Chapter 7.2, Problem 60MR

To determine

To Solve: The system $\begin{array}{l}2x-y=-3\\ x-y=1\end{array}$ .

Answer to Problem 60MR

The required solution is $\left(-4,-5\right)$ .

Explanation of Solution

Given information:

The system $\begin{array}{l}2x-y=-3\\ x-y=1\end{array}$

Calculation:

  $\begin{array}{l}2x-y=-3\\ x-y=1\end{array}$

(Write the system of equations)

  $\begin{array}{l}2x-y=-3\\ \underset{\_}{x-y=1}\\ x+0=-4\end{array}$

(Subtract the equations)

  $x=-4$

(Solve for x)

Now solve for the eliminated variable. Use either of the original equations

  $x-y=1$

(Write the second equation)

  $-4-y=1$

(Substitute -4 for x)

  $y=-5$

(Solve for y)

Thus the solution is $\left(-4,-5\right)$ .