Materials Science And Engineering Properties
1st Edition
ISBN: 9781111988609
Author: Charles Gilmore
Publisher: Cengage Learning
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Chapter 8, Problem 69CQ
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The linear portion of the stress- strain diagram of steel is known as the
A
Modulus of elasticity
B Plastic range
(c) Elastic range
D Stain hardening
An aluminum alloy [E = 70 GPa; v = 0.33; a = 23.0×10-6/°C] bar is subjected to a tensile load P. The bar has a depth of d = 260 mm, a
cross-sectional area of A = 14720 mm2, and a length of L = 5.5 m. The initial longitudinal normal strain in the bar is zero. After load P
is applied and the temperature of the bar has been increased by AT = 46°C, the longitudinal normal strain is found to be 1680 µɛ.
% D
Calculate the change in bar depth d after the load P has been applied and the temperature has been increased.
L
P
Answer:
Ad =
i
mm
An AISI 1040 hot-rolled steel [E = 207 GPa; α = 11.3×10–6/°C] bar is held between two rigid supports. The bar is stress free at a temperature of 30°C. The bar is then heated uniformly. If the yield strength of the steel is 429 MPa, determine the temperature at which yield first occurs.
Chapter 8 Solutions
Materials Science And Engineering Properties
Ch. 8 - Prob. 1CQCh. 8 - Prob. 2CQCh. 8 - Prob. 3CQCh. 8 - Prob. 4CQCh. 8 - Prob. 6CQCh. 8 - Prob. 7CQCh. 8 - Prob. 8CQCh. 8 - Prob. 9CQCh. 8 - Prob. 10CQCh. 8 - Prob. 11CQ
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- The aluminum (E=15x10^10psi, α=11.6x10^-6/°F) shell is fully bonded to the brass (E=10.6x10^6psi, α=12.9x10^-6/°F) sore, and the assembly is unstressed at a temperature of 78°F. Considering only axial deformations, determine the stress when the temperature reaches 180°F (a) in the brass core (b) in the aluminum shellarrow_forwardd) No increase Which of the following is not a property of steel materials? C a) Homogeneous and isotropic b) Linearly elastic stress-strain behavior c) Recyclable d) Fire-resistantarrow_forwardIn the bulk modulus of Brass is 110 GPa and its Poisson's ratio is 0.30, then the elastic modulusarrow_forward
- The cube of aluminum is subjected to the three stresses shown. Determine the principal strains. Take Eal = 10(103) ksi and nal = 0.33.arrow_forwardNarrow bars of aluminum are bonded to the two sides of a thick steel plate as shown. Initially, at T₁ = 70°F, all stresses are zero. Knowing that the temperature will be slowly raised to T₂ and then reduced to T₁, determine (a) the highest temperature T₂ that does not result in residual stresses, (b) the temperature T₂ that will result in a residual stress in the aluminum equal to 58 ksi. Assume aa = 12.8 x 10-6/°F for the aluminum and a = 6.5 × 10-6/°F for the steel. Further assume that the aluminum is elastoplastic with E = 10.9 × 106 psi and ay = 58 ksi. (Hint: Neglect the small stresses in the plate.) Fig. P2.121arrow_forwarda. Which of the following gives the approximate modulus elasticity of the The stress-strain diagram for a steel alloy having an original diam. of 12 mm and a material? gauge length of 50 mm is given in the figure. b. Which of the following gives the load on the specimen that causes yielding? c. Which of the following gives the ultimate load the specimen will (8) MPa ultimate strength- 80 support? 70 60 repture' strength yäerd põint- 50+ 40 propórtional limit 30 20+ 10+ 0 .0005 .001.0015 .002 .0025 .003 .0035 E(mm/mm)arrow_forward
- A batch of casted mild steel has a modulus of elasticity of 200 GPa and a yield strength of 250 MPa. Calculate for its modulus of resilience. After cold working the steel, the yield strength increases to 310 MPa. Calculate for the percent reduction in the average grain diameter given σo = 70 MPa and k = 0.74.arrow_forwardAn aluminum alloy [E = 74 GPa; v = 0.33; a = 23.0 x 10-6/°C] plate is subjected to a tensile load P. The plate has a depth of d = 265 mm, a cross-sectional area of A = 5300 mm², and a length of L= 4.2 m. The initial longitudinal normal strain in the plate is zero. After load P is applied and the temperature of the plate has been increased by AT = 57°C, the longitudinal normal strain in the plate is found to be 2920 με. Determine: (a) the magnitude of load P. (b) the change in plate depth Ad. L P Answer: (a) P = i (b) Δd = i kN mmarrow_forwardSteel, Brass, and Copper rods are connected as shown in the figure. Initially, the temperature was 15 degrees Celsius and the stress on the bars is zero. Eventually, the temperature increased to 25 degrees Celsius. Determine the total deformation on the steel. Steel Brass Copper Est = 200 GPa Ebr = 100 GPa Ecu = 120 GPa %3D ast = 12(10-6)/°C abr = 21(10¬6)/°C acu = 17(10-)/°C %3D Acu = 515 mm² |Ast = 200 mm? Abr = 450 mm² %3D 300 mm- 200 mm 100 mm O -0.0058mm O 0.0165mm O -0.0165mm O 0.0058mmarrow_forward
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