
Concept explainers
a.
To Find:
To find a curve to model the data and superimpose it on a
a.

Answer to Problem 65RE
The graph is shown superimposed
Explanation of Solution
Given information:
The given data is below:
Formula:
The general logistic regression equation is
The regression equation is given by
Now substituting the values,
Graph:
Interpretation:
The graph is shown superimposed on the scatter plot. The fit is almost perfect.
Therefore, the graph is shown superimposed.
b.
To Find:
To find the number of Anchorage population approach in the long run.
b.

Answer to Problem 65RE
The number of Anchorage population approach in the long run is
Explanation of Solution
Given information:
The given data is below:
The regression equation is given by
Now substituting the values,
Therefore, the number of Anchorage population approach in the long run is
c.
To Find:
To find the logistic
c.

Answer to Problem 65RE
The logistic differential equation is
Explanation of Solution
Given information:
The given data is below:
The logistic differential equation is
So from part (a) the carrying capacity
Now substituting the values in the differential equation,
Therefore, the logistic differential equation is
d.
To Find:
To find whether the data is affected by carrying capacity predicted by the regression equation.
d.

Answer to Problem 65RE
There is no reason to be concerned, unless the model application was extremely sensitive.
Explanation of Solution
Given information:
The given data is below:
With the new point, the carrying capacity of Anchorage is predicted to be
And thus, there is no reason to be concerned, unless the model application was extremely sensitive.
Chapter 7 Solutions
Calculus 2012 Student Edition (by Finney/Demana/Waits/Kennedy)
Additional Math Textbook Solutions
Calculus: Early Transcendentals (2nd Edition)
A First Course in Probability (10th Edition)
Introductory Statistics
Algebra and Trigonometry (6th Edition)
College Algebra with Modeling & Visualization (5th Edition)
Elementary Statistics (13th Edition)
- (10 points) Let f(x, y, z) = ze²²+y². Let E = {(x, y, z) | x² + y² ≤ 4,2 ≤ z ≤ 3}. Calculate the integral f(x, y, z) dv. Earrow_forward(12 points) Let E={(x, y, z)|x²+ y² + z² ≤ 4, x, y, z > 0}. (a) (4 points) Describe the region E using spherical coordinates, that is, find p, 0, and such that (x, y, z) (psin cos 0, psin sin 0, p cos) € E. (b) (8 points) Calculate the integral E xyz dV using spherical coordinates.arrow_forward(10 points) Let f(x, y, z) = ze²²+y². Let E = {(x, y, z) | x² + y² ≤ 4,2 ≤ z < 3}. Calculate the integral y, f(x, y, z) dV.arrow_forward
- (14 points) Let f: R3 R and T: R3. →R³ be defined by f(x, y, z) = ln(x²+ y²+2²), T(p, 0,4)=(psin cos 0, psin sin, pcos). (a) (4 points) Write out the composition g(p, 0, 4) = (foT)(p,, ) explicitly. Then calculate the gradient Vg directly, i.e. without using the chain rule. (b) (4 points) Calculate the gradient Vf(x, y, z) where (x, y, z) = T(p, 0,4). (c) (6 points) Calculate the derivative matrix DT(p, 0, p). Then use the Chain Rule to calculate Vg(r,0,4).arrow_forward(10 points) Let S be the upper hemisphere of the unit sphere x² + y²+2² = 1. Let F(x, y, z) = (x, y, z). Calculate the surface integral J F F-dS. Sarrow_forward(8 points) Calculate the following line integrals. (a) (4 points) F Fds where F(x, y, z) = (x, y, xy) and c(t) = (cost, sint, t), tЄ [0,π] . (b) (4 points) F. Fds where F(x, y, z) = (√xy, e³, xz) where c(t) = (t², t², t), t = [0, 1] .arrow_forward
- review help please and thank you!arrow_forward(10 points) Let S be the surface that is part of the sphere x² + y²+z² = 4 lying below the plane 2√3 and above the plane z-v -√3. Calculate the surface area of S.arrow_forward(8 points) Let D = {(x, y) | 0 ≤ x² + y² ≤4}. Calculate == (x² + y²)³/2dA by making a change of variables to polar coordinates, i.e. x=rcos 0, y = r sin 0.arrow_forward
- x² - y² (10 points) Let f(x,y): = (a) (6 points) For each vector u = (1, 2), calculate the directional derivative Duƒ(1,1). (b) (4 points) Determine all unit vectors u for which Duf(1, 1) = 0.arrow_forwardSolve : X + sin x = 0. By the false positioning numerical methodarrow_forwardSolve: X + sin X = 0 by the false positionining numerical methodarrow_forward
- Calculus: Early TranscendentalsCalculusISBN:9781285741550Author:James StewartPublisher:Cengage LearningThomas' Calculus (14th Edition)CalculusISBN:9780134438986Author:Joel R. Hass, Christopher E. Heil, Maurice D. WeirPublisher:PEARSONCalculus: Early Transcendentals (3rd Edition)CalculusISBN:9780134763644Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric SchulzPublisher:PEARSON
- Calculus: Early TranscendentalsCalculusISBN:9781319050740Author:Jon Rogawski, Colin Adams, Robert FranzosaPublisher:W. H. FreemanCalculus: Early Transcendental FunctionsCalculusISBN:9781337552516Author:Ron Larson, Bruce H. EdwardsPublisher:Cengage Learning





