Chapter 7, Problem 2CCSR

To determine

To find the equation whose solutions are $\left(2,-6\right)\&\left(-3,4\right)$ .

Answer to Problem 2CCSR

  $y=-2x-2$ & option I is correct.

Explanation of Solution

Given:

  $\left(2,-6\right)\&\left(-3,4\right)$

Concept used:

Equation of a line passing through the points $\left(x_1,y_1\right)\&\left(x_2,y_2\right)$ is,

  $y-y_1=\frac{y_2-y_1}{x_2-x_1}\left(x-x_1\right)$

Calculation:

The equation whose solutions are $\left(2,-6\right)\&\left(-3,4\right)$ is,

  $\begin{array}{l}y-\left(-6\right)=\frac{4-\left(-6\right)}{-3-2}\left(x-2\right)\\ \Rightarrow y+6=-2\left(x-2\right)\\ \Rightarrow y+6=-2x+4\\ \Rightarrow y=-2x-2\end{array}$

Hence option I is correct.