Explanation Given information: The allowable shearing stress ( τ a l l ) parallel to the weld is 1 , 350 psi . The gage pressure in the tank is p = 85 psi . The outer diameter of the tank is d = 1.6 m Show the unit conversion of the diameter of the tank as follows: d = 1.6 m × ( 39.37 in . 1 m ) ≈ 60 in . The plate thickness of the tank is t = 0.375 in . Calculation: Calculate the inner radius of the tank ( r ) as shown below. r = d 2 − t (1) Substitute 60 in . for d and 0.375 in . for t in Equation (1). r = 60 in . 2 − 0.375 in . =30 − 0.375 = 29.625 in . Show the expression for hoop stress acting on the tank as shown below. σ 1 = p r t Substitute 85 psi for σ w and 29.625 in . for r , and 0.375 in . for t . σ 1 = 85 × 29.625 0.375 = 6715 psi Show the expression for longitudinal stress acting on the tank as shown below. σ 2 = p r 2 t Substitute 85 psi for σ w and 29.625 in . for r , and 0.375 in . for t . σ 2 = 85 × 29.625 2 × 0.375 = 3357.5 psi Consider the hoop stress and the longitudinal stress as the principal stress, draw the Mohr’s circle as shown in Figure 1. Refer Figure 1. Show the radius of the Mohr’s circle as shown in Figure 1. R = ( σ 1 − σ 2 2 ) Substitute 6715 psi for σ 1 and 3357.5 psi for σ 2 . R = 1 2 ( 6715 psi − 3357.5 psi ) = 3357.5 2 = 1678.75 psi Show the allowable shear stress to the weld as follows: τ a l l = τ w = R sin ( 2 β ) (2) Substitute 1678

7th Edition

ISBN: 8220100257063

Author: BEER

Publisher: YUZU

See similar textbooks

Concept explainers

Axial Load

When a bar of the uniform cross-section is acted by a load, such that the load acts along the longitudinal axis of the bar, such kinds of loadings are known as axial loadings. In general terms, a load is an external force acting on a component. An axial …

Videos

Question

Chapter 7.6, Problem 119P

To determine

Find the range of angle β such that the shearing stress parallel to the weld not to exceed 1,350 psi.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 7.6, Problem 118P

Chapter 7.6, Problem 120P

Students have asked these similar questions

A steel pipe of 400-mm outer diameter is fabricated from 10-mm-thick plate by welding along a helix that forms an angle of 20°with a plane perpendicular to the axis of the pipe. Knowing that the maximum allowable normal and shearing stresses in the directions respectively normal and tangential to the weld are σ = 60 MPa and τ = 36 MPa, determine the magnitude P of the largest axial force that can be applied to the pipe.

The steel pressure tank shown has a 750-mm inner diameter and a 9-mm wall thickness. Knowing that the butt-welded seams form an angle β= 50° with the longitudinal axis of the tank and that the gage pressure in the tank is 1.5 MPa, determine, (a) the normal stress per-pendicular to the weld, (b) the shearing stress parallel to the weld.

Chapter 7 Solutions

EBK MECHANICS OF MATERIALS

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.

Find the range of angle β such that the shearing stress parallel to the weld not to exceed 1 , 350 psi .

Solution Summary: The author calculates the range of angle beta such that the shearing stress parallel to the weld not exceed 1,350psi.

Concept explainers

Videos

Find the range of angle β such that the shearing stress parallel to the weld not to exceed 1,350 psi.

Want to see the full answer?

Chapter 7 Solutions