To solve The system of linear equations by using the Cramer’s rule.
The system of equations have No solution .
Given information:
The given system of equations are { 3 x + 2 y = − 2 6 x + 4 y = 4 .
Formula used:
If { a 1 x + b 1 y = c 1 a 2 x + b 2 y = c 2 represents the system of equations then the value of x and y are calculated as x = c 1 b 2 − c 2 b 1 a 1 b 2 − a 2 b 1 = | c 1 b 1 c 2 b 2 | | a 1 b 1 a 2 b 2 | and y = a 1 c 2 − a 2 c 1 a 1 b 2 − a 2 b 1 = | a 1 c 1 a 2 c 2 | | a 1 b 1 a 2 b 2 | .
Calculation:
Compute the determinant of the matrix as follows,
D = [ 3 2 6 4 ] = ( 3 ) ( 4 ) − ( 2 ) ( 6 ) = 12 − 12 = 0
As the determinant of the equation iszero, so the solution of the equations does not exists.
Thus, the system of linear equations has no solutions.
The system of equations have
Given information:
The given system of equations are
Formula used:
If
Calculation:
Compute the determinant of the matrix as follows,
As the determinant of the equation iszero, so the solution of the equations does not exists.
Thus, the system of linear equations has no solutions.

Answer to Problem 24E
The system of equations have
Explanation of Solution
Given information:
The given system of equations are
Formula used:
If
Calculation:
Compute the determinant of the matrix as follows,
As the determinant of the equation iszero, so the solution of the equations does not exists.
Thus, the system of linear equations has no solutions.
Chapter 7 Solutions
PRECALCULUS W/LIMITS:GRAPH.APPROACH(HS)
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