Chapter 7, Problem 22GR

To determine

To find the range of the function $f\left(x\right)=-2x^2$ with domain $\left\{-2,0,3.5\right\}$ .

Answer to Problem 22GR

  $\left\{-8,0,-24.5\right\}$

Explanation of Solution

Given:

  $f\left(x\right)=-2x^2$ whose domain is $\left\{-2,0,3.5\right\}$ .

Calculation:

Put $x=-2$ in $f\left(x\right)=-2x^2$ , we get

  $\begin{array}{l}f\left(x\right)=-2{\left(-2\right)}^2\\ =-8\end{array}$

Put $x=0$ in $f\left(x\right)=-2x^2$ , we get

  $\begin{array}{l}f\left(0\right)=-2{\left(0\right)}^2\\ =0\end{array}$

Put $x=3.5$ in $f\left(x\right)=-2x^2$ , we get

  $\begin{array}{l}f\left(0\right)=-2{\left(3.5\right)}^2\\ =-24.5\end{array}$

Therefore the range is,

  $\left\{-8,0,-24.5\right\}$