When an object is displaced by an amount x from stable equilibrium, a restoring force acts on it, tending to return the object to its equilibrium position. The magnitude of the restoring force can be a complicated function of x . In such cases, we can generally imagine the force function F ( x ) to be expressed as a power series in x as F ( x ) = − ( k 1 x + k 2 x 2 + k 3 x 3 + ⋯ ) . The first term here is just Hooke’s law, which describes the force exerted by a simple spring for small displacements. For small excursions from equilibrium, we generally ignore the higher-order terms, but in some cases it may be desirable to keep the second term as well. If we model the restoring force as F = −( k 1 x + k 2 x 2 ), how much work is done on an object in displacing it from x = 0 to x = x max by an applied force − F ?
When an object is displaced by an amount x from stable equilibrium, a restoring force acts on it, tending to return the object to its equilibrium position. The magnitude of the restoring force can be a complicated function of x . In such cases, we can generally imagine the force function F ( x ) to be expressed as a power series in x as F ( x ) = − ( k 1 x + k 2 x 2 + k 3 x 3 + ⋯ ) . The first term here is just Hooke’s law, which describes the force exerted by a simple spring for small displacements. For small excursions from equilibrium, we generally ignore the higher-order terms, but in some cases it may be desirable to keep the second term as well. If we model the restoring force as F = −( k 1 x + k 2 x 2 ), how much work is done on an object in displacing it from x = 0 to x = x max by an applied force − F ?
Solution Summary: The author explains the work done on an object to displace from x=0 to
When an object is displaced by an amount x from stable equilibrium, a restoring force acts on it, tending to return the object to its equilibrium position. The magnitude of the restoring force can be a complicated function of x. In such cases, we can generally imagine the force function F(x) to be expressed as a power series in x as
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. The first term here is just Hooke’s law, which describes the force exerted by a simple spring for small displacements. For small excursions from equilibrium, we generally ignore the higher-order terms, but in some cases it may be desirable to keep the second term as well. If we model the restoring force as F = −(k1x + k2x2), how much work is done on an object in displacing it from x = 0 to x = xmax by an applied force −F?
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The work done on an object is equal to the integral of the force on that object dotted with its displacent.
This looks like W=∫(F.ds) (W is work, F is force, and ds is the infinitesimally small displacement vector). For a force whose direction is the line of motion, the equation becomes W=∫(Fdx).
If the force on an object as a function of displacement is F(x)=3x2+x, what is the work as a function of displacement (using calculus application) W(x)? Assume W(0)=0 and the force is in the direction of the object's motion.
In physics, the work done on an object is equal to the integral of the force on that object dotted with its displacent.
This looks like W = |(F-ds) (W is work, F is force, and ds is the infinitesimally small displacement vector). For a force whose direction
is the line of motion, the equation becomes W = /(Fdz).
If the force on an object as a function of displacement is F(z) = 3z² + z, what is the work as a function of displacement W(z)?Assume
W(0) = 0 and the force is in the direction of the object's motion.
Chapter 7 Solutions
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