Concept explainers
(a)
Interpretation: The given combustion reaction needs to be balanced.
Concept Introduction:A
A balance chemical reaction contains same number of atoms at both sides of the chemical reaction.
(a)
Answer to Problem 37A
Explanation of Solution
In a balance chemical equation, the number of atoms must be same at both sides. To balance a chemical reaction, coefficients must be added with the chemical formula to make it same at both sides.
Reactant | Product |
C = 2→4 | C = 1→4 |
H = 6→12 | H = 2→12 |
O = 2→14 | O = 3→10 |
Thus the balance chemical equation must be:
(b)
Interpretation: The given combustion reaction needs to be balanced.
Concept Introduction:A chemical reaction can be described as the process of conversion of reactant molecules to product molecules by breaking and making of chemical bonds.
A balance chemical reaction contains same number of atoms at both sides of the chemical reaction.
(b)
Answer to Problem 37A
Explanation of Solution
In a balance chemical equation, the number of atoms must be same at both sides. To balance a chemical reaction, coefficients must be added with the chemical formula to make it same at both sides.
Reactant | Product |
C = 2 | C = 1→2 |
H = 6 | H = 2→6 |
O = 3→7 | O = 3→7 |
Thus the balance chemical equation must be:
(c)
Interpretation: The given combustion reaction needs to be balanced.
Concept Introduction:A chemical reaction can be described as the process of conversion of reactant molecules to product molecules by breaking and making of chemical bonds.
A balance chemical reaction contains same number of atoms at both sides of the chemical reaction.
(c)
Answer to Problem 37A
Explanation of Solution
In a balance chemical equation, the number of atoms must be same at both sides. To balance a chemical reaction, coefficients must be added with the chemical formula to make it same at both sides.
Reactant | Product |
C = 2→4 | C = 1→4 |
H = 6→12 | H = 2→12 |
O = 4→14 | O = 3→14 |
Thus the balance chemical equation must be:
Chapter 8 Solutions
World of Chemistry
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