a. Answer The lengths of the side ET is 12 Explanation Given Information: Two similar triangles ΔABC and ΔJET with BC=20 and the scale factor 5 3 Formula used: The condition for similarity of two triangles as shown below in terms of the sides is expressed as A B J E = A C J T = B C E T The above ratio is called scale factor for the two triangles ΔABC and ΔJET. Calculation: Consider the two triangles ΔABC and ΔJET. The scale factor is given as 5 3 . Also, the side BC of the ΔABC is given as 20. Now, based on the definition of the scale factor as expressed in the previous section, the measure of side ET can be obtained as, 20 E T = 5 3 E T = 20 × 3 5 = 12 b. To determine To find: the perimeter of ΔABC Answer The perimeter of ΔABC is 50 Explanation Given Information: Two similar triangles ΔABC and ΔJET with BC=20 and the scale factor 5 3 Formula used: The condition for similarity of two triangles as shown below in terms of the perimeter of the triangles P A B C and P J E T is expressed as B C E T = P A B C P J E T The above ratio is called scale factor for the two triangles ΔABC and ΔJET. Calculation: Consider the two triangles ΔABC and ΔJET. The scale factor is given as 5 3 . Also, the perimeter of the ΔJET is given as 30. Now, based on the definition of the scale factor as expressed in the previous section, the measure of perimeter of ΔABC can be obtained as, P A B C 30 = 5 3 P A B C = 30 × 5 3 = 50

McDougal Littell Jurgensen Geometry: Student Edition Geometry

5th Edition

ISBN: 9780395977279

Author: Ray C. Jurgensen, Richard G. Brown, John W. Jurgensen

Publisher: Houghton Mifflin Company College Division

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Question

Polygon with three sides, three angles, and three vertices. Based on the properties of each side, the types of triangles are scalene (triangle with three three different lengths and three different angles), isosceles (angle with two equal sides and two equal angles), and equilateral (three equal sides and three angles of 60°). The types of angles are acute (less than 90°); obtuse (greater than 90°); and right (90°).

Chapter 7, Problem 11CR

To determine

To find: the lengths of the side ET of the ΔJET

Expert Solution

Answer to Problem 11CR

The lengths of the side ET is 12

Explanation of Solution

Given Information: Two similar triangles ΔABC and ΔJET with BC=20 and the scale factor 53

Formula used:

The condition for similarity of two triangles as shown below in terms of the sides is expressed as

ABJE=ACJT=BCET

The above ratio is called scale factor for the two triangles ΔABC and ΔJET.

Calculation: Consider the two triangles ΔABC and ΔJET.

The scale factor is given as 53 . Also, the side BC of the ΔABC is given as 20. Now, based on the definition of the scale factor as expressed in the previous section, the measure of side ET can be obtained as,

20ET=53ET=20×35=12

To determine

To find: the perimeter of ΔABC

Expert Solution

Answer to Problem 11CR

The perimeter of ΔABC is 50

Explanation of Solution

Given Information: Two similar triangles ΔABC and ΔJET with BC=20 and the scale factor 53

Formula used:

The condition for similarity of two triangles as shown below in terms of the perimeter of the triangles PABC and PJET is expressed as

BCET=PABCPJET

The above ratio is called scale factor for the two triangles ΔABC and ΔJET.

Calculation: Consider the two triangles ΔABC and ΔJET.

The scale factor is given as 53 . Also, the perimeter of the ΔJET is given as 30. Now, based on the definition of the scale factor as expressed in the previous section, the measure of perimeter of ΔABC can be obtained as,

PABC30=53PABC=30×53=50

Chapter 7, Problem 10CR

Chapter 7, Problem 12CR

Chapter 7 Solutions

McDougal Littell Jurgensen Geometry: Student Edition Geometry

Ch. 7.1 - Prob. 1CE Ch. 7.1 - Prob. 2CE Ch. 7.1 - Prob. 3CE Ch. 7.1 - Prob. 4CE Ch. 7.1 - Prob. 5CE Ch. 7.1 - Prob. 6CE Ch. 7.1 - Prob. 7CE Ch. 7.1 - Prob. 8CE Ch. 7.1 - Prob. 9CE Ch. 7.1 - Prob. 10CE

Ch. 7.1 - Prob. 11CE Ch. 7.1 - Prob. 12CE Ch. 7.1 - Prob. 13CE Ch. 7.1 - Prob. 14CE Ch. 7.1 - Prob. 15CE Ch. 7.1 - Prob. 16CE Ch. 7.1 - Prob. 17CE Ch. 7.1 - Prob. 18CE Ch. 7.1 - Prob. 1WE Ch. 7.1 - Prob. 2WE Ch. 7.1 - Prob. 3WE Ch. 7.1 - Prob. 4WE Ch. 7.1 - Prob. 5WE Ch. 7.1 - Prob. 6WE Ch. 7.1 - Prob. 7WE Ch. 7.1 - Prob. 8WE Ch. 7.1 - Prob. 9WE Ch. 7.1 - Prob. 10WE Ch. 7.1 - Prob. 11WE Ch. 7.1 - Prob. 12WE Ch. 7.1 - Prob. 13WE Ch. 7.1 - Prob. 14WE Ch. 7.1 - Prob. 15WE Ch. 7.1 - Prob. 16WE Ch. 7.1 - Prob. 17WE Ch. 7.1 - Prob. 18WE Ch. 7.1 - Prob. 19WE Ch. 7.1 - Prob. 20WE Ch. 7.1 - Prob. 21WE Ch. 7.1 - Prob. 22WE Ch. 7.1 - Prob. 23WE Ch. 7.1 - Prob. 24WE Ch. 7.1 - Prob. 25WE Ch. 7.1 - Prob. 26WE Ch. 7.1 - Prob. 27WE Ch. 7.1 - Prob. 28WE Ch. 7.1 - Prob. 29WE Ch. 7.1 - Prob. 30WE Ch. 7.1 - Prob. 31WE Ch. 7.1 - Prob. 32WE Ch. 7.1 - Prob. 33WE Ch. 7.1 - Prob. 34WE Ch. 7.1 - Prob. 35WE Ch. 7.1 - Prob. 36WE Ch. 7.2 - Prob. 1CE Ch. 7.2 - Prob. 2CE Ch. 7.2 - Prob. 3CE Ch. 7.2 - Prob. 4CE Ch. 7.2 - 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