Using MIS (10th Edition)
10th Edition
ISBN: 9780134606996
Author: David M. Kroenke, Randall J. Boyle
Publisher: PEARSON
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Expert Solution & Answer
Chapter 7.4, Problem 3EGDQ
Explanation of Solution
Eric’s fraudulent behavior:
Eric, removing the matters on the Internet and doing illegal activities in search engine results for money is not an ethical act according to categorical imperative. If all the comments are taken off the Internet then, possibly there wouldn’t be any content on the Internet. Doing illegal activities in search engine results, is not a good universal law.
Categorical Imperative:
Categorical imperative signifies a complete requirement or a law that must be followed in all situations and is acceptable as an end in it.
Here, Eric’s behavior is considered to be ethical, if he is willing to publish his actions to the whole world and not few people. Hence, his behavior is not ethical.
Utilitarian perspective:
Utilitarianism is nothing, but a moral theory that states that the greatest act is the one that increases utility.
Eric’s manipulation brings more harm to the public, because they don’t get the consistent and correct information...
Expert Solution & Answer
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Students have asked these similar questions
Exercise 1 Function and Structure [30 pts]
Please debug the following program and answer the following questions. There is a cycle in a linked
list if some node in the list can be reached again by continuously following the next pointer.
#include
typedef struct node {
int value;
struct node *next;
} node;
int 11_has_cycle (node *first)
if (first
==
node *head
{
NULL) return 0;B
= first;
while (head->next != NULL) {
if (head == first) {
return 1; }
head
head->next;
}
return 0;
void test_11_has_cycle() {
int i;
node nodes [6];
for (i = 0; i < 6; i++)
nodes [i] .next = NULL;
nodes [i].value
i;
}
nodes [0] .next
=
&nodes [1];
nodes [1] .next = &nodes [2];
nodes [2] .next
=
&nodes [3];
nodes [3] .next = & nodes [4];
nodes [4] .next
=
NULL;
nodes [5] .next = &nodes [0];
printf("1. Checking first list for cycles. \n Function 11_has_cycle says it
hass cycle\n\n", 11_has_cycle (&nodes [0]) ?"a":"no");
printf("2. Checking length-zero list for cycles. \n Function 11_has_cycle
says it has %s…
checkpoint exercice for my students for Amortized Analysis
using r language
Chapter 7 Solutions
Using MIS (10th Edition)
Ch. 7.4 - Prob. 1WPQCh. 7.4 - Prob. 2WPQCh. 7.4 - Prob. 3WPQCh. 7.4 - Prob. 4WPQCh. 7.4 - Prob. 5WPQCh. 7.4 - Prob. 1EGDQCh. 7.4 - Prob. 2EGDQCh. 7.4 - Prob. 3EGDQCh. 7.4 - Prob. 4EGDQCh. 7.4 - Prob. 5EGDQ
Ch. 7.8 - Prob. 1SGDQCh. 7.8 - Prob. 2SGDQCh. 7.8 - Prob. 3SGDQCh. 7.8 - Prob. 4SGDQCh. 7.8 - Prob. 7.1ARQCh. 7.8 - Prob. 7.2ARQCh. 7.8 - Prob. 7.3ARQCh. 7.8 - Prob. 7.4ARQCh. 7.8 - Prob. 7.5ARQCh. 7.8 - Prob. 7.6ARQCh. 7.8 - Prob. 7.7ARQCh. 7.8 - Prob. 7.8ARQCh. 7 - Prob. 7.1UYKCh. 7 - Prob. 7.2UYKCh. 7 - Prob. 7.3UYKCh. 7 - Prob. 7.4UYKCh. 7 - Prob. 7.5UYKCh. 7 - Prob. 7.6CE7Ch. 7 - Prob. 7.7CE7Ch. 7 - Prob. 7.8CE7Ch. 7 - Prob. 7.9CE7Ch. 7 - Prob. 7.1CE7Ch. 7 - Prob. 7.11CS7Ch. 7 - Prob. 7.12CS7Ch. 7 - Prob. 7.13CS7Ch. 7 - Prob. 7.14CS7Ch. 7 - Prob. 7.15CS7Ch. 7 - Prob. 7.16CS7Ch. 7 - Prob. 7.17CS7Ch. 7 - Prob. 7.18MMLCh. 7 - Go to www.microsoft.com and search for Microsoft...
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