From the given rate of effusion of two gases, molar mass of the unknown gas should be determined. Concept introduction: Effusion is used to describe the passage of a gas through a tiny particle into an evacuated chamber. The rate of effusion is the measure speed at which the gas is transferred to the chamber. According to Thomas Graham the rate of effusion of a gas is inversely proportional to the square root of the mass of its particles. The relative rate of effusion of two gases at the same temperature and pressure are the inverse ratio of the square root of the masses of the gases particles. That is, R a t e o f e f f u s i o n f o r g a s 1 R a t e o f e f f u s i o n f o r g a s 2 = M 2 M 1 o r R a t e 1 R a t e 2 = ( M 2 M 1 ) 1 / 2 M 1 and M 2 are the molar masses of twogases This equation is known as Graham’s law of effusion.

Question

b) Certain cyclic compounds are known to be conformationally similar to carbohydrates, although they are not themselves carbohydrates. One example is Compound C shown below, which could be imagined as adopting four possible conformations. In reality, however, only one of these is particularly stable. Circle the conformation you expect to be the most stable, and provide an explanation to justify your choice. For your explanation to be both convincing and correct, it must contain not only words, but also "cartoon" orbital drawings contrasting the four structures. Compound C Possible conformations (circle one): Дет

Answer 1

Question

Chapter 8, Problem 112E

Interpretation Introduction

Interpretation: From the given rate of effusion of two gases, molar mass of the unknown gas should be determined.

Concept introduction:

Effusion is used to describe the passage of a gas through a tiny particle into an evacuated chamber.

The rate of effusion is the measure speed at which the gas is transferred to the chamber.

According to Thomas Graham the rate of effusion of a gas is inversely proportional to the square root of the mass of its particles.

The relative rate of effusion of two gases at the same temperature and pressure are the inverse ratio of the square root of the masses of the gases particles. That is,

Rate of effusion for gas 1Rate of effusion for gas 2 =M2M1orRate1Rate2 = (M2M1)1/2

M1 and M2 are the molar masses of twogases

This equation is known as Graham’s law of effusion.

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