Chapter 7.1, Problem 26PPE

To determine

To Simplify: The expression $k^{-4}{j}^o$

Answer to Problem 26PPE

The required solution is $\frac{1}{k^4}$

Explanation of Solution

Given information:

  $k^{-4}{j}^o$

Concept Used:

Negative Exponent:

  $a^{-n}=\frac{1}{a^n}$

Where a is a non-zero number and n is an integer

Zero as an Exponent:

  $a^0=1$

Where a is a non-zero number.

Calculation:

  $k^{-4}{j}^o$

Applying Negative Exponent concept

  $=\frac{j^o}{k^4}$

Applying Zero as an Exponent concept

  $=\frac{1}{k^4}$