Chapter 7, Problem 27AR

To determine

To find: Positive value of $x.$

Answer to Problem 27AR

Positive value of $x$ is $2\sqrt{2}.$

Explanation of Solution

Given information: $1^2+x^2=3^2$

Calculation:

We have given:

  $1^2+x^2=3^2$

Find values of squares.

  $\Rightarrow 1+x^2=9$

Subtract $1$ from both side.

  $\Rightarrow x^2=9-1$

  $\Rightarrow x^2=8$

Take square root on both sides.

  $\Rightarrow x=\pm \sqrt{8}$

  $\Rightarrow x=\pm \sqrt{4\times 2}$

  $\Rightarrow x=\pm 2\sqrt{2}$

But $x$ is positive number.

  $\therefore x=2\sqrt{2}$

Conclusion:

Therefore, the positive value of $x$ is $2\sqrt{2}.$