bromo-4-tert-butylcyclohexane

Interpretation Introduction

(e)

Interpretation:

To explain why there is different products formed when the alkyl halides uses two different alkoxides.

Concept introduction:

The most common mechanism for dehydrohalogenation is the E2 mechanism. An E2 reaction exhibits a second-order kinetics, in which the reaction is bimolecular and both the alkyl halide and the base appear in the rate equation. The most straightforward explanation for the second-order kinetics is a concerted reaction: all bonds are broken and formed in a single step. In other words simultaneously all bonds are broken and formed.

The transition state of an E2 reaction consists of four atoms from the alkyl halide-one hydrogen atom, two carbon atoms, and the leaving group (X)-all aligned in the same plane. There are two ways for the C-H and C-x bonds to be coplanar. When the H and X atoms oriented on the same side of the molecule. This geometry is called syn periplanar. While the H and X atoms oriented on opposite sides of the molecule. This geometry is called anti periplanar. The dihedral angle for the C-H and C-X bonds equals 0° for the syn periplanar arrangement and 180° for the anti periplanar arrangement.

Whereas the E1 reaction is a twostep reaction of first order kinetics. The two steps reaction is the bond to the leaving group breaks first before the π bond is formed.

Expert Solution

Answer to Problem 8.57P

The bulky base ^–OC(CH₃)₃ favours the elimination by an E2 reaction mechanism, to get a mixture of enantiomers A and B. The strong nucleophile ^–OCH₃ favours nucleophile substitution by an SN2 mechanism. Inversion of configuration results from backside attack of the nucleophile. Thus different product are formed.

Explanation of Solution

^-OCH_3, is a strong nucleophile. The reaction follows the SN2 in which the backside attack occurs. With the cis isomer the nucleophile can attack by the equatorial position to avoid the 1, 3-diaxial interaction. Moreover only the cis isomer has the Br and Β carbon in the anti periplanar that is in trans diaxial arrangement when compared to trans isomer. Thus the cis isomer reacts faster than trans isomer. The bulky base ^–OC(CH₃)₃ favours the elimination by an E2 reaction mechanism, to get a mixture of enantiomers A and B.

Conclusion

Thus different product are formed when the alkyl halides uses two different alkoxides are used.

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Answer 3

Question

Chapter 8, Problem 8.57P

Interpretation Introduction

(a)

Interpretation:

To draw the mixture of enantiomers A and B obtained from cis and Trans isomers of 1-bromo-4-tert-butylcyclohexane with KOC (CH₃)₃.

Concept introduction:

The most common mechanism for dehydrohalogenation is the E2 mechanism. An E2 reaction exhibits a second-order kinetics, in which the reaction is bimolecular and both the alkyl halide and the base appear in the rate equation. The most straightforward explanation for the second-order kinetics is a concerted reaction: all bonds are broken and formed in a single step. In other words simultaneously all bonds are broken and formed.

The transition state of an E2 reaction consists of four atoms from the alkyl halide-one hydrogen atom, two carbon atoms, and the leaving group (X)-all aligned in the same plane. There are two ways for the C-H and C-x bonds to be coplanar. When the H and X atoms oriented on the same side of the molecule. This geometry is called syn periplanar. While the H and X atoms oriented on opposite sides of the molecule. This geometry is called anti periplanar. The dihedral angle for the C-H and C-X bonds equals 0° for the syn periplanar arrangement and 180° for the anti periplanar arrangement.

Whereas the E1 reaction is a twostep reaction of first order kinetics. The two steps reaction is the bond to the leaving group breaks first before the π bond is formed.

Expert Solution

Answer to Problem 8.57P

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 1

Explanation of Solution

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 2

The elimination of the Br from the reactant using base to form the respective alkene.

Conclusion

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 3

Interpretation Introduction

(b)

Interpretation:

To determine the isomer that reacts faster with KOC(CH₃)₃.

Concept introduction:

The most common mechanism for dehydrohalogenation is the E2 mechanism. An E2 reaction exhibits a second-order kinetics, in which the reaction is bimolecular and both the alkyl halide and the base appear in the rate equation. The most straightforward explanation for the second-order kinetics is a concerted reaction: all bonds are broken and formed in a single step. In other words simultaneously all bonds are broken and formed.

The transition state of an E2 reaction consists of four atoms from the alkyl halide-one hydrogen atom, two carbon atoms, and the leaving group (X)-all aligned in the same plane. There are two ways for the C-H and C-x bonds to be coplanar. When the H and X atoms oriented on the same side of the molecule. This geometry is called syn periplanar. While the H and X atoms oriented on opposite sides of the molecule. This geometry is called anti periplanar. The dihedral angle for the C-H and C-X bonds equals 0° for the syn periplanar arrangement and 180° for the anti periplanar arrangement.

Whereas the E1 reaction is a twostep reaction of first order kinetics. The two steps reaction is the bond to the leaving group breaks first before the π bond is formed.

Expert Solution

Answer to Problem 8.57P

The bulky tert-butyl group in the cyclohexane ring is in the equatorial position.

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 4

In the cis-isomer, the Br is in the axial position. So cis-isomer is faster than the trans-isomer.

Explanation of Solution

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 5

The bulky tert-butyl group in the cyclohexane ring is in the equatorial position. The cis isomer has the Br in the axial position while in the trans isomer the Br is in the equatorial position. For the dehydrogenation to occur, the halogen must be in the axial position to afford trans diaxial elimination of H and X. Thus the cis isomer react faster than trans where the Br lies in the equatorial position.

Conclusion

Thus cis-isomer is faster than the trans-isomer due to axial position of Br in the structure.

Interpretation Introduction

(c)

Interpretation:

To draw the structures for C and D from cis and trans-1-bromo-4-tert-butylcyclohexane with NaOCH_3.

Concept introduction:

The most common mechanism for dehydrohalogenation is the E2 mechanism. An E2 reaction exhibits a second-order kinetics, in which the reaction is bimolecular and both the alkyl halide and the base appear in the rate equation. The most straightforward explanation for the second-order kinetics is a concerted reaction: all bonds are broken and formed in a single step. In other words simultaneously all bonds are broken and formed.

The transition state of an E2 reaction consists of four atoms from the alkyl halide-one hydrogen atom, two carbon atoms, and the leaving group (X)-all aligned in the same plane. There are two ways for the C-H and C-x bonds to be coplanar. When the H and X atoms oriented on the same side of the molecule. This geometry is called syn periplanar. While the H and X atoms oriented on opposite sides of the molecule. This geometry is called anti periplanar. The dihedral angle for the C-H and C-X bonds equals 0° for the syn periplanar arrangement and 180° for the anti periplanar arrangement.

Whereas the E1 reaction is a twostep reaction of first order kinetics. The two steps reaction is the bond to the leaving group breaks first before the π bond is formed.

Expert Solution

Answer to Problem 8.57P

cis -1-bromo-4-tert-butylcyclohexane with NaOCH₃ forms the product

trans-1-bromo-4-tert-butylcyclohexane with NaOCH₃ forms the product

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 7

Explanation of Solution

The major products C and D formed when cis and trans-1-bromo-4-tert-butylcyclohexane reacts with NaOCH₃ is shown. The respective reaction takes place by SN2 reaction mechanism that is by backside attack of the nucleophile.

.

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 8

Conclusion

cis -1-bromo-4-tert-butylcyclohexane with NaOCH₃ forms the product.

trans-1-bromo-4-tert-butylcyclohexane with NaOCH₃ forms the product.

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 10

Interpretation Introduction

(d)

Interpretation:

To determine the isomer that reacts faster with NaOCH₃.

Concept introduction:

The most common mechanism for dehydrohalogenation is the E2 mechanism. An E2 reaction exhibits a second-order kinetics, in which the reaction is bimolecular and both the alkyl halide and the base appear in the rate equation. The most straightforward explanation for the second-order kinetics is a concerted reaction: all bonds are broken and formed in a single step. In other words simultaneously all bonds are broken and formed.

The transition state of an E2 reaction consists of four atoms from the alkyl halide-one hydrogen atom, two carbon atoms, and the leaving group (X)-all aligned in the same plane. There are two ways for the C-H and C-x bonds to be coplanar. When the H and X atoms oriented on the same side of the molecule. This geometry is called syn periplanar. While the H and X atoms oriented on opposite sides of the molecule. This geometry is called anti periplanar. The dihedral angle for the C-H and C-X bonds equals 0° for the syn periplanar arrangement and 180° for the anti periplanar arrangement.

Whereas the E1 reaction is a twostep reaction of first order kinetics. The two steps reaction is the bond to the leaving group breaks first before the π bond is formed.

Expert Solution

Answer to Problem 8.57P

The cis -1-bromo-4-tert-butylcyclohexane reacts faster when compared to trans-1-bromo-4-tert-butylcyclohexane.

cis -1-bromo-4-tert-butylcyclohexane with NaOCH₃.

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 11

trans-1-bromo-4-tert-butylcyclohexane with NaOCH₃

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 12

Explanation of Solution

NaOCH_3, is a strong nucleophile. The reaction follows the SN2 in which the backside attack occurs. With the cis isomer the nucleophile can attack by the equatorial position to avoid the 1, 3-diaxial interaction. Moreover only the cis isomer has the Br and Β carbon in the anti periplanar that is in trans diaxial arrangement when compared to trans isomer. Thus the cis isomer reacts faster than trans isomer.

cis -1-bromo-4-tert-butylcyclohexane with NaOCH₃

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 13

trans-1-bromo-4-tert-butylcyclohexane with NaOCH₃

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 14

Conclusion

Thus the cis -1-bromo-4-tert-butylcyclohexane reacts faster when compared to trans-1-bromo-4-tert-butylcyclohexane

Interpretation Introduction

(e)

Interpretation:

To explain why there is different products formed when the alkyl halides uses two different alkoxides.

Concept introduction:

The most common mechanism for dehydrohalogenation is the E2 mechanism. An E2 reaction exhibits a second-order kinetics, in which the reaction is bimolecular and both the alkyl halide and the base appear in the rate equation. The most straightforward explanation for the second-order kinetics is a concerted reaction: all bonds are broken and formed in a single step. In other words simultaneously all bonds are broken and formed.

The transition state of an E2 reaction consists of four atoms from the alkyl halide-one hydrogen atom, two carbon atoms, and the leaving group (X)-all aligned in the same plane. There are two ways for the C-H and C-x bonds to be coplanar. When the H and X atoms oriented on the same side of the molecule. This geometry is called syn periplanar. While the H and X atoms oriented on opposite sides of the molecule. This geometry is called anti periplanar. The dihedral angle for the C-H and C-X bonds equals 0° for the syn periplanar arrangement and 180° for the anti periplanar arrangement.

Whereas the E1 reaction is a twostep reaction of first order kinetics. The two steps reaction is the bond to the leaving group breaks first before the π bond is formed.

Expert Solution

Answer to Problem 8.57P

The bulky base ^–OC(CH₃)₃ favours the elimination by an E2 reaction mechanism, to get a mixture of enantiomers A and B. The strong nucleophile ^–OCH₃ favours nucleophile substitution by an SN2 mechanism. Inversion of configuration results from backside attack of the nucleophile. Thus different product are formed.

Explanation of Solution

^-OCH_3, is a strong nucleophile. The reaction follows the SN2 in which the backside attack occurs. With the cis isomer the nucleophile can attack by the equatorial position to avoid the 1, 3-diaxial interaction. Moreover only the cis isomer has the Br and Β carbon in the anti periplanar that is in trans diaxial arrangement when compared to trans isomer. Thus the cis isomer reacts faster than trans isomer. The bulky base ^–OC(CH₃)₃ favours the elimination by an E2 reaction mechanism, to get a mixture of enantiomers A and B.

Conclusion

Thus different product are formed when the alkyl halides uses two different alkoxides are used.

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Answer 4

Question

Chapter 8, Problem 8.57P

Interpretation Introduction

(a)

Interpretation:

To draw the mixture of enantiomers A and B obtained from cis and Trans isomers of 1-bromo-4-tert-butylcyclohexane with KOC (CH₃)₃.

Concept introduction:

The most common mechanism for dehydrohalogenation is the E2 mechanism. An E2 reaction exhibits a second-order kinetics, in which the reaction is bimolecular and both the alkyl halide and the base appear in the rate equation. The most straightforward explanation for the second-order kinetics is a concerted reaction: all bonds are broken and formed in a single step. In other words simultaneously all bonds are broken and formed.

The transition state of an E2 reaction consists of four atoms from the alkyl halide-one hydrogen atom, two carbon atoms, and the leaving group (X)-all aligned in the same plane. There are two ways for the C-H and C-x bonds to be coplanar. When the H and X atoms oriented on the same side of the molecule. This geometry is called syn periplanar. While the H and X atoms oriented on opposite sides of the molecule. This geometry is called anti periplanar. The dihedral angle for the C-H and C-X bonds equals 0° for the syn periplanar arrangement and 180° for the anti periplanar arrangement.

Whereas the E1 reaction is a twostep reaction of first order kinetics. The two steps reaction is the bond to the leaving group breaks first before the π bond is formed.

Expert Solution

Answer to Problem 8.57P

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 1

Explanation of Solution

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 2

The elimination of the Br from the reactant using base to form the respective alkene.

Conclusion

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 3

Interpretation Introduction

(b)

Interpretation:

To determine the isomer that reacts faster with KOC(CH₃)₃.

Concept introduction:

The most common mechanism for dehydrohalogenation is the E2 mechanism. An E2 reaction exhibits a second-order kinetics, in which the reaction is bimolecular and both the alkyl halide and the base appear in the rate equation. The most straightforward explanation for the second-order kinetics is a concerted reaction: all bonds are broken and formed in a single step. In other words simultaneously all bonds are broken and formed.

The transition state of an E2 reaction consists of four atoms from the alkyl halide-one hydrogen atom, two carbon atoms, and the leaving group (X)-all aligned in the same plane. There are two ways for the C-H and C-x bonds to be coplanar. When the H and X atoms oriented on the same side of the molecule. This geometry is called syn periplanar. While the H and X atoms oriented on opposite sides of the molecule. This geometry is called anti periplanar. The dihedral angle for the C-H and C-X bonds equals 0° for the syn periplanar arrangement and 180° for the anti periplanar arrangement.

Whereas the E1 reaction is a twostep reaction of first order kinetics. The two steps reaction is the bond to the leaving group breaks first before the π bond is formed.

Expert Solution

Answer to Problem 8.57P

The bulky tert-butyl group in the cyclohexane ring is in the equatorial position.

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 4

In the cis-isomer, the Br is in the axial position. So cis-isomer is faster than the trans-isomer.

Explanation of Solution

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 5

The bulky tert-butyl group in the cyclohexane ring is in the equatorial position. The cis isomer has the Br in the axial position while in the trans isomer the Br is in the equatorial position. For the dehydrogenation to occur, the halogen must be in the axial position to afford trans diaxial elimination of H and X. Thus the cis isomer react faster than trans where the Br lies in the equatorial position.

Conclusion

Thus cis-isomer is faster than the trans-isomer due to axial position of Br in the structure.

Interpretation Introduction

(c)

Interpretation:

To draw the structures for C and D from cis and trans-1-bromo-4-tert-butylcyclohexane with NaOCH_3.

Concept introduction:

The most common mechanism for dehydrohalogenation is the E2 mechanism. An E2 reaction exhibits a second-order kinetics, in which the reaction is bimolecular and both the alkyl halide and the base appear in the rate equation. The most straightforward explanation for the second-order kinetics is a concerted reaction: all bonds are broken and formed in a single step. In other words simultaneously all bonds are broken and formed.

The transition state of an E2 reaction consists of four atoms from the alkyl halide-one hydrogen atom, two carbon atoms, and the leaving group (X)-all aligned in the same plane. There are two ways for the C-H and C-x bonds to be coplanar. When the H and X atoms oriented on the same side of the molecule. This geometry is called syn periplanar. While the H and X atoms oriented on opposite sides of the molecule. This geometry is called anti periplanar. The dihedral angle for the C-H and C-X bonds equals 0° for the syn periplanar arrangement and 180° for the anti periplanar arrangement.

Whereas the E1 reaction is a twostep reaction of first order kinetics. The two steps reaction is the bond to the leaving group breaks first before the π bond is formed.

Expert Solution

Answer to Problem 8.57P

cis -1-bromo-4-tert-butylcyclohexane with NaOCH₃ forms the product

trans-1-bromo-4-tert-butylcyclohexane with NaOCH₃ forms the product

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 7

Explanation of Solution

The major products C and D formed when cis and trans-1-bromo-4-tert-butylcyclohexane reacts with NaOCH₃ is shown. The respective reaction takes place by SN2 reaction mechanism that is by backside attack of the nucleophile.

.

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 8

Conclusion

cis -1-bromo-4-tert-butylcyclohexane with NaOCH₃ forms the product.

trans-1-bromo-4-tert-butylcyclohexane with NaOCH₃ forms the product.

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 10

Interpretation Introduction

(d)

Interpretation:

To determine the isomer that reacts faster with NaOCH₃.

Concept introduction:

The most common mechanism for dehydrohalogenation is the E2 mechanism. An E2 reaction exhibits a second-order kinetics, in which the reaction is bimolecular and both the alkyl halide and the base appear in the rate equation. The most straightforward explanation for the second-order kinetics is a concerted reaction: all bonds are broken and formed in a single step. In other words simultaneously all bonds are broken and formed.

The transition state of an E2 reaction consists of four atoms from the alkyl halide-one hydrogen atom, two carbon atoms, and the leaving group (X)-all aligned in the same plane. There are two ways for the C-H and C-x bonds to be coplanar. When the H and X atoms oriented on the same side of the molecule. This geometry is called syn periplanar. While the H and X atoms oriented on opposite sides of the molecule. This geometry is called anti periplanar. The dihedral angle for the C-H and C-X bonds equals 0° for the syn periplanar arrangement and 180° for the anti periplanar arrangement.

Whereas the E1 reaction is a twostep reaction of first order kinetics. The two steps reaction is the bond to the leaving group breaks first before the π bond is formed.

Expert Solution

Answer to Problem 8.57P

The cis -1-bromo-4-tert-butylcyclohexane reacts faster when compared to trans-1-bromo-4-tert-butylcyclohexane.

cis -1-bromo-4-tert-butylcyclohexane with NaOCH₃.

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 11

trans-1-bromo-4-tert-butylcyclohexane with NaOCH₃

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 12

Explanation of Solution

NaOCH_3, is a strong nucleophile. The reaction follows the SN2 in which the backside attack occurs. With the cis isomer the nucleophile can attack by the equatorial position to avoid the 1, 3-diaxial interaction. Moreover only the cis isomer has the Br and Β carbon in the anti periplanar that is in trans diaxial arrangement when compared to trans isomer. Thus the cis isomer reacts faster than trans isomer.

cis -1-bromo-4-tert-butylcyclohexane with NaOCH₃

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 13

trans-1-bromo-4-tert-butylcyclohexane with NaOCH₃

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 14

Conclusion

Thus the cis -1-bromo-4-tert-butylcyclohexane reacts faster when compared to trans-1-bromo-4-tert-butylcyclohexane

Interpretation Introduction

(e)

Interpretation:

To explain why there is different products formed when the alkyl halides uses two different alkoxides.

Concept introduction:

The most common mechanism for dehydrohalogenation is the E2 mechanism. An E2 reaction exhibits a second-order kinetics, in which the reaction is bimolecular and both the alkyl halide and the base appear in the rate equation. The most straightforward explanation for the second-order kinetics is a concerted reaction: all bonds are broken and formed in a single step. In other words simultaneously all bonds are broken and formed.

The transition state of an E2 reaction consists of four atoms from the alkyl halide-one hydrogen atom, two carbon atoms, and the leaving group (X)-all aligned in the same plane. There are two ways for the C-H and C-x bonds to be coplanar. When the H and X atoms oriented on the same side of the molecule. This geometry is called syn periplanar. While the H and X atoms oriented on opposite sides of the molecule. This geometry is called anti periplanar. The dihedral angle for the C-H and C-X bonds equals 0° for the syn periplanar arrangement and 180° for the anti periplanar arrangement.

Whereas the E1 reaction is a twostep reaction of first order kinetics. The two steps reaction is the bond to the leaving group breaks first before the π bond is formed.

Expert Solution

Answer to Problem 8.57P

The bulky base ^–OC(CH₃)₃ favours the elimination by an E2 reaction mechanism, to get a mixture of enantiomers A and B. The strong nucleophile ^–OCH₃ favours nucleophile substitution by an SN2 mechanism. Inversion of configuration results from backside attack of the nucleophile. Thus different product are formed.

Explanation of Solution

^-OCH_3, is a strong nucleophile. The reaction follows the SN2 in which the backside attack occurs. With the cis isomer the nucleophile can attack by the equatorial position to avoid the 1, 3-diaxial interaction. Moreover only the cis isomer has the Br and Β carbon in the anti periplanar that is in trans diaxial arrangement when compared to trans isomer. Thus the cis isomer reacts faster than trans isomer. The bulky base ^–OC(CH₃)₃ favours the elimination by an E2 reaction mechanism, to get a mixture of enantiomers A and B.

Conclusion

Thus different product are formed when the alkyl halides uses two different alkoxides are used.

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Answer 5

Chapter 8, Problem 8.57P

Interpretation Introduction

(a)

Interpretation:

To draw the mixture of enantiomers A and B obtained from cis and Trans isomers of 1-bromo-4-tert-butylcyclohexane with KOC (CH₃)₃.

Concept introduction:

The most common mechanism for dehydrohalogenation is the E2 mechanism. An E2 reaction exhibits a second-order kinetics, in which the reaction is bimolecular and both the alkyl halide and the base appear in the rate equation. The most straightforward explanation for the second-order kinetics is a concerted reaction: all bonds are broken and formed in a single step. In other words simultaneously all bonds are broken and formed.

The transition state of an E2 reaction consists of four atoms from the alkyl halide-one hydrogen atom, two carbon atoms, and the leaving group (X)-all aligned in the same plane. There are two ways for the C-H and C-x bonds to be coplanar. When the H and X atoms oriented on the same side of the molecule. This geometry is called syn periplanar. While the H and X atoms oriented on opposite sides of the molecule. This geometry is called anti periplanar. The dihedral angle for the C-H and C-X bonds equals 0° for the syn periplanar arrangement and 180° for the anti periplanar arrangement.

Whereas the E1 reaction is a twostep reaction of first order kinetics. The two steps reaction is the bond to the leaving group breaks first before the π bond is formed.

Expert Solution

Answer to Problem 8.57P

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 1

Explanation of Solution

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 2

The elimination of the Br from the reactant using base to form the respective alkene.

Conclusion

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 3

Interpretation Introduction

(b)

Interpretation:

To determine the isomer that reacts faster with KOC(CH₃)₃.

Concept introduction:

The most common mechanism for dehydrohalogenation is the E2 mechanism. An E2 reaction exhibits a second-order kinetics, in which the reaction is bimolecular and both the alkyl halide and the base appear in the rate equation. The most straightforward explanation for the second-order kinetics is a concerted reaction: all bonds are broken and formed in a single step. In other words simultaneously all bonds are broken and formed.

The transition state of an E2 reaction consists of four atoms from the alkyl halide-one hydrogen atom, two carbon atoms, and the leaving group (X)-all aligned in the same plane. There are two ways for the C-H and C-x bonds to be coplanar. When the H and X atoms oriented on the same side of the molecule. This geometry is called syn periplanar. While the H and X atoms oriented on opposite sides of the molecule. This geometry is called anti periplanar. The dihedral angle for the C-H and C-X bonds equals 0° for the syn periplanar arrangement and 180° for the anti periplanar arrangement.

Whereas the E1 reaction is a twostep reaction of first order kinetics. The two steps reaction is the bond to the leaving group breaks first before the π bond is formed.

Expert Solution

Answer to Problem 8.57P

The bulky tert-butyl group in the cyclohexane ring is in the equatorial position.

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 4

In the cis-isomer, the Br is in the axial position. So cis-isomer is faster than the trans-isomer.

Explanation of Solution

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 5

The bulky tert-butyl group in the cyclohexane ring is in the equatorial position. The cis isomer has the Br in the axial position while in the trans isomer the Br is in the equatorial position. For the dehydrogenation to occur, the halogen must be in the axial position to afford trans diaxial elimination of H and X. Thus the cis isomer react faster than trans where the Br lies in the equatorial position.

Conclusion

Thus cis-isomer is faster than the trans-isomer due to axial position of Br in the structure.

Interpretation Introduction

(c)

Interpretation:

To draw the structures for C and D from cis and trans-1-bromo-4-tert-butylcyclohexane with NaOCH_3.

Concept introduction:

The most common mechanism for dehydrohalogenation is the E2 mechanism. An E2 reaction exhibits a second-order kinetics, in which the reaction is bimolecular and both the alkyl halide and the base appear in the rate equation. The most straightforward explanation for the second-order kinetics is a concerted reaction: all bonds are broken and formed in a single step. In other words simultaneously all bonds are broken and formed.

The transition state of an E2 reaction consists of four atoms from the alkyl halide-one hydrogen atom, two carbon atoms, and the leaving group (X)-all aligned in the same plane. There are two ways for the C-H and C-x bonds to be coplanar. When the H and X atoms oriented on the same side of the molecule. This geometry is called syn periplanar. While the H and X atoms oriented on opposite sides of the molecule. This geometry is called anti periplanar. The dihedral angle for the C-H and C-X bonds equals 0° for the syn periplanar arrangement and 180° for the anti periplanar arrangement.

Whereas the E1 reaction is a twostep reaction of first order kinetics. The two steps reaction is the bond to the leaving group breaks first before the π bond is formed.

Expert Solution

Answer to Problem 8.57P

cis -1-bromo-4-tert-butylcyclohexane with NaOCH₃ forms the product

trans-1-bromo-4-tert-butylcyclohexane with NaOCH₃ forms the product

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 7

Explanation of Solution

The major products C and D formed when cis and trans-1-bromo-4-tert-butylcyclohexane reacts with NaOCH₃ is shown. The respective reaction takes place by SN2 reaction mechanism that is by backside attack of the nucleophile.

.

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 8

Conclusion

cis -1-bromo-4-tert-butylcyclohexane with NaOCH₃ forms the product.

trans-1-bromo-4-tert-butylcyclohexane with NaOCH₃ forms the product.

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 10

Interpretation Introduction

(d)

Interpretation:

To determine the isomer that reacts faster with NaOCH₃.

Concept introduction:

The most common mechanism for dehydrohalogenation is the E2 mechanism. An E2 reaction exhibits a second-order kinetics, in which the reaction is bimolecular and both the alkyl halide and the base appear in the rate equation. The most straightforward explanation for the second-order kinetics is a concerted reaction: all bonds are broken and formed in a single step. In other words simultaneously all bonds are broken and formed.

The transition state of an E2 reaction consists of four atoms from the alkyl halide-one hydrogen atom, two carbon atoms, and the leaving group (X)-all aligned in the same plane. There are two ways for the C-H and C-x bonds to be coplanar. When the H and X atoms oriented on the same side of the molecule. This geometry is called syn periplanar. While the H and X atoms oriented on opposite sides of the molecule. This geometry is called anti periplanar. The dihedral angle for the C-H and C-X bonds equals 0° for the syn periplanar arrangement and 180° for the anti periplanar arrangement.

Whereas the E1 reaction is a twostep reaction of first order kinetics. The two steps reaction is the bond to the leaving group breaks first before the π bond is formed.

Expert Solution

Answer to Problem 8.57P

The cis -1-bromo-4-tert-butylcyclohexane reacts faster when compared to trans-1-bromo-4-tert-butylcyclohexane.

cis -1-bromo-4-tert-butylcyclohexane with NaOCH₃.

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 11

trans-1-bromo-4-tert-butylcyclohexane with NaOCH₃

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 12

Explanation of Solution

NaOCH_3, is a strong nucleophile. The reaction follows the SN2 in which the backside attack occurs. With the cis isomer the nucleophile can attack by the equatorial position to avoid the 1, 3-diaxial interaction. Moreover only the cis isomer has the Br and Β carbon in the anti periplanar that is in trans diaxial arrangement when compared to trans isomer. Thus the cis isomer reacts faster than trans isomer.

cis -1-bromo-4-tert-butylcyclohexane with NaOCH₃

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 13

trans-1-bromo-4-tert-butylcyclohexane with NaOCH₃

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 14

Conclusion

Thus the cis -1-bromo-4-tert-butylcyclohexane reacts faster when compared to trans-1-bromo-4-tert-butylcyclohexane

Interpretation Introduction

(e)

Interpretation:

To explain why there is different products formed when the alkyl halides uses two different alkoxides.

Concept introduction:

The most common mechanism for dehydrohalogenation is the E2 mechanism. An E2 reaction exhibits a second-order kinetics, in which the reaction is bimolecular and both the alkyl halide and the base appear in the rate equation. The most straightforward explanation for the second-order kinetics is a concerted reaction: all bonds are broken and formed in a single step. In other words simultaneously all bonds are broken and formed.

The transition state of an E2 reaction consists of four atoms from the alkyl halide-one hydrogen atom, two carbon atoms, and the leaving group (X)-all aligned in the same plane. There are two ways for the C-H and C-x bonds to be coplanar. When the H and X atoms oriented on the same side of the molecule. This geometry is called syn periplanar. While the H and X atoms oriented on opposite sides of the molecule. This geometry is called anti periplanar. The dihedral angle for the C-H and C-X bonds equals 0° for the syn periplanar arrangement and 180° for the anti periplanar arrangement.

Whereas the E1 reaction is a twostep reaction of first order kinetics. The two steps reaction is the bond to the leaving group breaks first before the π bond is formed.

Expert Solution

Answer to Problem 8.57P

The bulky base ^–OC(CH₃)₃ favours the elimination by an E2 reaction mechanism, to get a mixture of enantiomers A and B. The strong nucleophile ^–OCH₃ favours nucleophile substitution by an SN2 mechanism. Inversion of configuration results from backside attack of the nucleophile. Thus different product are formed.

Explanation of Solution

^-OCH_3, is a strong nucleophile. The reaction follows the SN2 in which the backside attack occurs. With the cis isomer the nucleophile can attack by the equatorial position to avoid the 1, 3-diaxial interaction. Moreover only the cis isomer has the Br and Β carbon in the anti periplanar that is in trans diaxial arrangement when compared to trans isomer. Thus the cis isomer reacts faster than trans isomer. The bulky base ^–OC(CH₃)₃ favours the elimination by an E2 reaction mechanism, to get a mixture of enantiomers A and B.

Conclusion

Thus different product are formed when the alkyl halides uses two different alkoxides are used.

Answer 6

Chapter 8, Problem 8.57P

Interpretation Introduction

(a)

Interpretation:

To draw the mixture of enantiomers A and B obtained from cis and Trans isomers of 1-bromo-4-tert-butylcyclohexane with KOC (CH₃)₃.

Concept introduction:

The most common mechanism for dehydrohalogenation is the E2 mechanism. An E2 reaction exhibits a second-order kinetics, in which the reaction is bimolecular and both the alkyl halide and the base appear in the rate equation. The most straightforward explanation for the second-order kinetics is a concerted reaction: all bonds are broken and formed in a single step. In other words simultaneously all bonds are broken and formed.

The transition state of an E2 reaction consists of four atoms from the alkyl halide-one hydrogen atom, two carbon atoms, and the leaving group (X)-all aligned in the same plane. There are two ways for the C-H and C-x bonds to be coplanar. When the H and X atoms oriented on the same side of the molecule. This geometry is called syn periplanar. While the H and X atoms oriented on opposite sides of the molecule. This geometry is called anti periplanar. The dihedral angle for the C-H and C-X bonds equals 0° for the syn periplanar arrangement and 180° for the anti periplanar arrangement.

Whereas the E1 reaction is a twostep reaction of first order kinetics. The two steps reaction is the bond to the leaving group breaks first before the π bond is formed.

Expert Solution

Answer to Problem 8.57P

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 1

Explanation of Solution

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 2

The elimination of the Br from the reactant using base to form the respective alkene.

Conclusion

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 3

Answer 7

Chapter 8, Problem 8.57P

Interpretation Introduction

(a)

Interpretation:

To draw the mixture of enantiomers A and B obtained from cis and Trans isomers of 1-bromo-4-tert-butylcyclohexane with KOC (CH₃)₃.

Concept introduction:

The most common mechanism for dehydrohalogenation is the E2 mechanism. An E2 reaction exhibits a second-order kinetics, in which the reaction is bimolecular and both the alkyl halide and the base appear in the rate equation. The most straightforward explanation for the second-order kinetics is a concerted reaction: all bonds are broken and formed in a single step. In other words simultaneously all bonds are broken and formed.

The transition state of an E2 reaction consists of four atoms from the alkyl halide-one hydrogen atom, two carbon atoms, and the leaving group (X)-all aligned in the same plane. There are two ways for the C-H and C-x bonds to be coplanar. When the H and X atoms oriented on the same side of the molecule. This geometry is called syn periplanar. While the H and X atoms oriented on opposite sides of the molecule. This geometry is called anti periplanar. The dihedral angle for the C-H and C-X bonds equals 0° for the syn periplanar arrangement and 180° for the anti periplanar arrangement.

Whereas the E1 reaction is a twostep reaction of first order kinetics. The two steps reaction is the bond to the leaving group breaks first before the π bond is formed.

Answer 8

Expert Solution

Answer to Problem 8.57P

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 1

Answer 9

Expert Solution

Answer 10

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 2

The elimination of the Br from the reactant using base to form the respective alkene.

Answer 13

Conclusion

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 3

Answer 14

Interpretation Introduction

(b)

Interpretation:

To determine the isomer that reacts faster with KOC(CH₃)₃.

Concept introduction:

The most common mechanism for dehydrohalogenation is the E2 mechanism. An E2 reaction exhibits a second-order kinetics, in which the reaction is bimolecular and both the alkyl halide and the base appear in the rate equation. The most straightforward explanation for the second-order kinetics is a concerted reaction: all bonds are broken and formed in a single step. In other words simultaneously all bonds are broken and formed.

The transition state of an E2 reaction consists of four atoms from the alkyl halide-one hydrogen atom, two carbon atoms, and the leaving group (X)-all aligned in the same plane. There are two ways for the C-H and C-x bonds to be coplanar. When the H and X atoms oriented on the same side of the molecule. This geometry is called syn periplanar. While the H and X atoms oriented on opposite sides of the molecule. This geometry is called anti periplanar. The dihedral angle for the C-H and C-X bonds equals 0° for the syn periplanar arrangement and 180° for the anti periplanar arrangement.

Whereas the E1 reaction is a twostep reaction of first order kinetics. The two steps reaction is the bond to the leaving group breaks first before the π bond is formed.

Expert Solution

Answer to Problem 8.57P

The bulky tert-butyl group in the cyclohexane ring is in the equatorial position.

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 4

In the cis-isomer, the Br is in the axial position. So cis-isomer is faster than the trans-isomer.

Explanation of Solution

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 5

The bulky tert-butyl group in the cyclohexane ring is in the equatorial position. The cis isomer has the Br in the axial position while in the trans isomer the Br is in the equatorial position. For the dehydrogenation to occur, the halogen must be in the axial position to afford trans diaxial elimination of H and X. Thus the cis isomer react faster than trans where the Br lies in the equatorial position.

Conclusion

Thus cis-isomer is faster than the trans-isomer due to axial position of Br in the structure.

Answer 15

Interpretation Introduction

(b)

Interpretation:

To determine the isomer that reacts faster with KOC(CH₃)₃.

Concept introduction:

The most common mechanism for dehydrohalogenation is the E2 mechanism. An E2 reaction exhibits a second-order kinetics, in which the reaction is bimolecular and both the alkyl halide and the base appear in the rate equation. The most straightforward explanation for the second-order kinetics is a concerted reaction: all bonds are broken and formed in a single step. In other words simultaneously all bonds are broken and formed.

The transition state of an E2 reaction consists of four atoms from the alkyl halide-one hydrogen atom, two carbon atoms, and the leaving group (X)-all aligned in the same plane. There are two ways for the C-H and C-x bonds to be coplanar. When the H and X atoms oriented on the same side of the molecule. This geometry is called syn periplanar. While the H and X atoms oriented on opposite sides of the molecule. This geometry is called anti periplanar. The dihedral angle for the C-H and C-X bonds equals 0° for the syn periplanar arrangement and 180° for the anti periplanar arrangement.

Whereas the E1 reaction is a twostep reaction of first order kinetics. The two steps reaction is the bond to the leaving group breaks first before the π bond is formed.

Answer 16

Expert Solution

Answer to Problem 8.57P

The bulky tert-butyl group in the cyclohexane ring is in the equatorial position.

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 4

In the cis-isomer, the Br is in the axial position. So cis-isomer is faster than the trans-isomer.

Answer 17

Expert Solution

Answer 18

Expert Solution

Answer 19

Expert Solution

Answer 20

Explanation of Solution

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 5

The bulky tert-butyl group in the cyclohexane ring is in the equatorial position. The cis isomer has the Br in the axial position while in the trans isomer the Br is in the equatorial position. For the dehydrogenation to occur, the halogen must be in the axial position to afford trans diaxial elimination of H and X. Thus the cis isomer react faster than trans where the Br lies in the equatorial position.

Answer 21

Conclusion

Thus cis-isomer is faster than the trans-isomer due to axial position of Br in the structure.

Answer 22

Interpretation Introduction

(c)

Interpretation:

To draw the structures for C and D from cis and trans-1-bromo-4-tert-butylcyclohexane with NaOCH_3.

Concept introduction:

The most common mechanism for dehydrohalogenation is the E2 mechanism. An E2 reaction exhibits a second-order kinetics, in which the reaction is bimolecular and both the alkyl halide and the base appear in the rate equation. The most straightforward explanation for the second-order kinetics is a concerted reaction: all bonds are broken and formed in a single step. In other words simultaneously all bonds are broken and formed.

The transition state of an E2 reaction consists of four atoms from the alkyl halide-one hydrogen atom, two carbon atoms, and the leaving group (X)-all aligned in the same plane. There are two ways for the C-H and C-x bonds to be coplanar. When the H and X atoms oriented on the same side of the molecule. This geometry is called syn periplanar. While the H and X atoms oriented on opposite sides of the molecule. This geometry is called anti periplanar. The dihedral angle for the C-H and C-X bonds equals 0° for the syn periplanar arrangement and 180° for the anti periplanar arrangement.

Whereas the E1 reaction is a twostep reaction of first order kinetics. The two steps reaction is the bond to the leaving group breaks first before the π bond is formed.

Expert Solution

Answer to Problem 8.57P

cis -1-bromo-4-tert-butylcyclohexane with NaOCH₃ forms the product

trans-1-bromo-4-tert-butylcyclohexane with NaOCH₃ forms the product

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 7

Explanation of Solution

The major products C and D formed when cis and trans-1-bromo-4-tert-butylcyclohexane reacts with NaOCH₃ is shown. The respective reaction takes place by SN2 reaction mechanism that is by backside attack of the nucleophile.

.

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 8

Conclusion

cis -1-bromo-4-tert-butylcyclohexane with NaOCH₃ forms the product.

trans-1-bromo-4-tert-butylcyclohexane with NaOCH₃ forms the product.

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 10

Answer 23

Interpretation Introduction

(c)

Interpretation:

To draw the structures for C and D from cis and trans-1-bromo-4-tert-butylcyclohexane with NaOCH_3.

Concept introduction:

The most common mechanism for dehydrohalogenation is the E2 mechanism. An E2 reaction exhibits a second-order kinetics, in which the reaction is bimolecular and both the alkyl halide and the base appear in the rate equation. The most straightforward explanation for the second-order kinetics is a concerted reaction: all bonds are broken and formed in a single step. In other words simultaneously all bonds are broken and formed.

The transition state of an E2 reaction consists of four atoms from the alkyl halide-one hydrogen atom, two carbon atoms, and the leaving group (X)-all aligned in the same plane. There are two ways for the C-H and C-x bonds to be coplanar. When the H and X atoms oriented on the same side of the molecule. This geometry is called syn periplanar. While the H and X atoms oriented on opposite sides of the molecule. This geometry is called anti periplanar. The dihedral angle for the C-H and C-X bonds equals 0° for the syn periplanar arrangement and 180° for the anti periplanar arrangement.

Whereas the E1 reaction is a twostep reaction of first order kinetics. The two steps reaction is the bond to the leaving group breaks first before the π bond is formed.

Answer 24

Expert Solution

Answer to Problem 8.57P

cis -1-bromo-4-tert-butylcyclohexane with NaOCH₃ forms the product

trans-1-bromo-4-tert-butylcyclohexane with NaOCH₃ forms the product

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 7

Answer 25

Expert Solution

Answer 26

Expert Solution

Answer 27

Expert Solution

Answer 28

Explanation of Solution

The major products C and D formed when cis and trans-1-bromo-4-tert-butylcyclohexane reacts with NaOCH₃ is shown. The respective reaction takes place by SN2 reaction mechanism that is by backside attack of the nucleophile.

.

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 8

Answer 29

Conclusion

cis -1-bromo-4-tert-butylcyclohexane with NaOCH₃ forms the product.

trans-1-bromo-4-tert-butylcyclohexane with NaOCH₃ forms the product.

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 10

Answer 30

Interpretation Introduction

(d)

Interpretation:

To determine the isomer that reacts faster with NaOCH₃.

Concept introduction:

The most common mechanism for dehydrohalogenation is the E2 mechanism. An E2 reaction exhibits a second-order kinetics, in which the reaction is bimolecular and both the alkyl halide and the base appear in the rate equation. The most straightforward explanation for the second-order kinetics is a concerted reaction: all bonds are broken and formed in a single step. In other words simultaneously all bonds are broken and formed.

The transition state of an E2 reaction consists of four atoms from the alkyl halide-one hydrogen atom, two carbon atoms, and the leaving group (X)-all aligned in the same plane. There are two ways for the C-H and C-x bonds to be coplanar. When the H and X atoms oriented on the same side of the molecule. This geometry is called syn periplanar. While the H and X atoms oriented on opposite sides of the molecule. This geometry is called anti periplanar. The dihedral angle for the C-H and C-X bonds equals 0° for the syn periplanar arrangement and 180° for the anti periplanar arrangement.

Whereas the E1 reaction is a twostep reaction of first order kinetics. The two steps reaction is the bond to the leaving group breaks first before the π bond is formed.

Expert Solution

Answer to Problem 8.57P

The cis -1-bromo-4-tert-butylcyclohexane reacts faster when compared to trans-1-bromo-4-tert-butylcyclohexane.

cis -1-bromo-4-tert-butylcyclohexane with NaOCH₃.

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 11

trans-1-bromo-4-tert-butylcyclohexane with NaOCH₃

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 12

Explanation of Solution

NaOCH_3, is a strong nucleophile. The reaction follows the SN2 in which the backside attack occurs. With the cis isomer the nucleophile can attack by the equatorial position to avoid the 1, 3-diaxial interaction. Moreover only the cis isomer has the Br and Β carbon in the anti periplanar that is in trans diaxial arrangement when compared to trans isomer. Thus the cis isomer reacts faster than trans isomer.

cis -1-bromo-4-tert-butylcyclohexane with NaOCH₃

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 13

trans-1-bromo-4-tert-butylcyclohexane with NaOCH₃

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 14

Conclusion

Thus the cis -1-bromo-4-tert-butylcyclohexane reacts faster when compared to trans-1-bromo-4-tert-butylcyclohexane

Answer 31

Interpretation Introduction

(d)

Interpretation:

To determine the isomer that reacts faster with NaOCH₃.

Concept introduction:

The most common mechanism for dehydrohalogenation is the E2 mechanism. An E2 reaction exhibits a second-order kinetics, in which the reaction is bimolecular and both the alkyl halide and the base appear in the rate equation. The most straightforward explanation for the second-order kinetics is a concerted reaction: all bonds are broken and formed in a single step. In other words simultaneously all bonds are broken and formed.

The transition state of an E2 reaction consists of four atoms from the alkyl halide-one hydrogen atom, two carbon atoms, and the leaving group (X)-all aligned in the same plane. There are two ways for the C-H and C-x bonds to be coplanar. When the H and X atoms oriented on the same side of the molecule. This geometry is called syn periplanar. While the H and X atoms oriented on opposite sides of the molecule. This geometry is called anti periplanar. The dihedral angle for the C-H and C-X bonds equals 0° for the syn periplanar arrangement and 180° for the anti periplanar arrangement.

Whereas the E1 reaction is a twostep reaction of first order kinetics. The two steps reaction is the bond to the leaving group breaks first before the π bond is formed.

Answer 32

Expert Solution

Answer to Problem 8.57P

The cis -1-bromo-4-tert-butylcyclohexane reacts faster when compared to trans-1-bromo-4-tert-butylcyclohexane.

cis -1-bromo-4-tert-butylcyclohexane with NaOCH₃.

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 11

trans-1-bromo-4-tert-butylcyclohexane with NaOCH₃

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 12

Answer 33

Expert Solution

Answer 34

Expert Solution

Answer 35

Expert Solution

Answer 36

Explanation of Solution

NaOCH_3, is a strong nucleophile. The reaction follows the SN2 in which the backside attack occurs. With the cis isomer the nucleophile can attack by the equatorial position to avoid the 1, 3-diaxial interaction. Moreover only the cis isomer has the Br and Β carbon in the anti periplanar that is in trans diaxial arrangement when compared to trans isomer. Thus the cis isomer reacts faster than trans isomer.

cis -1-bromo-4-tert-butylcyclohexane with NaOCH₃

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 13

trans-1-bromo-4-tert-butylcyclohexane with NaOCH₃

Organic Chemistry-Package(Custom), Chapter 8, Problem 8.57P , additional homework tip 14

Answer 37

Conclusion

Thus the cis -1-bromo-4-tert-butylcyclohexane reacts faster when compared to trans-1-bromo-4-tert-butylcyclohexane

Answer 38

Interpretation Introduction

(e)

Interpretation:

To explain why there is different products formed when the alkyl halides uses two different alkoxides.

Concept introduction:

The most common mechanism for dehydrohalogenation is the E2 mechanism. An E2 reaction exhibits a second-order kinetics, in which the reaction is bimolecular and both the alkyl halide and the base appear in the rate equation. The most straightforward explanation for the second-order kinetics is a concerted reaction: all bonds are broken and formed in a single step. In other words simultaneously all bonds are broken and formed.

The transition state of an E2 reaction consists of four atoms from the alkyl halide-one hydrogen atom, two carbon atoms, and the leaving group (X)-all aligned in the same plane. There are two ways for the C-H and C-x bonds to be coplanar. When the H and X atoms oriented on the same side of the molecule. This geometry is called syn periplanar. While the H and X atoms oriented on opposite sides of the molecule. This geometry is called anti periplanar. The dihedral angle for the C-H and C-X bonds equals 0° for the syn periplanar arrangement and 180° for the anti periplanar arrangement.

Whereas the E1 reaction is a twostep reaction of first order kinetics. The two steps reaction is the bond to the leaving group breaks first before the π bond is formed.

Expert Solution

Answer to Problem 8.57P

The bulky base ^–OC(CH₃)₃ favours the elimination by an E2 reaction mechanism, to get a mixture of enantiomers A and B. The strong nucleophile ^–OCH₃ favours nucleophile substitution by an SN2 mechanism. Inversion of configuration results from backside attack of the nucleophile. Thus different product are formed.

Explanation of Solution

^-OCH_3, is a strong nucleophile. The reaction follows the SN2 in which the backside attack occurs. With the cis isomer the nucleophile can attack by the equatorial position to avoid the 1, 3-diaxial interaction. Moreover only the cis isomer has the Br and Β carbon in the anti periplanar that is in trans diaxial arrangement when compared to trans isomer. Thus the cis isomer reacts faster than trans isomer. The bulky base ^–OC(CH₃)₃ favours the elimination by an E2 reaction mechanism, to get a mixture of enantiomers A and B.

Conclusion

Thus different product are formed when the alkyl halides uses two different alkoxides are used.

Answer 39

Interpretation Introduction

(e)

Interpretation:

To explain why there is different products formed when the alkyl halides uses two different alkoxides.

Concept introduction:

The most common mechanism for dehydrohalogenation is the E2 mechanism. An E2 reaction exhibits a second-order kinetics, in which the reaction is bimolecular and both the alkyl halide and the base appear in the rate equation. The most straightforward explanation for the second-order kinetics is a concerted reaction: all bonds are broken and formed in a single step. In other words simultaneously all bonds are broken and formed.

The transition state of an E2 reaction consists of four atoms from the alkyl halide-one hydrogen atom, two carbon atoms, and the leaving group (X)-all aligned in the same plane. There are two ways for the C-H and C-x bonds to be coplanar. When the H and X atoms oriented on the same side of the molecule. This geometry is called syn periplanar. While the H and X atoms oriented on opposite sides of the molecule. This geometry is called anti periplanar. The dihedral angle for the C-H and C-X bonds equals 0° for the syn periplanar arrangement and 180° for the anti periplanar arrangement.

Whereas the E1 reaction is a twostep reaction of first order kinetics. The two steps reaction is the bond to the leaving group breaks first before the π bond is formed.

Answer 40

Expert Solution

Answer to Problem 8.57P

The bulky base ^–OC(CH₃)₃ favours the elimination by an E2 reaction mechanism, to get a mixture of enantiomers A and B. The strong nucleophile ^–OCH₃ favours nucleophile substitution by an SN2 mechanism. Inversion of configuration results from backside attack of the nucleophile. Thus different product are formed.

Answer 41

Expert Solution

Answer 42

Expert Solution

Answer 43

Expert Solution

Answer 44

Explanation of Solution

^-OCH_3, is a strong nucleophile. The reaction follows the SN2 in which the backside attack occurs. With the cis isomer the nucleophile can attack by the equatorial position to avoid the 1, 3-diaxial interaction. Moreover only the cis isomer has the Br and Β carbon in the anti periplanar that is in trans diaxial arrangement when compared to trans isomer. Thus the cis isomer reacts faster than trans isomer. The bulky base ^–OC(CH₃)₃ favours the elimination by an E2 reaction mechanism, to get a mixture of enantiomers A and B.