Explanation Given data: Refer to the Figure P8.43 in the textbook for the standing of a student on the beam. Mass of the beam ( m B ) is 100 kg. Mass of the student ( m S ) is 80 kg. From the Figure, the distance between the two supports is 3.0 m and the distance between the student and support 1 is 2.0 m. Therefore, the distance of the student from the support 1 ( d 1 ) is 2.0 m. The distance between the two supports ( d ) is 3.0 m. Formula used: Write the expression for equilibrium condition of the torque as follows. ∑ τ = 0 (1) Here, ∑ τ is the sum of the torques acting on any object. Write the expression for weight of the object as follows. w = m g (2) Here, m is the mass of the object, and g is the acceleration due to gravity, which is 9.8 m s 2 . Write the expression for torque in terms of force and distance as follows. τ = F d (3) Here, F is the force, and d is the distance. Write the expression for equilibrium condition of the forces as follows. ∑ F = 0 (4) Here, ∑ F is the sum of the forces acting on any object. From the given data, the following forces acts on the beam. Weight of the beam acts at the center of the gravity (center of the beam, 1.5 m) towards in the downward direction. Weight of the student acts at the standing position of the student (2.0 m from the support 1) towards in the downward direction. The normal forces exerted by each beam towards in the upward direction. From the analysis, modify the expression in equation (4) for the sum of the forces in the vertical component ( y -component) as follows. − w B + ( − w S ) + F 1 + F 2 = 0 (5) Here, w B is the weight of the beam in the downward direction, w S is the weight of the student in the downward direction, F 1 is the normal exerted by the support 1 in the upward direction, and F 2 is the normal exerted by the support 2 in the upward direction. Calculation of weight of the student: Substitute 80 kg for m , and 9.8 m s 2 for g in equation (2), w S = ( 80 kg ) ( 9.8 m s 2 ) = 784 kg ⋅ m s 2 = 784 N { ∵ 1 kg ⋅ m s 2 = 1 N } Calculation of weight of the beam: Substitute 100 kg for m , and 9.8 m s 2 for g in equation (2), w B = ( 100 kg ) ( 9.8 m s 2 ) = 980 kg ⋅ m s 2 = 980 N Rewrite the expression in equation (5) as follows

College Physics: A Strategic Approach (3rd Edition)

3rd Edition

ISBN: 9780321879721

Author: Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field

Publisher: PEARSON

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Center of Gravity of a system

The centre of gravity is a property that is based on the geometry of a rigid body or any particle. It is described as an equilibrium point or a hypothetical location where the total weight of the body is concentrated.

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Chapter 8, Problem 43GP

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To find: The upward force exerted by each support on the beam.

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Chapter 8, Problem 42P

Chapter 8, Problem 44GP

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Chapter 8 Solutions

College Physics: A Strategic Approach (3rd Edition)

Ch. 8 - An object is acted upon by two (and only two)...Ch. 8 - Prob. 2CQ Ch. 8 - Could a ladder on a level floor lean against a...Ch. 8 - If you are using a rope to raise a tall mast,...Ch. 8 - Prob. 5CQ Ch. 8 - Prob. 6CQ Ch. 8 - Prob. 7CQ Ch. 8 - A spring exerts a 10 N force after being stretched...Ch. 8 - The left end of a spring is attached to a wall....Ch. 8 - A spring is attached to the floor and pulled...

Ch. 8 - A typical mattress has a network of springs that...Ch. 8 - Take a spring and cut it in half to make two...Ch. 8 - A wire is stretched right to its breaking point by...Ch. 8 - Steel nails are rigid and unbending. Steel wool is...Ch. 8 - The rod in Figure Q8.15 pivots around an axle at...Ch. 8 - Two children hold opposite ends of a lightweight,...Ch. 8 - Prob. 17MCQ Ch. 8 - Prob. 18MCQ Ch. 8 - Prob. 19MCQ Ch. 8 - Prob. 20MCQ Ch. 8 - Prob. 21MCQ Ch. 8 - Prob. 22MCQ Ch. 8 - You have a heavy piece of equipment hanging from a...Ch. 8 - Prob. 24MCQ Ch. 8 - Prob. 1P Ch. 8 - Prob. 2P Ch. 8 - Prob. 3P Ch. 8 - Prob. 4P Ch. 8 - Youre carrying a 3.6-m-long, 25 kg pole to a...Ch. 8 - Prob. 6P Ch. 8 - How much torque must the pin exert to keep the rod...Ch. 8 - Prob. 8P Ch. 8 - Prob. 9P Ch. 8 - Consider the procedure for measuring a womans...Ch. 8 - Prob. 11P Ch. 8 - Prob. 12P Ch. 8 - Prob. 13P Ch. 8 - Prob. 14P Ch. 8 - Prob. 15P Ch. 8 - Prob. 16P Ch. 8 - Prob. 17P Ch. 8 - The stability of a vehicle is often rated by the...Ch. 8 - You want to slowly push a stiff board across a 20...Ch. 8 - Prob. 20P Ch. 8 - A car manufacturer claims that you can drive its...Ch. 8 - Prob. 22P Ch. 8 - One end of a spring is attached to a wall. A 25 N...Ch. 8 - An orthodontic spring, connected between the upper...Ch. 8 - Experiments using optical tweezers measure the...Ch. 8 - A spring has an unstretched length of 10 cm. It...Ch. 8 - One end of a 10-cm-long spring is attached to the...Ch. 8 - A spring stretches 5.0 cm when a 0.20 kg block is...Ch. 8 - A 1.2 kg block is hung from a vertical spring,...Ch. 8 - You need to make a spring scale to measure the...Ch. 8 - A force stretches a wire by 1.0 mm. a. A second...Ch. 8 - What hanging mass will stretch a 2.0-m-long,...Ch. 8 - How much force does it take to stretch a...Ch. 8 - An 80-cm-long, 1.0-mm-diameter steel guitar string...Ch. 8 - A student is testing a 1.0 m length of...Ch. 8 - A 1.2-m-long steel rod with a diameter of 0.50 cm...Ch. 8 - A mineshaft has an ore elevator hung from a single...Ch. 8 - The normal force of the ground on the foot can...Ch. 8 - A three-legged wooden bar stool made out of solid...Ch. 8 - Prob. 40P Ch. 8 - A glass optical fiber in a communications system...Ch. 8 - The Achilles tendon connects the muscles in your...Ch. 8 - Prob. 43GP Ch. 8 - Prob. 44GP Ch. 8 - Using the information in Figure 8.2, calculate the...Ch. 8 - A woman weighing 580 N does a pushup from her...Ch. 8 - Prob. 47GP Ch. 8 - Prob. 48GP Ch. 8 - Prob. 49GP Ch. 8 - The wheel of mass m in Figure P8.50 is pulled on...Ch. 8 - A 5.0 kg mass hanging from a spring scale is...Ch. 8 - Two identical, side-by-side springs with spring...Ch. 8 - Two springs have the same equilibrium length but...Ch. 8 - Figure P8.54 shows two springs attached to a block...Ch. 8 - A 60 kg student is standing atop a spring in an...Ch. 8 - A 25 kg child bounces on a pogo stick. The pogo...Ch. 8 - Figure P8.57 shows a lightweight plank supported...Ch. 8 - In the hammer throw, an athlete spins a heavy mass...Ch. 8 - There is a disk of cartilage between each pair of...Ch. 8 - In Example 8.1, the tension in the biceps tendon...Ch. 8 - Larger animals have sturdier bones than smaller...Ch. 8 - Orb spiders make silk with a typical diameter of...Ch. 8 - Prob. 63MSPP Ch. 8 - Prob. 64MSPP Ch. 8 - Prob. 65MSPP

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The upward force exerted by each support on the beam.

Solution Summary: The author explains the upward force exerted by the support 1 and support 2 on the beam.

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To find: The upward force exerted by each support on the beam.

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Chapter 8 Solutions