Chapter 7, Problem 21AR

To determine

To find: Positive value of $x.$

Answer to Problem 21AR

Positive value of $x$ is $5.$

Explanation of Solution

Given information: $3^2+4^2=x^2$

Calculation:

We have given:

  $3^2+4^2=x^2$

  $\Rightarrow x^2=3^2+4^2$

Find values of squares.

  $\Rightarrow x^2=9+16$

  $\Rightarrow x^2=25$

Take square root on both sides.

  $\Rightarrow x=\pm \sqrt{25}$

  $\Rightarrow x=\pm 5$

But $x$ is positive number.

  $\therefore x=5$

Conclusion:

Therefore, the positive value of $x$ is $5.$