Modern Database Management
13th Edition
ISBN: 9780134773650
Author: Hoffer
Publisher: PEARSON
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Chapter 8, Problem 8.54PAE
Program Plan Intro
Problems that might arise from vertical partitioning of a relation and general conditions influencing them.
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Given these potential problems, what general conditions influence when to partition a relation vertically?
What problems can arise from vertical partitioning of a relation and general conditions influencing them.
How does the primary key of a relation relate to the interdependencies among its other attributes from a practical standpoint?
Chapter 8 Solutions
Modern Database Management
Ch. 8 - Prob. 8.1RQCh. 8 - Prob. 8.2RQCh. 8 - Prob. 8.3RQCh. 8 - Prob. 8.4RQCh. 8 - Prob. 8.5RQCh. 8 - Prob. 8.6RQCh. 8 - Prob. 8.7RQCh. 8 - Prob. 8.8RQCh. 8 - Explain why you sometimes have to reserve much...Ch. 8 - Why are field values sometimes coded?
Ch. 8 - Prob. 8.11RQCh. 8 - Prob. 8.12RQCh. 8 - Explain why normalized relations may not comprise...Ch. 8 - Prob. 8.14RQCh. 8 - List three common situations that suggest that...Ch. 8 - Explain the reasons why some experts are against...Ch. 8 - Prob. 8.17RQCh. 8 - Prob. 8.18RQCh. 8 - Prob. 8.19RQCh. 8 - Prob. 8.20RQCh. 8 - Prob. 8.21RQCh. 8 - Prob. 8.22RQCh. 8 - One of the strongest recommendations regarding...Ch. 8 - Explain why an index is useful only if there is...Ch. 8 - Indexing can clearly be very beneficial. Why...Ch. 8 - Prob. 8.26RQCh. 8 - Prob. 8.27RQCh. 8 - Describe the role of data dictionary in the...Ch. 8 - Prob. 8.29RQCh. 8 - Prob. 8.30RQCh. 8 - Explain how creating a view may increase data...Ch. 8 - Prob. 8.32RQCh. 8 - Prob. 8.33RQCh. 8 - Prob. 8.34RQCh. 8 - Prob. 8.35RQCh. 8 - Prob. 8.36RQCh. 8 - Prob. 8.37RQCh. 8 - Prob. 8.38RQCh. 8 - Prob. 8.39RQCh. 8 - How can views be used as part of data security?...Ch. 8 - Prob. 8.41RQCh. 8 - Prob. 8.42RQCh. 8 - Consider the following two relations for...Ch. 8 - Prob. 8.44PAECh. 8 - Prob. 8.45PAECh. 8 - Prob. 8.46PAECh. 8 - Prob. 8.47PAECh. 8 - Suppose you are designing a default value for the...Ch. 8 - When a student has not chosen a major at a...Ch. 8 - Prob. 8.50PAECh. 8 - Prob. 8.51PAECh. 8 - Consider the relations in Problem and Exercise...Ch. 8 - Prob. 8.53PAECh. 8 - Prob. 8.54PAECh. 8 - Prob. 8.55PAECh. 8 - Prob. 8.56PAECh. 8 - Prob. 8.57PAECh. 8 - Consider the relations specified in Problem and...Ch. 8 - Prob. 8.59PAECh. 8 - Prob. 8.60PAECh. 8 - Prob. 8.61PAECh. 8 - Prob. 8.62PAECh. 8 - Prob. 8.63PAECh. 8 - Prob. 8.64PAECh. 8 - Problems and Exercises 8-65 through 8-68 refer to...Ch. 8 - Prob. 8.66PAECh. 8 - Problems and Exercises 8-65i5 through 8-68 refer...Ch. 8 - Refer to Figure 4-5 0. For each of the following...Ch. 8 - Prob. 8.69PAECh. 8 - Prob. 8.70PAECh. 8 - Prob. 8.71PAECh. 8 - Prob. 8.72PAECh. 8 - Prob. 8.73PAECh. 8 - Prob. 8.74PAECh. 8 - Prob. 8.75PAECh. 8 - Prob. 8.76PAECh. 8 - Prob. 8.77PAE
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- Explain three situations under which a surrogate key for the main key of a relation should be established.arrow_forwardHow does the primary key of a relation relate to the interdependencies of its characteristics from a functional standpoint?arrow_forwardAn explanation of the three circumstances in which the secondary key of a relation should be used instead of the main key of the connectionarrow_forward
- Explain three scenarios in which a surrogate key for a relation's primary key should be generated.arrow_forwardDescribe three circumstances in which a substitute key for a relation's primary key should be established.arrow_forwardIt is important to build a hybrid merge-join technique in order to accomplish the task of combining two relations that are not physically ordered but do share an index on the features that are in concern.arrow_forward
- Here are three examples of when it makes sense to create a surrogate key in place of the primary key in a relation.arrow_forwardBased on the following functional dependencies, for the relation SCHEDULE bring it into a set of 3NF relations. Dependencies: Section#, CourseID, Semester ID → RoomNo Section#, CourseID, Semester ID → Inst_ID Section#, CourseID, Semester ID → Week_day Section#, CourseID, Semester ID → Start_time Section#, CourseID, Semester ID → End_time Course_ID → Course Name RoomNo → Occupancy Instr_ID → Instr_name SCHEDULE CourseID, Section#, Semester ID, Course Name ,RoomNo, Occupancy, Inst_ID, Instr_Name, Week_day, Start_time, End_time)arrow_forwardWhat does it mean to be related? How do you define a relation's properties?arrow_forward
- Cardinality ratios often dictate the detailed design of a database. The cardinality ratio depends on the real-world meaning of the entity types involved and is defined by the specific application. For the following binary relationships, suggest cardinality ratios based on the following description of the mini-world: Each BANK has a unique Code, as well as a Name and Address. Each BANK is related to one or more BANK-BRANCHes, and the BranhNo is unique among each set of BANK-BRANCHes that are related to the same BANK. Each BANK-BRANCH has an Address. Each BANK-BRANCH has zero or more LOANS and zero or more ACCTS. Each ACCOUNT has an AcctNo (unique), Balance, and Type and is related to exactly one BANK-BRANCH and to at least one CUSTOMER. Each LOAN has a LoanNo (unique), Amount, and Type and is related to exactly one BANK-BRANCH and to at least one CUSTOMER. Each CUSTOMER has an SSN (unique), Name, Phone, and Address, and is related to zero or more ACCOUNTS and to zero or more LOANS.…arrow_forwardPlease transform the following Entity-Relationship Schema (Diagram) into a Relational Schema. Please do not forget to specify the keys and constraints for each relation. (RESP_ENG: the engineer responsible for the project. WORKS_ON: the project an engineer works on). MANAGES SSNO FName PNo PROJECT EMPLOYEE LName PName |1 Address \ISA WORKS ON ENGINEER Speciality RESP ENGarrow_forwardPART A. Identify all dependencies. PART B. Write Relation Schema to meet 3NF requirements PART C. DRAW CROWS FOOT ERDarrow_forward
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