The average cycle time for each operation. Introduction: The amount of the dependency on human effort by an organization in terms of achieving its goals is given by the work design. It is directly linked to the productivity of an organization where good work design helps in achieving high productivity.

Question

Want to see more full solutions like this?

Answer 1

Question

Chapter 7, Problem 3P

a)

Summary Introduction

To determine: The average cycle time for each operation.

Introduction: The amount of the dependency on human effort by an organization in terms of achieving its goals is given by the work design. It is directly linked to the productivity of an organization where good work design helps in achieving high productivity.

a)

Expert Solution

Explanation of Solution

Given information:

		Observation (minutes per cycle)
Element	Performance rating	1	2	3	4	5	6
1	90	0.44	0.5	0.43	0.45	0.48	0.46
2	85	1.5	1.54	1.47	1.51	1.49	1.52
3	110	0.84	0.89	0.77	0.83	0.85	0.8
4	100	1.1	1.14	1.08	1.2	1.16	1.26

Calculation of average time per cycle:

	Observation (minutes per cycle)
Performance rating	1	2	3	4	5	6	Average time per cycle
90	0.44	0.5	0.43	0.45	0.48	0.46	0.46
85	1.5	1.54	1.47	1.51	1.49	1.52	1.505
110	0.84	0.89	0.77	0.83	0.85	0.8	0.83
100	1.1	1.14	1.08	1.2	1.16	1.26	1.156667

Excel worksheet:

Operations Management (McGraw-Hill Series in Operations and Decision Sciences), Chapter 7, Problem 3P , additional homework tip 1

Average time per cycle is calculated by taking average of all cycle in each element which is average of 0.44, 0.5, 0.43, 0.45, 0.48 and 0.46 which gives 0.46 as average time per cycle for element 1 and similar method follows for element 2, 3 and 4.

b)

Summary Introduction

To determine: The normal time for the operation.

b)

Expert Solution

Explanation of Solution

Given information:

		Observation (minutes per cycle)
Element	Performance rating	1	2	3	4	5	6
1	90	0.44	0.5	0.43	0.45	0.48	0.46
2	85	1.5	1.54	1.47	1.51	1.49	1.52
3	110	0.84	0.89	0.77	0.83	0.85	0.8
4	100	1.1	1.14	1.08	1.2	1.16	1.26

Formula:

NT = Observed time × Perform Rating = OR × PR

Calculation of normal time:

		Observation (minutes per cycle)
Element	Performance rating	1	2	3	4	5	6	Average time per cycle	NT
1	0.9	0.44	0.5	0.43	0.45	0.48	0.46	0.46	0.414
2	0.85	1.5	1.54	1.47	1.51	1.49	1.52	1.505	1.27925
3	1.1	0.84	0.89	0.77	0.83	0.85	0.8	0.83	0.913
4	1	1.1	1.14	1.08	1.2	1.16	1.26	1.156666667	1.156667

Excel worksheet:

Operations Management (McGraw-Hill Series in Operations and Decision Sciences), Chapter 7, Problem 3P , additional homework tip 2

Normal time is calculated by multiplying observed timing, 0.46 and performance rating, 0.9 which yields 0.414 minutes for element 1, 2, 3 and 4.

c)

Summary Introduction

To determine: The standard time for the operation.

c)

Expert Solution

Explanation of Solution

Given information:

		Observation (minutes per cycle)
Element	Performance rating	1	2	3	4	5	6
1	90	0.44	0.5	0.43	0.45	0.48	0.46
2	85	1.5	1.54	1.47	1.51	1.49	1.52
3	110	0.84	0.89	0.77	0.83	0.85	0.8
4	100	1.1	1.14	1.08	1.2	1.16	1.26

Formula:

Standard time = Normal time × Allowance factor = NT × AF

Calculation of standard time:

AF job = 1+A = 1+0.15 = 1.15

Allowance factor is calculated by dividing 1 with difference of 1 and 0.15 which yields 1.15.

		Observation (minutes per cycle)
Element	Performance rating	1	2	3	4	5	6	Average time per cycle	NT	Af_job	ST
1	0.9	0.44	0.5	0.43	0.45	0.48	0.46	0.46	0.414	1.15	0.4761
2	0.85	1.5	1.54	1.47	1.51	1.49	1.52	1.505	1.27925	1.15	1.471138
3	1.1	0.84	0.89	0.77	0.83	0.85	0.8	0.83	0.913	1.15	1.04995
4	1	1.1	1.14	1.08	1.2	1.16	1.26	1.157	1.157	1.15	1.330167

Excel worksheet:

Operations Management (McGraw-Hill Series in Operations and Decision Sciences), Chapter 7, Problem 3P , additional homework tip 3

Standard time for the operation is calculated by multiplying normal time of 0.414 minutes with allowance factor of 1.15 which gives 0.4761 minutes for element 1 and same procedure goes with element 2, 3 and 4.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Students have asked these similar questions

Conclusion: The report recommendations and broad conclusion to the essay. TOTAL 5 100

As part of your new role, as a strategy consultant and member of the steering committee, discuss what logistics and transportation strategies you will execute to achieve operational efficiencies and facilitate economic growth in SA. The committee would like to have a implementable strategic transport and logistics plan to realise the roadmap vision based on the subsection numbering given below! QUESTION ONE Introduction: Must include an overview and history of South Africa's Road, rail and freight transport network. Marks 5

1.2 What are the current freight and logistic challenges on the road network 10 1.3 Discuss key relevant financials of infrastructure, industries and revenue resulting in this logistics crisis. 15

Answer 2

Question

Chapter 7, Problem 3P

a)

Summary Introduction

To determine: The average cycle time for each operation.

Introduction: The amount of the dependency on human effort by an organization in terms of achieving its goals is given by the work design. It is directly linked to the productivity of an organization where good work design helps in achieving high productivity.

a)

Expert Solution

Explanation of Solution

Given information:

		Observation (minutes per cycle)
Element	Performance rating	1	2	3	4	5	6
1	90	0.44	0.5	0.43	0.45	0.48	0.46
2	85	1.5	1.54	1.47	1.51	1.49	1.52
3	110	0.84	0.89	0.77	0.83	0.85	0.8
4	100	1.1	1.14	1.08	1.2	1.16	1.26

Calculation of average time per cycle:

	Observation (minutes per cycle)
Performance rating	1	2	3	4	5	6	Average time per cycle
90	0.44	0.5	0.43	0.45	0.48	0.46	0.46
85	1.5	1.54	1.47	1.51	1.49	1.52	1.505
110	0.84	0.89	0.77	0.83	0.85	0.8	0.83
100	1.1	1.14	1.08	1.2	1.16	1.26	1.156667

Excel worksheet:

Operations Management (McGraw-Hill Series in Operations and Decision Sciences), Chapter 7, Problem 3P , additional homework tip 1

Average time per cycle is calculated by taking average of all cycle in each element which is average of 0.44, 0.5, 0.43, 0.45, 0.48 and 0.46 which gives 0.46 as average time per cycle for element 1 and similar method follows for element 2, 3 and 4.

b)

Summary Introduction

To determine: The normal time for the operation.

b)

Expert Solution

Explanation of Solution

Given information:

		Observation (minutes per cycle)
Element	Performance rating	1	2	3	4	5	6
1	90	0.44	0.5	0.43	0.45	0.48	0.46
2	85	1.5	1.54	1.47	1.51	1.49	1.52
3	110	0.84	0.89	0.77	0.83	0.85	0.8
4	100	1.1	1.14	1.08	1.2	1.16	1.26

Formula:

NT = Observed time × Perform Rating = OR × PR

Calculation of normal time:

		Observation (minutes per cycle)
Element	Performance rating	1	2	3	4	5	6	Average time per cycle	NT
1	0.9	0.44	0.5	0.43	0.45	0.48	0.46	0.46	0.414
2	0.85	1.5	1.54	1.47	1.51	1.49	1.52	1.505	1.27925
3	1.1	0.84	0.89	0.77	0.83	0.85	0.8	0.83	0.913
4	1	1.1	1.14	1.08	1.2	1.16	1.26	1.156666667	1.156667

Excel worksheet:

Operations Management (McGraw-Hill Series in Operations and Decision Sciences), Chapter 7, Problem 3P , additional homework tip 2

Normal time is calculated by multiplying observed timing, 0.46 and performance rating, 0.9 which yields 0.414 minutes for element 1, 2, 3 and 4.

c)

Summary Introduction

To determine: The standard time for the operation.

c)

Expert Solution

Explanation of Solution

Given information:

		Observation (minutes per cycle)
Element	Performance rating	1	2	3	4	5	6
1	90	0.44	0.5	0.43	0.45	0.48	0.46
2	85	1.5	1.54	1.47	1.51	1.49	1.52
3	110	0.84	0.89	0.77	0.83	0.85	0.8
4	100	1.1	1.14	1.08	1.2	1.16	1.26

Formula:

Standard time = Normal time × Allowance factor = NT × AF

Calculation of standard time:

AF job = 1+A = 1+0.15 = 1.15

Allowance factor is calculated by dividing 1 with difference of 1 and 0.15 which yields 1.15.

		Observation (minutes per cycle)
Element	Performance rating	1	2	3	4	5	6	Average time per cycle	NT	Af_job	ST
1	0.9	0.44	0.5	0.43	0.45	0.48	0.46	0.46	0.414	1.15	0.4761
2	0.85	1.5	1.54	1.47	1.51	1.49	1.52	1.505	1.27925	1.15	1.471138
3	1.1	0.84	0.89	0.77	0.83	0.85	0.8	0.83	0.913	1.15	1.04995
4	1	1.1	1.14	1.08	1.2	1.16	1.26	1.157	1.157	1.15	1.330167

Excel worksheet:

Operations Management (McGraw-Hill Series in Operations and Decision Sciences), Chapter 7, Problem 3P , additional homework tip 3

Standard time for the operation is calculated by multiplying normal time of 0.414 minutes with allowance factor of 1.15 which gives 0.4761 minutes for element 1 and same procedure goes with element 2, 3 and 4.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Question

Chapter 7, Problem 3P

a)

Summary Introduction

To determine: The average cycle time for each operation.

Introduction: The amount of the dependency on human effort by an organization in terms of achieving its goals is given by the work design. It is directly linked to the productivity of an organization where good work design helps in achieving high productivity.

a)

Expert Solution

Explanation of Solution

Given information:

		Observation (minutes per cycle)
Element	Performance rating	1	2	3	4	5	6
1	90	0.44	0.5	0.43	0.45	0.48	0.46
2	85	1.5	1.54	1.47	1.51	1.49	1.52
3	110	0.84	0.89	0.77	0.83	0.85	0.8
4	100	1.1	1.14	1.08	1.2	1.16	1.26

Calculation of average time per cycle:

	Observation (minutes per cycle)
Performance rating	1	2	3	4	5	6	Average time per cycle
90	0.44	0.5	0.43	0.45	0.48	0.46	0.46
85	1.5	1.54	1.47	1.51	1.49	1.52	1.505
110	0.84	0.89	0.77	0.83	0.85	0.8	0.83
100	1.1	1.14	1.08	1.2	1.16	1.26	1.156667

Excel worksheet:

Operations Management (McGraw-Hill Series in Operations and Decision Sciences), Chapter 7, Problem 3P , additional homework tip 1

Average time per cycle is calculated by taking average of all cycle in each element which is average of 0.44, 0.5, 0.43, 0.45, 0.48 and 0.46 which gives 0.46 as average time per cycle for element 1 and similar method follows for element 2, 3 and 4.

b)

Summary Introduction

To determine: The normal time for the operation.

b)

Expert Solution

Explanation of Solution

Given information:

		Observation (minutes per cycle)
Element	Performance rating	1	2	3	4	5	6
1	90	0.44	0.5	0.43	0.45	0.48	0.46
2	85	1.5	1.54	1.47	1.51	1.49	1.52
3	110	0.84	0.89	0.77	0.83	0.85	0.8
4	100	1.1	1.14	1.08	1.2	1.16	1.26

Formula:

NT = Observed time × Perform Rating = OR × PR

Calculation of normal time:

		Observation (minutes per cycle)
Element	Performance rating	1	2	3	4	5	6	Average time per cycle	NT
1	0.9	0.44	0.5	0.43	0.45	0.48	0.46	0.46	0.414
2	0.85	1.5	1.54	1.47	1.51	1.49	1.52	1.505	1.27925
3	1.1	0.84	0.89	0.77	0.83	0.85	0.8	0.83	0.913
4	1	1.1	1.14	1.08	1.2	1.16	1.26	1.156666667	1.156667

Excel worksheet:

Operations Management (McGraw-Hill Series in Operations and Decision Sciences), Chapter 7, Problem 3P , additional homework tip 2

Normal time is calculated by multiplying observed timing, 0.46 and performance rating, 0.9 which yields 0.414 minutes for element 1, 2, 3 and 4.

c)

Summary Introduction

To determine: The standard time for the operation.

c)

Expert Solution

Explanation of Solution

Given information:

		Observation (minutes per cycle)
Element	Performance rating	1	2	3	4	5	6
1	90	0.44	0.5	0.43	0.45	0.48	0.46
2	85	1.5	1.54	1.47	1.51	1.49	1.52
3	110	0.84	0.89	0.77	0.83	0.85	0.8
4	100	1.1	1.14	1.08	1.2	1.16	1.26

Formula:

Standard time = Normal time × Allowance factor = NT × AF

Calculation of standard time:

AF job = 1+A = 1+0.15 = 1.15

Allowance factor is calculated by dividing 1 with difference of 1 and 0.15 which yields 1.15.

		Observation (minutes per cycle)
Element	Performance rating	1	2	3	4	5	6	Average time per cycle	NT	Af_job	ST
1	0.9	0.44	0.5	0.43	0.45	0.48	0.46	0.46	0.414	1.15	0.4761
2	0.85	1.5	1.54	1.47	1.51	1.49	1.52	1.505	1.27925	1.15	1.471138
3	1.1	0.84	0.89	0.77	0.83	0.85	0.8	0.83	0.913	1.15	1.04995
4	1	1.1	1.14	1.08	1.2	1.16	1.26	1.157	1.157	1.15	1.330167

Excel worksheet:

Operations Management (McGraw-Hill Series in Operations and Decision Sciences), Chapter 7, Problem 3P , additional homework tip 3

Standard time for the operation is calculated by multiplying normal time of 0.414 minutes with allowance factor of 1.15 which gives 0.4761 minutes for element 1 and same procedure goes with element 2, 3 and 4.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Question

Chapter 7, Problem 3P

a)

Summary Introduction

To determine: The average cycle time for each operation.

Introduction: The amount of the dependency on human effort by an organization in terms of achieving its goals is given by the work design. It is directly linked to the productivity of an organization where good work design helps in achieving high productivity.

a)

Expert Solution

Explanation of Solution

Given information:

		Observation (minutes per cycle)
Element	Performance rating	1	2	3	4	5	6
1	90	0.44	0.5	0.43	0.45	0.48	0.46
2	85	1.5	1.54	1.47	1.51	1.49	1.52
3	110	0.84	0.89	0.77	0.83	0.85	0.8
4	100	1.1	1.14	1.08	1.2	1.16	1.26

Calculation of average time per cycle:

	Observation (minutes per cycle)
Performance rating	1	2	3	4	5	6	Average time per cycle
90	0.44	0.5	0.43	0.45	0.48	0.46	0.46
85	1.5	1.54	1.47	1.51	1.49	1.52	1.505
110	0.84	0.89	0.77	0.83	0.85	0.8	0.83
100	1.1	1.14	1.08	1.2	1.16	1.26	1.156667

Excel worksheet:

Operations Management (McGraw-Hill Series in Operations and Decision Sciences), Chapter 7, Problem 3P , additional homework tip 1

Average time per cycle is calculated by taking average of all cycle in each element which is average of 0.44, 0.5, 0.43, 0.45, 0.48 and 0.46 which gives 0.46 as average time per cycle for element 1 and similar method follows for element 2, 3 and 4.

b)

Summary Introduction

To determine: The normal time for the operation.

b)

Expert Solution

Explanation of Solution

Given information:

		Observation (minutes per cycle)
Element	Performance rating	1	2	3	4	5	6
1	90	0.44	0.5	0.43	0.45	0.48	0.46
2	85	1.5	1.54	1.47	1.51	1.49	1.52
3	110	0.84	0.89	0.77	0.83	0.85	0.8
4	100	1.1	1.14	1.08	1.2	1.16	1.26

Formula:

NT = Observed time × Perform Rating = OR × PR

Calculation of normal time:

		Observation (minutes per cycle)
Element	Performance rating	1	2	3	4	5	6	Average time per cycle	NT
1	0.9	0.44	0.5	0.43	0.45	0.48	0.46	0.46	0.414
2	0.85	1.5	1.54	1.47	1.51	1.49	1.52	1.505	1.27925
3	1.1	0.84	0.89	0.77	0.83	0.85	0.8	0.83	0.913
4	1	1.1	1.14	1.08	1.2	1.16	1.26	1.156666667	1.156667

Excel worksheet:

Operations Management (McGraw-Hill Series in Operations and Decision Sciences), Chapter 7, Problem 3P , additional homework tip 2

Normal time is calculated by multiplying observed timing, 0.46 and performance rating, 0.9 which yields 0.414 minutes for element 1, 2, 3 and 4.

c)

Summary Introduction

To determine: The standard time for the operation.

c)

Expert Solution

Explanation of Solution

Given information:

		Observation (minutes per cycle)
Element	Performance rating	1	2	3	4	5	6
1	90	0.44	0.5	0.43	0.45	0.48	0.46
2	85	1.5	1.54	1.47	1.51	1.49	1.52
3	110	0.84	0.89	0.77	0.83	0.85	0.8
4	100	1.1	1.14	1.08	1.2	1.16	1.26

Formula:

Standard time = Normal time × Allowance factor = NT × AF

Calculation of standard time:

AF job = 1+A = 1+0.15 = 1.15

Allowance factor is calculated by dividing 1 with difference of 1 and 0.15 which yields 1.15.

		Observation (minutes per cycle)
Element	Performance rating	1	2	3	4	5	6	Average time per cycle	NT	Af_job	ST
1	0.9	0.44	0.5	0.43	0.45	0.48	0.46	0.46	0.414	1.15	0.4761
2	0.85	1.5	1.54	1.47	1.51	1.49	1.52	1.505	1.27925	1.15	1.471138
3	1.1	0.84	0.89	0.77	0.83	0.85	0.8	0.83	0.913	1.15	1.04995
4	1	1.1	1.14	1.08	1.2	1.16	1.26	1.157	1.157	1.15	1.330167

Excel worksheet:

Operations Management (McGraw-Hill Series in Operations and Decision Sciences), Chapter 7, Problem 3P , additional homework tip 3

Standard time for the operation is calculated by multiplying normal time of 0.414 minutes with allowance factor of 1.15 which gives 0.4761 minutes for element 1 and same procedure goes with element 2, 3 and 4.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 7, Problem 3P

a)

Summary Introduction

To determine: The average cycle time for each operation.

Introduction: The amount of the dependency on human effort by an organization in terms of achieving its goals is given by the work design. It is directly linked to the productivity of an organization where good work design helps in achieving high productivity.

a)

Expert Solution

Explanation of Solution

Given information:

		Observation (minutes per cycle)
Element	Performance rating	1	2	3	4	5	6
1	90	0.44	0.5	0.43	0.45	0.48	0.46
2	85	1.5	1.54	1.47	1.51	1.49	1.52
3	110	0.84	0.89	0.77	0.83	0.85	0.8
4	100	1.1	1.14	1.08	1.2	1.16	1.26

Calculation of average time per cycle:

	Observation (minutes per cycle)
Performance rating	1	2	3	4	5	6	Average time per cycle
90	0.44	0.5	0.43	0.45	0.48	0.46	0.46
85	1.5	1.54	1.47	1.51	1.49	1.52	1.505
110	0.84	0.89	0.77	0.83	0.85	0.8	0.83
100	1.1	1.14	1.08	1.2	1.16	1.26	1.156667

Excel worksheet:

Operations Management (McGraw-Hill Series in Operations and Decision Sciences), Chapter 7, Problem 3P , additional homework tip 1

Average time per cycle is calculated by taking average of all cycle in each element which is average of 0.44, 0.5, 0.43, 0.45, 0.48 and 0.46 which gives 0.46 as average time per cycle for element 1 and similar method follows for element 2, 3 and 4.

b)

Summary Introduction

To determine: The normal time for the operation.

b)

Expert Solution

Explanation of Solution

Given information:

		Observation (minutes per cycle)
Element	Performance rating	1	2	3	4	5	6
1	90	0.44	0.5	0.43	0.45	0.48	0.46
2	85	1.5	1.54	1.47	1.51	1.49	1.52
3	110	0.84	0.89	0.77	0.83	0.85	0.8
4	100	1.1	1.14	1.08	1.2	1.16	1.26

Formula:

NT = Observed time × Perform Rating = OR × PR

Calculation of normal time:

		Observation (minutes per cycle)
Element	Performance rating	1	2	3	4	5	6	Average time per cycle	NT
1	0.9	0.44	0.5	0.43	0.45	0.48	0.46	0.46	0.414
2	0.85	1.5	1.54	1.47	1.51	1.49	1.52	1.505	1.27925
3	1.1	0.84	0.89	0.77	0.83	0.85	0.8	0.83	0.913
4	1	1.1	1.14	1.08	1.2	1.16	1.26	1.156666667	1.156667

Excel worksheet:

Operations Management (McGraw-Hill Series in Operations and Decision Sciences), Chapter 7, Problem 3P , additional homework tip 2

Normal time is calculated by multiplying observed timing, 0.46 and performance rating, 0.9 which yields 0.414 minutes for element 1, 2, 3 and 4.

c)

Summary Introduction

To determine: The standard time for the operation.

c)

Expert Solution

Explanation of Solution

Given information:

		Observation (minutes per cycle)
Element	Performance rating	1	2	3	4	5	6
1	90	0.44	0.5	0.43	0.45	0.48	0.46
2	85	1.5	1.54	1.47	1.51	1.49	1.52
3	110	0.84	0.89	0.77	0.83	0.85	0.8
4	100	1.1	1.14	1.08	1.2	1.16	1.26

Formula:

Standard time = Normal time × Allowance factor = NT × AF

Calculation of standard time:

AF job = 1+A = 1+0.15 = 1.15

Allowance factor is calculated by dividing 1 with difference of 1 and 0.15 which yields 1.15.

		Observation (minutes per cycle)
Element	Performance rating	1	2	3	4	5	6	Average time per cycle	NT	Af_job	ST
1	0.9	0.44	0.5	0.43	0.45	0.48	0.46	0.46	0.414	1.15	0.4761
2	0.85	1.5	1.54	1.47	1.51	1.49	1.52	1.505	1.27925	1.15	1.471138
3	1.1	0.84	0.89	0.77	0.83	0.85	0.8	0.83	0.913	1.15	1.04995
4	1	1.1	1.14	1.08	1.2	1.16	1.26	1.157	1.157	1.15	1.330167

Excel worksheet:

Operations Management (McGraw-Hill Series in Operations and Decision Sciences), Chapter 7, Problem 3P , additional homework tip 3

Standard time for the operation is calculated by multiplying normal time of 0.414 minutes with allowance factor of 1.15 which gives 0.4761 minutes for element 1 and same procedure goes with element 2, 3 and 4.

Answer 6

Chapter 7, Problem 3P

a)

Summary Introduction

To determine: The average cycle time for each operation.

Introduction: The amount of the dependency on human effort by an organization in terms of achieving its goals is given by the work design. It is directly linked to the productivity of an organization where good work design helps in achieving high productivity.

a)

Expert Solution

Explanation of Solution

Given information:

		Observation (minutes per cycle)
Element	Performance rating	1	2	3	4	5	6
1	90	0.44	0.5	0.43	0.45	0.48	0.46
2	85	1.5	1.54	1.47	1.51	1.49	1.52
3	110	0.84	0.89	0.77	0.83	0.85	0.8
4	100	1.1	1.14	1.08	1.2	1.16	1.26

Calculation of average time per cycle:

	Observation (minutes per cycle)
Performance rating	1	2	3	4	5	6	Average time per cycle
90	0.44	0.5	0.43	0.45	0.48	0.46	0.46
85	1.5	1.54	1.47	1.51	1.49	1.52	1.505
110	0.84	0.89	0.77	0.83	0.85	0.8	0.83
100	1.1	1.14	1.08	1.2	1.16	1.26	1.156667

Excel worksheet:

Operations Management (McGraw-Hill Series in Operations and Decision Sciences), Chapter 7, Problem 3P , additional homework tip 1

Average time per cycle is calculated by taking average of all cycle in each element which is average of 0.44, 0.5, 0.43, 0.45, 0.48 and 0.46 which gives 0.46 as average time per cycle for element 1 and similar method follows for element 2, 3 and 4.

Answer 7

Chapter 7, Problem 3P

a)

Summary Introduction

To determine: The average cycle time for each operation.

Introduction: The amount of the dependency on human effort by an organization in terms of achieving its goals is given by the work design. It is directly linked to the productivity of an organization where good work design helps in achieving high productivity.

Answer 8

a)

Expert Solution

Explanation of Solution

Given information:

		Observation (minutes per cycle)
Element	Performance rating	1	2	3	4	5	6
1	90	0.44	0.5	0.43	0.45	0.48	0.46
2	85	1.5	1.54	1.47	1.51	1.49	1.52
3	110	0.84	0.89	0.77	0.83	0.85	0.8
4	100	1.1	1.14	1.08	1.2	1.16	1.26

Calculation of average time per cycle:

	Observation (minutes per cycle)
Performance rating	1	2	3	4	5	6	Average time per cycle
90	0.44	0.5	0.43	0.45	0.48	0.46	0.46
85	1.5	1.54	1.47	1.51	1.49	1.52	1.505
110	0.84	0.89	0.77	0.83	0.85	0.8	0.83
100	1.1	1.14	1.08	1.2	1.16	1.26	1.156667

Excel worksheet:

Operations Management (McGraw-Hill Series in Operations and Decision Sciences), Chapter 7, Problem 3P , additional homework tip 1

Average time per cycle is calculated by taking average of all cycle in each element which is average of 0.44, 0.5, 0.43, 0.45, 0.48 and 0.46 which gives 0.46 as average time per cycle for element 1 and similar method follows for element 2, 3 and 4.

Answer 9

a)

Expert Solution

Answer 10

a)

Expert Solution

Answer 11

Expert Solution

Answer 12

b)

Summary Introduction

To determine: The normal time for the operation.

b)

Expert Solution

Explanation of Solution

Given information:

		Observation (minutes per cycle)
Element	Performance rating	1	2	3	4	5	6
1	90	0.44	0.5	0.43	0.45	0.48	0.46
2	85	1.5	1.54	1.47	1.51	1.49	1.52
3	110	0.84	0.89	0.77	0.83	0.85	0.8
4	100	1.1	1.14	1.08	1.2	1.16	1.26

Formula:

NT = Observed time × Perform Rating = OR × PR

Calculation of normal time:

		Observation (minutes per cycle)
Element	Performance rating	1	2	3	4	5	6	Average time per cycle	NT
1	0.9	0.44	0.5	0.43	0.45	0.48	0.46	0.46	0.414
2	0.85	1.5	1.54	1.47	1.51	1.49	1.52	1.505	1.27925
3	1.1	0.84	0.89	0.77	0.83	0.85	0.8	0.83	0.913
4	1	1.1	1.14	1.08	1.2	1.16	1.26	1.156666667	1.156667

Excel worksheet:

Operations Management (McGraw-Hill Series in Operations and Decision Sciences), Chapter 7, Problem 3P , additional homework tip 2

Normal time is calculated by multiplying observed timing, 0.46 and performance rating, 0.9 which yields 0.414 minutes for element 1, 2, 3 and 4.

Answer 13

b)

Summary Introduction

To determine: The normal time for the operation.

Answer 14

b)

Expert Solution

Explanation of Solution

Given information:

		Observation (minutes per cycle)
Element	Performance rating	1	2	3	4	5	6
1	90	0.44	0.5	0.43	0.45	0.48	0.46
2	85	1.5	1.54	1.47	1.51	1.49	1.52
3	110	0.84	0.89	0.77	0.83	0.85	0.8
4	100	1.1	1.14	1.08	1.2	1.16	1.26

Formula:

NT = Observed time × Perform Rating = OR × PR

Calculation of normal time:

		Observation (minutes per cycle)
Element	Performance rating	1	2	3	4	5	6	Average time per cycle	NT
1	0.9	0.44	0.5	0.43	0.45	0.48	0.46	0.46	0.414
2	0.85	1.5	1.54	1.47	1.51	1.49	1.52	1.505	1.27925
3	1.1	0.84	0.89	0.77	0.83	0.85	0.8	0.83	0.913
4	1	1.1	1.14	1.08	1.2	1.16	1.26	1.156666667	1.156667

Excel worksheet:

Operations Management (McGraw-Hill Series in Operations and Decision Sciences), Chapter 7, Problem 3P , additional homework tip 2

Normal time is calculated by multiplying observed timing, 0.46 and performance rating, 0.9 which yields 0.414 minutes for element 1, 2, 3 and 4.

Answer 15

b)

Expert Solution

Answer 16

b)

Expert Solution

Answer 17

Expert Solution

Answer 18

c)

Summary Introduction

To determine: The standard time for the operation.

c)

Expert Solution

Explanation of Solution

Given information:

		Observation (minutes per cycle)
Element	Performance rating	1	2	3	4	5	6
1	90	0.44	0.5	0.43	0.45	0.48	0.46
2	85	1.5	1.54	1.47	1.51	1.49	1.52
3	110	0.84	0.89	0.77	0.83	0.85	0.8
4	100	1.1	1.14	1.08	1.2	1.16	1.26

Formula:

Standard time = Normal time × Allowance factor = NT × AF

Calculation of standard time:

AF job = 1+A = 1+0.15 = 1.15

Allowance factor is calculated by dividing 1 with difference of 1 and 0.15 which yields 1.15.

		Observation (minutes per cycle)
Element	Performance rating	1	2	3	4	5	6	Average time per cycle	NT	Af_job	ST
1	0.9	0.44	0.5	0.43	0.45	0.48	0.46	0.46	0.414	1.15	0.4761
2	0.85	1.5	1.54	1.47	1.51	1.49	1.52	1.505	1.27925	1.15	1.471138
3	1.1	0.84	0.89	0.77	0.83	0.85	0.8	0.83	0.913	1.15	1.04995
4	1	1.1	1.14	1.08	1.2	1.16	1.26	1.157	1.157	1.15	1.330167

Excel worksheet:

Operations Management (McGraw-Hill Series in Operations and Decision Sciences), Chapter 7, Problem 3P , additional homework tip 3

Standard time for the operation is calculated by multiplying normal time of 0.414 minutes with allowance factor of 1.15 which gives 0.4761 minutes for element 1 and same procedure goes with element 2, 3 and 4.

Answer 19

c)

Summary Introduction

To determine: The standard time for the operation.

Answer 20

c)

Expert Solution

Explanation of Solution

Given information:

		Observation (minutes per cycle)
Element	Performance rating	1	2	3	4	5	6
1	90	0.44	0.5	0.43	0.45	0.48	0.46
2	85	1.5	1.54	1.47	1.51	1.49	1.52
3	110	0.84	0.89	0.77	0.83	0.85	0.8
4	100	1.1	1.14	1.08	1.2	1.16	1.26

Formula:

Standard time = Normal time × Allowance factor = NT × AF

Calculation of standard time:

AF job = 1+A = 1+0.15 = 1.15

Allowance factor is calculated by dividing 1 with difference of 1 and 0.15 which yields 1.15.

		Observation (minutes per cycle)
Element	Performance rating	1	2	3	4	5	6	Average time per cycle	NT	Af_job	ST
1	0.9	0.44	0.5	0.43	0.45	0.48	0.46	0.46	0.414	1.15	0.4761
2	0.85	1.5	1.54	1.47	1.51	1.49	1.52	1.505	1.27925	1.15	1.471138
3	1.1	0.84	0.89	0.77	0.83	0.85	0.8	0.83	0.913	1.15	1.04995
4	1	1.1	1.14	1.08	1.2	1.16	1.26	1.157	1.157	1.15	1.330167

Excel worksheet:

Operations Management (McGraw-Hill Series in Operations and Decision Sciences), Chapter 7, Problem 3P , additional homework tip 3

Standard time for the operation is calculated by multiplying normal time of 0.414 minutes with allowance factor of 1.15 which gives 0.4761 minutes for element 1 and same procedure goes with element 2, 3 and 4.