Materials Science And Engineering Properties
1st Edition
ISBN: 9781111988609
Author: Charles Gilmore
Publisher: Cengage Learning
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Chapter 8, Problem 100CQ
To determine
The primary usage of butadiene rubber.
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23) An HSS 10 × 6 × 5/16 with F, = 46 ksi is used as a column. The length is 16 feet.
Both ends are pinned, and there is support against weak axis buckling at a
point 6 feet from the top. Determine
a. the design strength for LRFD.
b.the allowable stress for ASD
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Chapter 8 Solutions
Materials Science And Engineering Properties
Ch. 8 - Prob. 1CQCh. 8 - Prob. 2CQCh. 8 - Prob. 3CQCh. 8 - Prob. 4CQCh. 8 - Prob. 6CQCh. 8 - Prob. 7CQCh. 8 - Prob. 8CQCh. 8 - Prob. 9CQCh. 8 - Prob. 10CQCh. 8 - Prob. 11CQ
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- + H.W ATF pland as illustrated in hig below. has. the following: a primary clarifier with a 16.8m diameter, 21m (SWD), and Single peripheral weir, an 26m diameter TE with a 2.1 deep stone filled bed; and a final settling Tank with a 15-2m diameter, 2.1m (SWD), and single peripheral weir, The normal operating recirculation ratio is NA 0.5 with return to the wet well from the bottom of the final during periods of low influent flow (fig② The daily wow flow is 5220 m³/d with an average BOD of 180-9/1 Calculate the loadings on all of the units, and the anticipated. effluent BOD 2 20°C and 16C * Assume @ efficiency of removal BOD load of 78% in 20 C Is of 68% 7416 68/74/6 Futurarrow_forwardW10 x 33 A992 steel [x= ry=9 Q2) Does the column shown in Figure below have enough available strength to support the given service loads? a. Use LRFD. b.Use ASD D= 180k L = 540* W14 x 90 13' A992 steel (Sto Sage)arrow_forwardStatics Beam Problem – Find Reactions, Shear, Moment, and Deflection Description: I need help solving this statics problem related to a beam subjected to multiple loads. The problem asks for: Determining the three reactions at the supports. Drawing the shear force diagram. Drawing the bending moment diagram. Drawing the deflected shape of the beam.arrow_forward
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- subjectarrow_forwardExample 5.2: Design Example of a Square Foundation for a Colum Figure A.3a shows a square column foundation with the followin conditions: Live load=L=675 kN Dead load D= 1125 kN Allowable gross soil-bearing capacity 145 kN/m² Column size-0.5 m x 0.5 m -20.68 MN/m² 1,413.7 MN/m² Let it be required to design the column foundation. 1.25m-D L-675 AN D-1125 AN (a) Column section- 05 m x 0.5marrow_forwardExample 5.3: Design Example of a Rectangular Foundation for Column This section describes the design of a rectangular foundation to support a column having dimensions of 0.4 m x 0.4 m in cross section. Other details are as follows: Dead load D= 290 kN Live load L= 110 kN Depth from the ground surface to the top of the foundation = 1.2 m Allowable gross soil-bearing capacity = 120 kN/m² Maximum width of foundation = B = 1.5 m f, = 413.7 MN/m² f=20.68 MN/m² Unit weight of soil = y = 17.27 kN/m³ Unit weight of concrete = y₁ = 22.97 kN/m³ General Considerations For this design, let us assume a foundation thickness of 0.45 m (Figure A.4a). The weight of foundation/m² = 0.45 y = (0.45) (22.97) = 10.34 kN/m², and the weight of soil above the foundation/m² = (1.2)y = (1.2) (17.27) = 20.72 kN/m² Hence, the net allowable soil- bearing capacity Iqata] =120-10.34-20.72 = 88.94 kN/m² The required area of the foundation = (D+L)/4(all) = (290 + 110)/88.94 = 4.5 m². Hence, the length of the foundation…arrow_forward
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