
Concept explainers
(a)
Interpretation:The indicated synthesis for alcohol should be evaluated as either good, not so good or worthless.
Concept introduction:Haloalkane solvolysis with ethanol, methanol or water is a typical example for unimolecuar substitution. It proceeds via two-step mechanism. The first slow step that determines rate is the removal of leaving group from the substrate haloalkane and generates a carbocation. Since the rate is only governed by substrate alone and no other nucleophile or solvent it is termed as unimolecuar substitution. The final step is attack of nucleophile on carbocation generated and formation of racemic products.
Tertiary or secondary halides undergo fastest unimolecuar substitution as they can readily form the tertiary carbocation followed by secondary and least reactive are primary.
(b)
Interpretation: The indicated synthesis for alcohol should be classified as either good, not so good or worthless.
Concept introduction:Bimolecular substitution or
A general
(c)
Interpretation: The indicated synthesis for alcohol should be classified as either good, not so good or worthless.
Concept introduction:Bimolecular substitution or
A general
(d)
Interpretation: The indicated synthesis for alcohol should be classified as either good, not so good or worthless.
Concept introduction: Bimolecular substitution or
A general
(e)
Interpretation: The indicated synthesis for alcohol should be classified as either good, not so good or worthless.
Concept introduction: Bimolecular substitution or
A general
(f)
Interpretation: The indicated synthesis for alcohol should be classified as either good, not so good or worthless.
Concept introduction: Bimolecular substitution or
A general
(g)
Interpretation: The indicated synthesis for alcohol should be evaluated as either good, not so good or worthless.
Concept introduction: Haloalkane solvolysis with ethanol, methanol or water is a typical example for unimolecuar substitution. It proceeds via two-step mechanism. The first slow step that determines rate is the removal of leaving group from the substrate haloalkane and generates a carbocation. Since the rate is only governed by substrate alone and no other nucleophile or solvent it is termed as unimolecuar substitution. The final step is attack of nucleophile on carbocation generated and formation of racemic products.
Tertiary or secondary halides undergo fastest unimolecuar substitution as they can readily form the tertiary carbocation followed by secondary and least reactive are primary.
(h)
Interpretation: The indicated synthesis for alcohol should be classified as either good, not so good or worthless.
Concept introduction: Bimolecular substitution or
A general

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Chapter 8 Solutions
EBK STUDY GUIDE/SOLUTIONS MANUAL FOR OR
- N Classify each of the following molecules as aromatic, antiaromatic, or nonaromatic. NH O aromatic O antiaromatic O nonaromatic O aromatic O antiaromatic O nonaromatic O aromatic O antiaromatic O nonaromatic Garrow_forwardThe conjugate base of alkanes is called alkides. Correct?.arrow_forwardName these organic compounds: structure Br name CH3 CH3 ☐ ☐arrow_forward
- HH H-C H -C-H HH Draw the Skeletal Structures & H Name the molecules HH H H H H-C-C-C-C-C-C-H HHH HHH H H HHHHHHH H-C-C-C-C-C-C-C-C-C-H HHHHH H H H Harrow_forwarddont provide AI solution .... otherwise i will give you dislikearrow_forwardName these organic compounds: structure name CH3 CH3 ☐ F F CH3 ☐ O Explanation Check 2025 McGraw Hill LLC. All Rights Reserved. Terms ofarrow_forward
- Classify each of the following molecules as aromatic, antiaromatic, or nonaromatic. ZI NH Explanation Check O aromatic O antiaromatic O nonaromatic O aromatic O antiaromatic H O nonaromatic O aromatic O antiaromatic O nonaromatic ×arrow_forwardPart I. Draw the stepwise reaction mechanism of each product (a, b, c, d, e, f) HO HO OH НОН,С HO OH Sucrose HO CH₂OH H N N HO -H H -OH KMnO4, Heat H OH CH₂OH (d) Phenyl Osatriazole OH НОН,С HO HO + Glacial HOAC HO- HO CH₂OH OH HO Fructose (a) Glucose OH (b) H₂N HN (c) CuSO4-5H2O, ethanol H N N N HO ·H H OH H OH N CH₂OH OH (f) Phenyl Osazone H (e) Carboxy phenyl osatriazole Figure 2.1. Reaction Scheme for the Total Synthesis of Fine Chemicalsarrow_forwardWhich molecule is the most stable? Please explain.arrow_forward
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