Chapter 7, Problem 7.54P

Interpretation Introduction

Interpretation:

Concept Introduction:

$ndot=100\frac{kmol}{hr}$

Initial Pressure $P_1=1.2bar$

Initial temperature $T_1=300K$

Final Pressure $P_2=6bar$

Final temperature = T₂ For ideal gas ethylene, $C_p=50.6\frac{J}{mol.K}$

Efficiency of compressor, $\eta =0.70$

For adiabatic compression, $T_2={\left(\frac{P_2}{P_1}\right)}^{\frac{R}{C_p}}\times T_1$

$\mathrm{C}(Compressor)=3040\$\times {\left(\frac{{\stackrel{•}{W}}_s}{kW}\right)}^{0.952}$

  ${\stackrel{•}{W}}_s$ = Isentropic Power required for compressor

  $C(Motor)=380\$\times {\left(\frac{{\stackrel{•}{W}}_e}{kW}\right)}^{0.855}$

  ${\stackrel{•}{W}}_e$ = Delivered shaft power of motor