Chapter 8, Problem 156CP

Interpretation Introduction

Interpretation: The mole fractions of $\text{CO}$, ${\text{CO}}_2$ and ${\text{O}}_2$ in the final mixture of given reaction mixture containing $\text{5}\text{mol}$ graphite and $\text{5}\text{mol}$ ${\text{O}}_2$ should be determined if the pressure of cylinder is increased by 17% after reaction at constant temperature.

Concept introduction:

• Balanced equation of a reaction is written according to law of conservation of mass.

• According toideal gas law: the pressure of gas is directly proportional to the number of moles of gas at constant volume and temperature.

$\frac{\text{P}}{\text{n}}\text{=}\frac{\text{RT}}{\text{V}}$ , P and n are proportional.

• Mole ratios between the reactant and products of a reaction are depends upon the coefficients of respective reactant in a balanced chemical equation.

• Equation for mole fraction of a molecule in a mixture of three molecules (A, B and C) is,

• $\text{molecule}\text{fraction}\text{of}\text{A,}\text{(}{\text{χ}}_{\text{A}}\text{) }\text{=}\frac{\text{numbers}\text{of moles of}\text{molecule A}{\text{(n}}_{\text{A}}\text{)}}{\text{total number of moles}{\text{(n}}_{\text{A}}{\text{+n}}_{\text{B}}{\text{+n}}_{\text{C}}\text{) }}$

• Partial pressure of a gas in a mixture of gases is the pressure of that gas when it alone.

To determine: The mole fractions of $\text{CO}$, ${\text{CO}}_2$ and ${\text{O}}_2$ in the final mixture of given reaction mixture containing $\text{5}\text{mol}$ graphite and $\text{5}\text{mol}$ ${\text{O}}_2$.