a. Answer The sum is A + B = [ 9 5 1 − 2 − 3 15 ] . Explanation Given information: The matrices are, A = [ 8 − 1 2 3 − 4 5 ] and B = [ 1 6 − 1 − 5 1 10 ] . Concept used: Operations like addition and subtraction of matrices are only possible when they are of same dimension. Dimension of matrix with a rows and b columns is given by a × b . If a matrix is multiplied by a scalar then each element of the matrix is multiplied by the same scalar. Calculation: The sum of both matrices is, A + B = [ 8 − 1 2 3 − 4 5 ] + [ 1 6 − 1 − 5 1 10 ] A + B = [ 8 + 1 − 1 + 6 2 − 1 3 − 5 − 4 + 1 5 + 10 ] A + B = [ 9 5 1 − 2 − 3 15 ] Now, by graphing utility of matrix capability, Hence, the result is verified. b. To determine To find A − B . Answer The differenceis A − B = [ 7 − 7 3 8 − 5 − 5 ] . Explanation Given information: The matrices are, A = [ 8 − 1 2 3 − 4 5 ] and B = [ 1 6 − 1 − 5 1 10 ] Concept used: Operations like addition and subtraction of matrices are only possible when they are of same dimension. Dimension of matrix with a rows and b columns is given by a × b . If a matrix is multiplied by a scalar then each element of the matrix is multiplied by the same scalar. Calculation: The difference of both matrices is, A − B = [ 8 − 1 2 3 − 4 5 ] − [ 1 6 − 1 − 5 1 10 ] A − B = [ 8 − 1 − 1 − 6 2 − ( − 1 ) 3 − ( − 5 ) − 4 − 1 5 − 10 ] A − B = [ 7 − 7 2 + 1 3 + 5 − 5 − 5 ] A − B = [ 7 − 7 3 8 − 5 − 5 ] Now, by graphing utility of matrix capability, Hence, the result is verified. c. To determine To find 3 A . Answer 3 A = [ 24 − 3 6 9 − 12 15 ] . Explanation Given information: The matrices are, A = [ 8 − 1 2 3 − 4 5 ] and B = [ 1 6 − 1 − 5 1 10 ] . Concept used: Operations like addition and subtraction of matrices are only possible when they are of same dimension. Dimension of matrix with a rows and b columns is given by a × b . If a matrix is multiplied by a scalar then each element of the matrix is multiplied by the same scalar. Calculation: 3 A = 3 [ 8 − 1 2 3 − 4 5 ] 3 A = [ 8 ( 3 ) − 1 ( 3 ) 2 ( 3 ) 3 ( 3 ) − 4 ( 3 ) 5 ( 3 ) ] 3 A = [ 24 − 3 6 9 − 12 15 ] Now, by graphing utility of matrix capability, Hence, the result is verified. d. To determine To find 3 A − 2 B . Answer The differenceis 3 A − 2 B = [ 22 − 15 8 19 − 10 − 5 ] . Explanation Given information: The matrices are, A = [ 8 − 1 2 3 − 4 5 ] and B = [ 1 6 − 1 − 5 1 10 ] Concept used: Operations like addition and subtraction of matrices are only possible when they are of same dimension. Dimension of matrix with a rows and b columns is given by a × b . If a matrix is multiplied by a scalar then each element of the matrix is multiplied by the same scalar. Calculation: The difference is, 3 A − 2 B = 3 [ 8 − 1 2 3 − 4 5 ] − 2 [ 1 6 − 1 − 5 1 10 ] 3 A − 2 B = [ 8 ( 3 ) − 1 ( 3 ) 2 ( 3 ) 3 ( 3 ) − 4 ( 3 ) 5 ( 3 ) ] − [ 1 ( 2 ) 6 ( 2 ) − 1 ( 2 ) − 5 ( 2 ) 1 ( 2 ) 10 ( 2 ) ] 3 A − 2 B = [ 24 − 3 6 9 − 12 15 ] − [ 2 12 − 2 − 10 2 20 ] 3 A − 2 B = [ 24 − 2 − 3 − 12 6 − ( − 2 ) 9 − ( − 10 ) − 12 − 2 15 − 20 ] 3 A − 2 B = [ 22 − 15 6 + 2 9 + 10 − 10 − 5 ] 3 A − 2 B = [ 22 − 15 8 19 − 10 − 5 ] Now, by graphing utility of matrix capability, Hence, the result is verified.

8th Edition

ISBN: 9781337904285

Author: Larson

Publisher: CENGAGE L

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Question

Chapter 7.5, Problem 15E

To determine

To find A+B .

Expert Solution

Answer to Problem 15E

The sum is A+B=[951−2−315] .

Explanation of Solution

Given information:

The matrices are,

A=[8−123−45] and B=[16−1−5110] .

Concept used:

Operations like addition and subtraction of matrices are only possible when they are of same dimension.

Dimension of matrix with a rows and b columns is given by a×b .

If a matrix is multiplied by a scalar then each element of the matrix is multiplied by the same scalar.

Calculation:

The sum of both matrices is,

A+B=[8−123−45] +[16−1−5110]A+B=[8+1−1+62−13−5−4+15+10]A+B=[951−2−315]

Now, by graphing utility of matrix capability,

PRECALCULUS W/LIMITS:GRAPH.APPROACH(HS), Chapter 7.5, Problem 15E , additional homework tip 1

Hence, the result is verified.

To determine

To find A−B .

Expert Solution

Answer to Problem 15E

The differenceis A−B=[7−738−5−5] .

Explanation of Solution

Given information:

The matrices are,

A=[8−123−45] and B=[16−1−5110]

Concept used:

Operations like addition and subtraction of matrices are only possible when they are of same dimension.

Dimension of matrix with a rows and b columns is given by a×b .

If a matrix is multiplied by a scalar then each element of the matrix is multiplied by the same scalar.

Calculation:

The difference of both matrices is,

A−B=[8−123−45] −[16−1−5110]A−B=[8−1−1−62−(−1)3−(−5)−4−15−10]A−B=[7−72+13+5−5−5]A−B=[7−738−5−5]

Now, by graphing utility of matrix capability,

PRECALCULUS W/LIMITS:GRAPH.APPROACH(HS), Chapter 7.5, Problem 15E , additional homework tip 2

Hence, the result is verified.

To determine

To find 3A .

Expert Solution

Answer to Problem 15E

3A=[24−369−1215] .

Explanation of Solution

Given information:

The matrices are,

A=[8−123−45] and B=[16−1−5110] .

Concept used:

Operations like addition and subtraction of matrices are only possible when they are of same dimension.

Dimension of matrix with a rows and b columns is given by a×b .

If a matrix is multiplied by a scalar then each element of the matrix is multiplied by the same scalar.

Calculation:

3A=3[8−123−45]3A=[8(3)−1(3)2(3)3(3)−4(3)5(3)]3A=[24−369−1215]

Now, by graphing utility of matrix capability,

PRECALCULUS W/LIMITS:GRAPH.APPROACH(HS), Chapter 7.5, Problem 15E , additional homework tip 3

Hence, the result is verified.

To determine

To find 3A−2B .

Expert Solution

Answer to Problem 15E

The differenceis 3A−2B=[22−15819−10−5] .

Explanation of Solution

Given information:

The matrices are,

A=[8−123−45] and B=[16−1−5110]

Concept used:

Operations like addition and subtraction of matrices are only possible when they are of same dimension.

Dimension of matrix with a rows and b columns is given by a×b .

If a matrix is multiplied by a scalar then each element of the matrix is multiplied by the same scalar.

Calculation:

The difference is,

3A−2B=3[8−123−45] −2[16−1−5110]3A−2B=[8(3)−1(3)2(3)3(3)−4(3)5(3)]−[1(2)6(2)−1(2)−5(2)1(2)10(2)]3A−2B=[24−369−1215]−[212−2−10220]3A−2B=[24−2−3−126−(−2)9−(−10)−12−215−20]3A−2B=[22−156+29+10−10−5]3A−2B=[22−15819−10−5]

Now, by graphing utility of matrix capability,

PRECALCULUS W/LIMITS:GRAPH.APPROACH(HS), Chapter 7.5, Problem 15E , additional homework tip 4

Hence, the result is verified.

Chapter 7.5, Problem 14E

Chapter 7.5, Problem 16E

Chapter 7 Solutions

PRECALCULUS W/LIMITS:GRAPH.APPROACH(HS)

Ch. 7.1 - Prob. 1E Ch. 7.1 - Prob. 2E Ch. 7.1 - Prob. 3E Ch. 7.1 - Prob. 4E Ch. 7.1 - Prob. 5E Ch. 7.1 - Prob. 6E Ch. 7.1 - Prob. 7E Ch. 7.1 - Prob. 8E Ch. 7.1 - Prob. 9E Ch. 7.1 - Prob. 10E

Ch. 7.1 - Prob. 11E Ch. 7.1 - Prob. 12E Ch. 7.1 - Prob. 13E Ch. 7.1 - Prob. 14E Ch. 7.1 - Prob. 15E Ch. 7.1 - Prob. 16E Ch. 7.1 - Prob. 17E Ch. 7.1 - Prob. 18E Ch. 7.1 - Prob. 19E Ch. 7.1 - Prob. 20E Ch. 7.1 - Prob. 21E Ch. 7.1 - Prob. 22E Ch. 7.1 - Prob. 23E Ch. 7.1 - Prob. 24E Ch. 7.1 - Prob. 25E Ch. 7.1 - Prob. 26E Ch. 7.1 - Prob. 27E Ch. 7.1 - Prob. 28E Ch. 7.1 - Prob. 29E Ch. 7.1 - Prob. 30E Ch. 7.1 - Prob. 31E Ch. 7.1 - Prob. 32E Ch. 7.1 - Prob. 33E Ch. 7.1 - Prob. 34E Ch. 7.1 - Prob. 35E Ch. 7.1 - Prob. 36E Ch. 7.1 - Prob. 37E Ch. 7.1 - Prob. 38E Ch. 7.1 - Prob. 39E Ch. 7.1 - Prob. 40E Ch. 7.1 - Prob. 41E Ch. 7.1 - Prob. 42E Ch. 7.1 - Prob. 43E Ch. 7.1 - Prob. 44E Ch. 7.1 - Prob. 45E Ch. 7.1 - Prob. 46E Ch. 7.1 - Prob. 47E Ch. 7.1 - Prob. 48E Ch. 7.1 - Prob. 49E Ch. 7.1 - Prob. 50E Ch. 7.1 - Prob. 51E Ch. 7.1 - Prob. 52E Ch. 7.1 - Prob. 53E Ch. 7.1 - Prob. 54E Ch. 7.1 - Prob. 55E Ch. 7.1 - Prob. 56E Ch. 7.1 - Prob. 57E Ch. 7.1 - Prob. 58E Ch. 7.1 - Prob. 59E Ch. 7.1 - Prob. 60E Ch. 7.1 - 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Prob. 27E Ch. 7.5 - Prob. 28E Ch. 7.5 - Prob. 29E Ch. 7.5 - Prob. 30E Ch. 7.5 - Prob. 31E Ch. 7.5 - Prob. 32E Ch. 7.5 - Prob. 33E Ch. 7.5 - Prob. 34E Ch. 7.5 - Prob. 35E Ch. 7.5 - Prob. 36E Ch. 7.5 - Prob. 37E Ch. 7.5 - Prob. 38E Ch. 7.5 - Prob. 39E Ch. 7.5 - Prob. 40E Ch. 7.5 - Prob. 41E Ch. 7.5 - Prob. 42E Ch. 7.5 - Prob. 43E Ch. 7.5 - Prob. 44E Ch. 7.5 - Prob. 45E Ch. 7.5 - Prob. 46E Ch. 7.5 - Prob. 47E Ch. 7.5 - Prob. 48E Ch. 7.5 - Prob. 49E Ch. 7.5 - Prob. 50E Ch. 7.5 - Prob. 51E Ch. 7.5 - Prob. 52E Ch. 7.5 - Prob. 53E Ch. 7.5 - Prob. 54E Ch. 7.5 - Prob. 55E Ch. 7.5 - Prob. 56E Ch. 7.5 - Prob. 57E Ch. 7.5 - Prob. 58E Ch. 7.5 - Prob. 59E Ch. 7.5 - Prob. 60E Ch. 7.5 - Prob. 61E Ch. 7.5 - Prob. 62E Ch. 7.5 - Prob. 63E Ch. 7.5 - Prob. 64E Ch. 7.5 - Prob. 65E Ch. 7.5 - Prob. 66E Ch. 7.5 - Prob. 67E Ch. 7.5 - Prob. 68E Ch. 7.5 - Prob. 69E Ch. 7.5 - Prob. 70E Ch. 7.5 - Prob. 71E Ch. 7.5 - Prob. 72E Ch. 7.5 - Prob. 73E Ch. 7.5 - Prob. 74E Ch. 7.5 - Prob. 75E Ch. 7.5 - Prob. 76E Ch. 7.5 - Prob. 77E Ch. 7.5 - Prob. 78E Ch. 7.5 - Prob. 79E Ch. 7.5 - Prob. 80E Ch. 7.5 - Prob. 81E Ch. 7.5 - Prob. 82E Ch. 7.5 - Prob. 83E Ch. 7.5 - Prob. 84E Ch. 7.5 - Prob. 85E Ch. 7.5 - Prob. 86E Ch. 7.5 - Prob. 87E Ch. 7.5 - Prob. 88E Ch. 7.5 - Prob. 89E Ch. 7.5 - Prob. 90E Ch. 7.5 - Prob. 91E Ch. 7.5 - Prob. 92E Ch. 7.5 - Prob. 93E Ch. 7.5 - Prob. 94E Ch. 7.5 - Prob. 95E Ch. 7.5 - Prob. 96E Ch. 7.5 - Prob. 97E Ch. 7.5 - Prob. 98E Ch. 7.5 - Prob. 99E Ch. 7.5 - Prob. 100E Ch. 7.5 - Prob. 101E Ch. 7.5 - Prob. 102E Ch. 7.5 - Prob. 103E Ch. 7.5 - Prob. 104E Ch. 7.5 - Prob. 105E Ch. 7.5 - Prob. 106E Ch. 7.5 - Prob. 107E Ch. 7.5 - Prob. 108E Ch. 7.5 - Prob. 109E Ch. 7.5 - Prob. 110E Ch. 7.5 - Prob. 111E Ch. 7.5 - Prob. 112E Ch. 7.5 - Prob. 113E Ch. 7.5 - Prob. 114E Ch. 7.5 - Prob. 115E Ch. 7.5 - Prob. 116E Ch. 7.5 - Prob. 117E Ch. 7.5 - Prob. 118E Ch. 7.5 - Prob. 119E Ch. 7.5 - Prob. 120E Ch. 7.6 - Prob. 1E Ch. 7.6 - Prob. 2E Ch. 7.6 - Prob. 3E Ch. 7.6 - Prob. 4E Ch. 7.6 - Prob. 5E Ch. 7.6 - Prob. 6E Ch. 7.6 - Prob. 7E Ch. 7.6 - Prob. 8E Ch. 7.6 - Prob. 9E Ch. 7.6 - Prob. 10E Ch. 7.6 - Prob. 11E Ch. 7.6 - Prob. 12E Ch. 7.6 - Prob. 13E Ch. 7.6 - Prob. 14E Ch. 7.6 - Prob. 15E Ch. 7.6 - Prob. 16E Ch. 7.6 - Prob. 17E Ch. 7.6 - Prob. 18E Ch. 7.6 - Prob. 19E Ch. 7.6 - Prob. 20E Ch. 7.6 - Prob. 21E Ch. 7.6 - Prob. 22E Ch. 7.6 - Prob. 23E Ch. 7.6 - Prob. 24E Ch. 7.6 - Prob. 25E Ch. 7.6 - Prob. 26E Ch. 7.6 - Prob. 27E Ch. 7.6 - Prob. 28E Ch. 7.6 - Prob. 29E Ch. 7.6 - Prob. 30E Ch. 7.6 - Prob. 31E Ch. 7.6 - Prob. 32E Ch. 7.6 - Prob. 33E Ch. 7.6 - Prob. 34E Ch. 7.6 - Prob. 35E Ch. 7.6 - Prob. 36E Ch. 7.6 - Prob. 37E Ch. 7.6 - Prob. 38E Ch. 7.6 - Prob. 39E Ch. 7.6 - Prob. 40E Ch. 7.6 - Prob. 41E Ch. 7.6 - Prob. 42E Ch. 7.6 - Prob. 43E Ch. 7.6 - Prob. 44E Ch. 7.6 - Prob. 45E Ch. 7.6 - Prob. 46E Ch. 7.6 - Prob. 47E Ch. 7.6 - Prob. 48E Ch. 7.6 - Prob. 49E Ch. 7.6 - Prob. 50E Ch. 7.6 - Prob. 51E Ch. 7.6 - Prob. 52E Ch. 7.6 - Prob. 53E Ch. 7.6 - Prob. 54E Ch. 7.6 - Prob. 55E Ch. 7.6 - Prob. 56E Ch. 7.6 - Prob. 57E Ch. 7.6 - Prob. 58E Ch. 7.6 - Prob. 59E Ch. 7.6 - Prob. 60E Ch. 7.6 - Prob. 61E Ch. 7.6 - Prob. 62E Ch. 7.6 - Prob. 64E Ch. 7.6 - Prob. 65E Ch. 7.6 - Prob. 66E Ch. 7.6 - Prob. 67E Ch. 7.6 - Prob. 68E Ch. 7.6 - Prob. 69E Ch. 7.6 - Prob. 70E Ch. 7.6 - Prob. 71E Ch. 7.6 - Prob. 72E Ch. 7.6 - Prob. 73E Ch. 7.6 - Prob. 74E Ch. 7.6 - Prob. 75E Ch. 7.6 - Prob. 76E Ch. 7.7 - Prob. 1E Ch. 7.7 - Prob. 2E Ch. 7.7 - Prob. 3E Ch. 7.7 - Prob. 4E Ch. 7.7 - Prob. 5E Ch. 7.7 - Prob. 6E Ch. 7.7 - Prob. 7E Ch. 7.7 - Prob. 8E Ch. 7.7 - Prob. 9E Ch. 7.7 - Prob. 10E Ch. 7.7 - Prob. 11E Ch. 7.7 - Prob. 12E Ch. 7.7 - Prob. 13E Ch. 7.7 - Prob. 14E Ch. 7.7 - Prob. 15E Ch. 7.7 - Prob. 16E Ch. 7.7 - Prob. 17E Ch. 7.7 - Prob. 18E Ch. 7.7 - Prob. 19E Ch. 7.7 - Prob. 20E Ch. 7.7 - Prob. 21E Ch. 7.7 - Prob. 22E Ch. 7.7 - Prob. 23E Ch. 7.7 - Prob. 24E Ch. 7.7 - Prob. 25E Ch. 7.7 - Prob. 26E Ch. 7.7 - Prob. 27E Ch. 7.7 - Prob. 28E Ch. 7.7 - Prob. 29E Ch. 7.7 - Prob. 30E Ch. 7.7 - Prob. 31E Ch. 7.7 - Prob. 32E Ch. 7.7 - Prob. 33E Ch. 7.7 - Prob. 34E Ch. 7.7 - Prob. 35E Ch. 7.7 - Prob. 36E Ch. 7.7 - Prob. 37E Ch. 7.7 - Prob. 38E Ch. 7.7 - Prob. 39E Ch. 7.7 - Prob. 40E Ch. 7.7 - Prob. 41E Ch. 7.7 - Prob. 42E Ch. 7.7 - Prob. 43E Ch. 7.7 - Prob. 44E Ch. 7.7 - Prob. 45E Ch. 7.7 - Prob. 46E Ch. 7.7 - Prob. 47E Ch. 7.7 - Prob. 48E Ch. 7.7 - Prob. 49E Ch. 7.7 - Prob. 50E Ch. 7.7 - Prob. 51E Ch. 7.7 - Prob. 52E Ch. 7.7 - Prob. 53E Ch. 7.7 - Prob. 54E Ch. 7.7 - Prob. 55E Ch. 7.7 - Prob. 56E Ch. 7.7 - Prob. 57E Ch. 7.7 - Prob. 58E Ch. 7.7 - Prob. 59E Ch. 7.7 - Prob. 60E Ch. 7.7 - Prob. 61E Ch. 7.7 - Prob. 62E Ch. 7.7 - Prob. 63E Ch. 7.7 - Prob. 64E Ch. 7.7 - Prob. 65E Ch. 7.7 - Prob. 66E Ch. 7.7 - Prob. 67E Ch. 7.7 - Prob. 68E Ch. 7.7 - Prob. 69E Ch. 7.7 - Prob. 70E Ch. 7.7 - Prob. 71E Ch. 7.7 - Prob. 72E Ch. 7.7 - Prob. 73E Ch. 7.7 - Prob. 74E Ch. 7.7 - Prob. 75E Ch. 7.7 - Prob. 76E Ch. 7.7 - Prob. 77E Ch. 7.7 - Prob. 78E Ch. 7.7 - Prob. 79E Ch. 7.7 - Prob. 80E Ch. 7.7 - Prob. 81E Ch. 7.7 - Prob. 82E Ch. 7.7 - Prob. 83E Ch. 7.7 - Prob. 84E Ch. 7.7 - Prob. 85E Ch. 7.7 - Prob. 86E Ch. 7.7 - Prob. 87E Ch. 7.7 - Prob. 88E Ch. 7.8 - Prob. 1E Ch. 7.8 - Prob. 2E Ch. 7.8 - Prob. 3E Ch. 7.8 - Prob. 4E Ch. 7.8 - Prob. 5E Ch. 7.8 - Prob. 6E Ch. 7.8 - Prob. 7E Ch. 7.8 - Prob. 8E Ch. 7.8 - Prob. 9E Ch. 7.8 - Prob. 10E Ch. 7.8 - Prob. 11E Ch. 7.8 - Prob. 12E Ch. 7.8 - Prob. 13E Ch. 7.8 - Prob. 14E Ch. 7.8 - Prob. 15E Ch. 7.8 - Prob. 16E Ch. 7.8 - Prob. 17E Ch. 7.8 - Prob. 18E Ch. 7.8 - Prob. 19E Ch. 7.8 - Prob. 20E Ch. 7.8 - Prob. 21E Ch. 7.8 - Prob. 22E Ch. 7.8 - Prob. 23E Ch. 7.8 - Prob. 24E Ch. 7.8 - Prob. 25E Ch. 7.8 - Prob. 26E Ch. 7.8 - Prob. 27E Ch. 7.8 - Prob. 28E Ch. 7.8 - Prob. 29E Ch. 7.8 - Prob. 30E Ch. 7.8 - Prob. 31E Ch. 7.8 - Prob. 32E Ch. 7.8 - Prob. 33E Ch. 7.8 - Prob. 34E Ch. 7.8 - Prob. 35E Ch. 7.8 - Prob. 36E Ch. 7.8 - Prob. 41E Ch. 7.8 - Prob. 42E Ch. 7.8 - Prob. 43E Ch. 7.8 - Prob. 44E Ch. 7.8 - Prob. 45E Ch. 7.8 - Prob. 46E Ch. 7.8 - Prob. 47E Ch. 7.8 - Prob. 48E Ch. 7 - Prob. 1CR Ch. 7 - Prob. 2CR Ch. 7 - Prob. 3CR Ch. 7 - Prob. 4CR Ch. 7 - Prob. 5CR Ch. 7 - Prob. 6CR Ch. 7 - Prob. 7CR Ch. 7 - Prob. 8CR Ch. 7 - Prob. 9CR Ch. 7 - Prob. 10CR Ch. 7 - Prob. 11CR Ch. 7 - Prob. 12CR Ch. 7 - Prob. 13CR Ch. 7 - Prob. 14CR Ch. 7 - Prob. 15CR Ch. 7 - Prob. 16CR Ch. 7 - Prob. 17CR Ch. 7 - Prob. 18CR Ch. 7 - Prob. 19CR Ch. 7 - Prob. 20CR Ch. 7 - Prob. 21CR Ch. 7 - Prob. 22CR Ch. 7 - Prob. 23CR Ch. 7 - Prob. 24CR Ch. 7 - Prob. 25CR Ch. 7 - Prob. 26CR Ch. 7 - Prob. 27CR Ch. 7 - Prob. 28CR Ch. 7 - Prob. 29CR Ch. 7 - Prob. 30CR Ch. 7 - Prob. 31CR Ch. 7 - Prob. 32CR Ch. 7 - Prob. 33CR Ch. 7 - Prob. 34CR Ch. 7 - Prob. 35CR Ch. 7 - Prob. 36CR Ch. 7 - Prob. 37CR Ch. 7 - Prob. 38CR Ch. 7 - Prob. 39CR Ch. 7 - Prob. 40CR Ch. 7 - Prob. 41CR Ch. 7 - Prob. 42CR Ch. 7 - Prob. 43CR Ch. 7 - Prob. 44CR Ch. 7 - Prob. 45CR Ch. 7 - Prob. 46CR Ch. 7 - Prob. 47CR Ch. 7 - Prob. 48CR Ch. 7 - Prob. 49CR Ch. 7 - Prob. 50CR Ch. 7 - Prob. 51CR Ch. 7 - Prob. 52CR Ch. 7 - Prob. 53CR Ch. 7 - Prob. 54CR Ch. 7 - Prob. 55CR Ch. 7 - Prob. 56CR Ch. 7 - Prob. 57CR Ch. 7 - Prob. 58CR Ch. 7 - Prob. 59CR Ch. 7 - Prob. 60CR Ch. 7 - Prob. 61CR Ch. 7 - Prob. 62CR Ch. 7 - Prob. 63CR Ch. 7 - Prob. 64CR Ch. 7 - Prob. 65CR Ch. 7 - Prob. 66CR Ch. 7 - Prob. 67CR Ch. 7 - Prob. 68CR Ch. 7 - Prob. 69CR Ch. 7 - Prob. 70CR Ch. 7 - Prob. 71CR Ch. 7 - Prob. 72CR Ch. 7 - Prob. 73CR Ch. 7 - Prob. 74CR Ch. 7 - Prob. 75CR Ch. 7 - Prob. 76CR Ch. 7 - Prob. 77CR Ch. 7 - Prob. 78CR Ch. 7 - Prob. 79CR Ch. 7 - Prob. 80CR Ch. 7 - Prob. 81CR Ch. 7 - Prob. 82CR Ch. 7 - Prob. 83CR Ch. 7 - Prob. 84CR Ch. 7 - Prob. 85CR Ch. 7 - Prob. 86CR Ch. 7 - Prob. 87CR Ch. 7 - Prob. 88CR Ch. 7 - Prob. 89CR Ch. 7 - Prob. 90CR Ch. 7 - Prob. 91CR Ch. 7 - Prob. 92CR Ch. 7 - Prob. 93CR Ch. 7 - Prob. 94CR Ch. 7 - Prob. 95CR Ch. 7 - Prob. 96CR Ch. 7 - Prob. 97CR Ch. 7 - Prob. 98CR Ch. 7 - Prob. 99CR Ch. 7 - Prob. 100CR Ch. 7 - Prob. 101CR Ch. 7 - Prob. 102CR Ch. 7 - Prob. 103CR Ch. 7 - Prob. 104CR Ch. 7 - Prob. 105CR Ch. 7 - Prob. 106CR Ch. 7 - Prob. 107CR Ch. 7 - Prob. 108CR Ch. 7 - Prob. 109CR Ch. 7 - Prob. 110CR Ch. 7 - Prob. 111CR Ch. 7 - Prob. 112CR Ch. 7 - Prob. 113CR Ch. 7 - Prob. 114CR Ch. 7 - Prob. 115CR Ch. 7 - Prob. 116CR Ch. 7 - Prob. 117CR Ch. 7 - Prob. 118CR Ch. 7 - Prob. 119CR Ch. 7 - Prob. 120CR Ch. 7 - Prob. 121CR Ch. 7 - Prob. 122CR Ch. 7 - Prob. 123CR Ch. 7 - Prob. 124CR Ch. 7 - Prob. 125CR Ch. 7 - Prob. 126CR Ch. 7 - Prob. 127CR Ch. 7 - Prob. 128CR Ch. 7 - Prob. 129CR Ch. 7 - Prob. 130CR Ch. 7 - Prob. 131CR Ch. 7 - Prob. 132CR Ch. 7 - Prob. 133CR Ch. 7 - Prob. 134CR Ch. 7 - Prob. 135CR Ch. 7 - Prob. 136CR Ch. 7 - Prob. 137CR Ch. 7 - Prob. 138CR Ch. 7 - Prob. 139CR Ch. 7 - Prob. 140CR Ch. 7 - Prob. 141CR Ch. 7 - Prob. 1CT Ch. 7 - Prob. 2CT Ch. 7 - Prob. 3CT Ch. 7 - Prob. 4CT Ch. 7 - Prob. 5CT Ch. 7 - Prob. 6CT Ch. 7 - Prob. 7CT Ch. 7 - Prob. 8CT Ch. 7 - Prob. 9CT Ch. 7 - Prob. 10CT Ch. 7 - Prob. 11CT Ch. 7 - Prob. 12CT Ch. 7 - Prob. 13CT Ch. 7 - Prob. 14CT Ch. 7 - Prob. 15CT Ch. 7 - Prob. 16CT Ch. 7 - Prob. 17CT

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