Concept explainers
(a)
Interpretation:
For the given IUPAC name of the compound, bond-line structure has to be drawn and identified.
Concept introduction:
Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry).IUPAC name consists of three parts in major namely Prefix suffix and root word.
Prefix represents the substituent present in the molecule and its position in the parent chain.
Suffix denotes the presence of
Root word represents the longest continuous carbon skeleton of the organic molecule.
The structure of a molecule can be drawn by analyzing the presence of prefix, suffix and root word in the given IUPAC name.
In bond-line structure the carbon atoms and the hydrogen atoms which are attached to that carbon atom are not to show, they are drawn as line segments. For acyclic carbon chains it draws as in a zig-zag fashion and for cyclic chains of carbon it draws as a cyclic polygon. For representing a heteroatom attached to the carbon, use a labelled line segment.
(b).
Interpretation:
For the given IUPAC name of the compound, bond-line structure has to be drawn and identified.
Concept introduction:
Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry).IUPAC name consists of three parts in major namely Prefix suffix and root word.
Prefix represents the substituent present in the molecule and its position in the parent chain.
Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc. The position of this fictional group is represented just before the root name.
Root word represents the longest continuous carbon skeleton of the organic molecule.
The structure of a molecule can be drawn by analyzing the presence of prefix, suffix and root word in the given IUPAC name.
In bond-line structure the carbon atoms and the hydrogen atoms which are attached to that carbon atom are not to show, they are drawn as line segments. For acyclic carbon chains it draws as in a zig-zag fashion and for cyclic chains of carbon it draws as a cyclic polygon. For representing a heteroatom attached to the carbon, use a labelled line segment.
(c).
Interpretation:
For the given IUPAC name of the compound, bond-line structure has to be drawn and identified.
Concept introduction:
Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry).IUPAC name consists of three parts in major namely Prefix suffix and root word.
Prefix represents the substituent present in the molecule and its position in the parent chain.
Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc. The position of this fictional group is represented just before the root name.
Root word represents the longest continuous carbon skeleton of the organic molecule.
The structure of a molecule can be drawn by analyzing the presence of prefix, suffix and root word in the given IUPAC name.
In bond-line structure the carbon atoms and the hydrogen atoms which are attached to that carbon atom are not to show, they are drawn as line segments. For acyclic carbon chains it draws as in a zig-zag fashion and for cyclic chains of carbon it draws as a cyclic polygon. For representing a heteroatom attached to the carbon, use a labelled line segment.

Want to see the full answer?
Check out a sample textbook solution
Chapter 7 Solutions
Organic Chemistry
- Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electrons-pushing arrows for the following reaction or mechanistic step(s).arrow_forwardCurved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s). Be sure to account for all bond-breaking and bond-making steps. I I I H Select to Add Arrows HCI, CH3CH2OHarrow_forwardCurved arrows are used to illustrate the flow of electrons. Use the reaction conditions provided and the follow the arrows to draw the intermediate and product in this reaction or mechanistic step(s).arrow_forward
- Curved arrows are used to illustrate the flow of electrons. Use the reaction conditions provided and follow the curved arrows to draw the intermediates and product of the following reaction or mechanistic step(s).arrow_forwardCurved arrows are used to illustrate the flow of electrons. Use the reaction conditions provided and follow the arrows to draw the intermediate and the product in this reaction or mechanistic step(s).arrow_forwardLook at the following pairs of structures carefully to identify them as representing a) completely different compounds, b) compounds that are structural isomers of each other, c) compounds that are geometric isomers of each other, d) conformers of the same compound (part of structure rotated around a single bond) or e) the same structure.arrow_forward
- Given 10.0 g of NaOH, what volume of a 0.100 M solution of H2SO4 would be required to exactly react all the NaOH?arrow_forward3.50 g of Li are combined with 3.50 g of N2. What is the maximum mass of Li3N that can be produced? 6 Li + N2 ---> 2 Li3Narrow_forward3.50 g of Li are combined with 3.50 g of N2. What is the maximum mass of Li3N that can be produced? 6 Li + N2 ---> 2 Li3Narrow_forward
- Concentration Trial1 Concentration of iodide solution (mA) 255.8 Concentration of thiosulfate solution (mM) 47.0 Concentration of hydrogen peroxide solution (mM) 110.1 Temperature of iodide solution ('C) 25.0 Volume of iodide solution (1) used (mL) 10.0 Volume of thiosulfate solution (5:03) used (mL) Volume of DI water used (mL) Volume of hydrogen peroxide solution (H₂O₂) used (mL) 1.0 2.5 7.5 Time (s) 16.9 Dark blue Observations Initial concentration of iodide in reaction (mA) Initial concentration of thiosulfate in reaction (mA) Initial concentration of hydrogen peroxide in reaction (mA) Initial Rate (mA's)arrow_forwardDraw the condensed or line-angle structure for an alkene with the formula C5H10. Note: Avoid selecting cis-/trans- isomers in this exercise. Draw two additional condensed or line-angle structures for alkenes with the formula C5H10. Record the name of the isomers in Data Table 1. Repeat steps for 2 cyclic isomers of C5H10arrow_forwardExplain why the following names of the structures are incorrect. CH2CH3 CH3-C=CH-CH2-CH3 a. 2-ethyl-2-pentene CH3 | CH3-CH-CH2-CH=CH2 b. 2-methyl-4-pentenearrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY





