Pearson eText Bauman Microbiology with Diseases by Body Systems -- Instant Access (Pearson+)
5th Edition
ISBN: 9780135891018
Author: ROBERT BAUMAN
Publisher: PEARSON+
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Textbook Question
Chapter 8, Problem 3CT
A thermocycler uses DNA polymerase from hypenhermophilic prokaryotes, but it cannot use DNA polymerase derived from E. coli. Why not?
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Chapter 8 Solutions
Pearson eText Bauman Microbiology with Diseases by Body Systems -- Instant Access (Pearson+)
Ch. 8 - Why arent the terms recombinant DNA technology...Ch. 8 - Prob. 2TMWCh. 8 - Why wasnt polymerase chain reaction (PCR)...Ch. 8 - Why dont doctors routinely insert genes into their...Ch. 8 - Prob. 5TMWCh. 8 - Which of the following statements is true...Ch. 8 - A DNA gene synthesized from an RNA template is...Ch. 8 - Prob. 3MCCh. 8 - Prob. 4MCCh. 8 - Prob. 5MC
Ch. 8 - Prob. 6MCCh. 8 - Prob. 7MCCh. 8 - Prob. 8MCCh. 8 - Prob. 9MCCh. 8 - Prob. 10MCCh. 8 - Modified True/False 1. ________ Restriction...Ch. 8 - Modified True/False 2. ________ Restriction...Ch. 8 - Prob. 3MTFCh. 8 - Prob. 4MTFCh. 8 - Prob. 5MTFCh. 8 - Label the reagents and steps of PCR on the figure...Ch. 8 - Describe three artificial methods of introducing...Ch. 8 - Prob. 2SACh. 8 - Prob. 3SACh. 8 - Prob. 4SACh. 8 - List three potential problems of recombinant DNA...Ch. 8 - Examine the restriction sites listed in Table 8.1...Ch. 8 - CRITICAL THINKING 2 A cancer-inducing virus,...Ch. 8 - A thermocycler uses DNA polymerase from...Ch. 8 - Prob. 4CTCh. 8 - Prob. 5CTCh. 8 - Prob. 6CTCh. 8 - Prob. 7CTCh. 8 - Prob. 8CTCh. 8 - Prob. 9CTCh. 8 - Using the following terms, fill in the following...
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- When would you expect to see the E. coli produce the enzyme beta galactosidase if the growth media contained only glucose as an energy source?arrow_forwardIf five E. coli cells are placed into sterile nutrient media under optimal conditions (with a growth rate of 20 minutes per cell division), how many E. coli cells will be present after 6 hours of optimal growth? 5 x 26 = 320 cells 5 x 29 = 2,560 cells 5 x 212 = 20,480 cells 5 x 215 = 163,840 cells 5 x 218 = 1,310,720 cellsarrow_forwardWhy is the DNA polymerase used in PCR derived from an extreme thermophile bacteria species rather than a mesophile bacteria species? (be sure to describe the mesophile DNA polymerase as well as the extreme thermophile DNA polymerase.)arrow_forward
- In your laboratory, you have an F− strain of E. coli that is resistantto streptomycin and is unable to metabolize lactose, but it can metabolizeglucose. Therefore, this strain can grow on a medium thatcontains glucose and streptomycin, but it cannot grow on a mediumcontaining lactose. A researcher has sent you two E. colistrains in two separate tubes. One strain, let’s call it strain A, hasan F′ factor (an F prime factor) that carries the genes that are requiredfor lactose metabolism. On its chromosome, it also has thegenes that are required for glucose metabolism. However, it is sensitiveto streptomycin. This strain can grow on a medium containinglactose or glucose, but it cannot grow if streptomycin is addedto the medium. The second strain, let’s call it strain B, is an F−strain. On its chromosome, it has the genes that are required forlactose and glucose metabolism. Strain B is also sensitive to streptomycin.Unfortunately, when strains A and B were sent to you, thelabels had fallen…arrow_forwardWhat are the reagents and materials used/needed in the extraction of invertase from yeast? for a lab experiment regarding enzymes.arrow_forwardTo digest cellulose in the environment, a fungus produces a (n): endoenzyme exoenzyme catalase polymerase constitutive enzymearrow_forward
- How can i explain my answers in depth in microbology for example this question: Assume that there are horizontal gene transfers between two completely different bacterial species. In one case it is a plasmid that is transferred via conjugation, in the other case it is a part of the bacterial chromosome that is transferred via transformation. In which of the two cases is it most likely that the transferred DNA will remain and be able to function in the recipient cells? Explain the biological background to your answer . How do I break down the question so I answer it fullyarrow_forwardYou got an opportunity to join a professor lab who is working in-vivo model and specifically looking at the dysregulation of mitochondria in liver. He asked you to isolate mitochondria from a Rat liver and placed in an assay medium. Based on the knowledge you gain in this course so far, please answer the following questions: a) Which technique will you use to isolate mitochondria? b) What happens to the pH of the medium when the medium is kept anaerobic? c) What happens when O2-saturated saline is added to the mixture?arrow_forwardThe pathway shown below is used by a fungus to create Arginine from a precursor starter molecule. A nonsense mutation occurs in the gene that encodes enzyme 2. This fungus is grown on media that only contains the precursor. Discuss the effects of this mutation on:(i) The function of Enzyme 2 (ii) The potential of the fungus to produce Ornithinearrow_forward
- The primary aim of fixation is to preserve the morphological and chemical integrity of the cell. Explain.arrow_forwardYou inoculate two test tubes with the same amount of identical growth medium and with the same number of identical yeast cells and grow these cells under identical conditions except for the presence or absence of oxygen. b) The cells of both cultures convert glucose to pyruvate via glycolysis, and then further metabolize pyruvate. Are the cells of both cultures able to obtain the same amount of ATP from glycolysis? Explain. Under anaerobic conditions, the carbon from pyruvate will ultimately be found in which molecule? Under aerobic conditions, the carbon from pyruvate will ultimately be found in which molecule?arrow_forwardWhat cell types would be able to grow on the ECM in the following situations?a) Streptomycin was not added to the ECM.b) The ECM contains thiamine.c) The ECM contains all 20 amino acids and all 5 nitrogenous nucleic acid bases. Reminder: ECM = minimal medium + glucose + has streptomycin antibioticarrow_forward
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