Chapter 7.15, Problem 7.30P

(a)

Interpretation Introduction

Interpretation:

The products of the elimination reaction of two stereoisomers of bromodecalin with $\text{KOH}$ are to be predicted. The reason corresponding to the large difference in the ease of elimination of both the stereoisomers of bromodecalin is to be stated.

Concept introduction:

The chemical reaction that consists of an alkyl halide, a good leaving group which reacts with Lewis base to form an alkene is termed as elimination reaction. In this reaction there is complete removal of the leaving group without any substitution.

The bimolecular elimination reaction that favours the removal of an $\text{HX}$ substituent from an alkyl halide that needs a base to remove $\text{H}$ from carbon adjacent to the leaving group that in turn forms a double bond is termed ${\text{E}}_{\text{2}}$ elimination reaction.

(b)

Interpretation Introduction

Interpretation:

The compound that undergoes faster elimination reaction with $\text{KOH}$ from the given set of compounds is to be predicted. The major product formed during the elimination reaction is to be predicted.

Concept introduction:

The chemical reaction that consists of an alkyl halide, a good leaving group which reacts with Lewis base to form an alkene is termed as elimination reaction. In this reaction there is complete removal of the leaving group takes place without any substitution.

The bimolecular elimination reaction that favours the removal of a $\text{HX}$ substituent from an alkyl halide that needs a base to remove $\text{H}$ from carbon adjacent to the leaving group that in turn forms a double bond is termed ${\text{E}}_{\text{2}}$ elimination reaction.