Chapter 7, Problem 24AR

To determine

To find: Positive value of $x.$

Answer to Problem 24AR

Positive value of $x$ is $\sqrt{7}.$

Explanation of Solution

Given information: $x^2+3^2=4^2$

Calculation:

We have given:

  $x^2+3^2=4^2$

Find values of squares.

  $\Rightarrow x^2+9=16$

Subtract $9$ from both side.

  $\Rightarrow x^2=16-9$

  $\Rightarrow x^2=7$

Take square root on both sides.

  $\Rightarrow x=\pm \sqrt{7}$

But $x$ is positive number.

  $\therefore x=\sqrt{7}$

Conclusion:

Therefore, the positive value of $x$ is $\sqrt{7}.$