Modern Database Management
13th Edition
ISBN: 9780134773650
Author: Hoffer
Publisher: PEARSON
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Question
Chapter 8, Problem 8.1RQ
Program Plan Intro
(a)
Define File Organization.
Expert Solution
Explanation of Solution
File organization is a process for arranging and organizing files and records in a secondary storage device. Modern
Program Plan Intro
(b)
Define Heap File Organization.
Expert Solution
Explanation of Solution
In the Heap file organization, the files and their records are not stored in a particular order. One example for heap file organization is Oracle 12c in which the default table structure is organized in the heap form.
Program Plan Intro
(c)
Define Sequential File Organization.
Expert Solution
Explanation of Solution
In the sequential file organization, the file records are stored in a particular order according to the primary key value. To search a particular record, the files are scanned from the beginning until the desired record is located.
Program Plan Intro
(d)
Define Index File Organization.
Expert Solution
Explanation of Solution
Index file organization stores the files and records either sequentially or non-sequentially and creates an index to locate individual record with the help of applictaion software. An index is a table that contains index entries matching a key value with one record that contains the location of record.
Program Plan Intro
(e)
Define Hashed File Organization.
Expert Solution
Explanation of Solution
Hashed file organization determines the address of each record using the hashing
Program Plan Intro
(f)
Define Denormalization.
Expert Solution
Explanation of Solution
Denormalization is a process that transforms the normalized tables into non normalized physical record specification.
Program Plan Intro
(g)
Define Composite key.
Expert Solution
Explanation of Solution
Composite key is also known as compound key and is a combination of two or more attributes which combinely identifies a row in the table uniquely.
Program Plan Intro
(h)
Define Secondary Key.
Expert Solution
Explanation of Solution
An entity can have multiple choices for primary keys which are collectively known as candidate keys out of which, one is considered as a primary key and other keys which are not selected as primary key are known as secondary keys.
Program Plan Intro
(i)
Define Data Type.
Expert Solution
Explanation of Solution
Data type is a detailed coding scheme used to represent organizatonal data and is recognized by system software like DBMS. The pattern of coding scheme is transparent to the user.
Program Plan Intro
(j)
Define Data Dictionary.
Expert Solution
Explanation of Solution
Data dictionary is a set of files that contain collection of data which describe the data model. It contains record about the objects in the database.
Program Plan Intro
(k)
Define Transaction log.
Expert Solution
Explanation of Solution
Transaction log is an integral and important part of SQL server database. It is a file that contains all the log records of the logging process in SQL server database and plays an important role in the disaster recovery. Every database modification or transaction occurred is recorded in a transaction log.
Program Plan Intro
(l)
Define Encryption.
Expert Solution
Explanation of Solution
Encryption is a process of encoding any information or message so that any unauthorized parties cannot access that confidential information.
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The player starts at the bottom left corner of the labyrinth. He has to get to the top right corner of the labyrinth as fast he can, avoiding a meeting with the evil dragon. Take care that the player and the dragon cannot start off on walls. Also the dragon starts off from a randomly chosen position
public class Labyrinth { private final int size; private final Cell[][] grid;
public Labyrinth(int size) { this.size = size; this.grid = new Cell[size][size]; generateLabyrinth(); }
private void generateLabyrinth() { Random rand = new Random(); for (int i = 0; i < size; i++) { for (int j = 0; j < size; j++) { // Randomly create walls and paths grid[i][j] = new Cell(rand.nextBoolean()); } } // Ensure start and end are…
Change the following code so that it checks the following 3 conditions:
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Chapter 8 Solutions
Modern Database Management
Ch. 8 - Prob. 8.1RQCh. 8 - Prob. 8.2RQCh. 8 - Prob. 8.3RQCh. 8 - Prob. 8.4RQCh. 8 - Prob. 8.5RQCh. 8 - Prob. 8.6RQCh. 8 - Prob. 8.7RQCh. 8 - Prob. 8.8RQCh. 8 - Explain why you sometimes have to reserve much...Ch. 8 - Why are field values sometimes coded?
Ch. 8 - Prob. 8.11RQCh. 8 - Prob. 8.12RQCh. 8 - Explain why normalized relations may not comprise...Ch. 8 - Prob. 8.14RQCh. 8 - List three common situations that suggest that...Ch. 8 - Explain the reasons why some experts are against...Ch. 8 - Prob. 8.17RQCh. 8 - Prob. 8.18RQCh. 8 - Prob. 8.19RQCh. 8 - Prob. 8.20RQCh. 8 - Prob. 8.21RQCh. 8 - Prob. 8.22RQCh. 8 - One of the strongest recommendations regarding...Ch. 8 - Explain why an index is useful only if there is...Ch. 8 - Indexing can clearly be very beneficial. Why...Ch. 8 - Prob. 8.26RQCh. 8 - Prob. 8.27RQCh. 8 - Describe the role of data dictionary in the...Ch. 8 - Prob. 8.29RQCh. 8 - Prob. 8.30RQCh. 8 - Explain how creating a view may increase data...Ch. 8 - Prob. 8.32RQCh. 8 - Prob. 8.33RQCh. 8 - Prob. 8.34RQCh. 8 - Prob. 8.35RQCh. 8 - Prob. 8.36RQCh. 8 - Prob. 8.37RQCh. 8 - Prob. 8.38RQCh. 8 - Prob. 8.39RQCh. 8 - How can views be used as part of data security?...Ch. 8 - Prob. 8.41RQCh. 8 - Prob. 8.42RQCh. 8 - Consider the following two relations for...Ch. 8 - Prob. 8.44PAECh. 8 - Prob. 8.45PAECh. 8 - Prob. 8.46PAECh. 8 - Prob. 8.47PAECh. 8 - Suppose you are designing a default value for the...Ch. 8 - When a student has not chosen a major at a...Ch. 8 - Prob. 8.50PAECh. 8 - Prob. 8.51PAECh. 8 - Consider the relations in Problem and Exercise...Ch. 8 - Prob. 8.53PAECh. 8 - Prob. 8.54PAECh. 8 - Prob. 8.55PAECh. 8 - Prob. 8.56PAECh. 8 - Prob. 8.57PAECh. 8 - Consider the relations specified in Problem and...Ch. 8 - Prob. 8.59PAECh. 8 - Prob. 8.60PAECh. 8 - Prob. 8.61PAECh. 8 - Prob. 8.62PAECh. 8 - Prob. 8.63PAECh. 8 - Prob. 8.64PAECh. 8 - Problems and Exercises 8-65 through 8-68 refer to...Ch. 8 - Prob. 8.66PAECh. 8 - Problems and Exercises 8-65i5 through 8-68 refer...Ch. 8 - Refer to Figure 4-5 0. For each of the following...Ch. 8 - Prob. 8.69PAECh. 8 - Prob. 8.70PAECh. 8 - Prob. 8.71PAECh. 8 - Prob. 8.72PAECh. 8 - Prob. 8.73PAECh. 8 - Prob. 8.74PAECh. 8 - Prob. 8.75PAECh. 8 - Prob. 8.76PAECh. 8 - Prob. 8.77PAE
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