A 7.00-kg bowling ball moving at 8.0 m/s strikes a 1.0-kg bowling pin and slows to 7.0 m/s in 0.040 s.
a. Show that the force of impact on the bowling ball is 175 N.
b. How much force acts on the bowling pin?
(a)
To show: The force of impact on the bowling ball is
Explanation of Solution
Given:
Mass of the bowling ball is
Initial velocity of the ball is
Mass of the bowling pin is
Final velocity of the ball is
Time interval is
Formula used:
Initial momentum of the ball is
Final momentum of the ball is
From the impulse - momentum theorem, the impulse on the ball can be written as
Substituting for
Calculation:
Substituting the numerical values in equation
Magnitude of force on the ball is
Conclusion:
The force of impact on the bowling ball is
(b)
The amount of force acting on the bowling pin.
Answer to Problem 59A
Explanation of Solution
Introduction:
Newton’s third law of motion - When there is an interaction among two bodies, both the bodies exerts force on each another whose magnitude are equal but they are acting in reverse direction. This third law is also called by the name law of action and reaction.
In the case of hitting a bowling ball with a bowling pin, both the ball and the pin experiences the force. The magnitude of the force experienced by the bowling ball and the bowling pin are equal and are acting in reverse direction.
Therefore the force acting on the bowling pin is also
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