Chapter 7.2, Problem 28WE

To determine

Complete the table for the condition $\frac{KR}{RT}=\frac{KS}{SU}$ in the given figure.

Answer to Problem 28WE

The value of $KR=20,RT=10\text{and S}U=14$

Explanation of Solution

Given:

The given figure is,

  

And the given condition is,

  $\frac{KR}{RT}=\frac{KS}{SU}$

The table is,

  

From the table,

  $KT=30,KS=28\text{and }KU=42$

Now,

  $\begin{array}{l}SU=KU-KS\\ =42-28\\ \Rightarrow SU=14\end{array}$

And

  $\begin{array}{l}\frac{KR}{KT-KR}=\frac{28}{14}\\ \Rightarrow \frac{KR}{30-KR}=2\\ \Rightarrow KR=60-2KR\\ \Rightarrow 3KR=60\\ \Rightarrow KR=20\end{array}$

And

  $\begin{array}{l}RT=KT-KR\\ =30-20\\ \Rightarrow RT=10\end{array}$

So, $KR=20,RT=10\text{and S}U=14$