The reason behind the sugar alcohol (monosaccharide derivatives) is no longer designated as D or L. Introduction: Monosaccharide having five carbons is known as pentose. The molecular formula of carbohydrate is C n (H 2 O) n where n represents a whole number like 3 or higher. Monosaccharide contains various functional groups like alcohol, aldehyde or ketone groups.

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Answer 1

Question

Chapter 7, Problem 1P

Summary Introduction

To explain: The reason behind the sugar alcohol (monosaccharide derivatives) is no longer designated as D or L.

Introduction:

Monosaccharide having five carbons is known as pentose. The molecular formula of carbohydrate is C_n(H₂O)_n where n represents a whole number like 3 or higher. Monosaccharide contains various functional groups like alcohol, aldehyde or ketone groups.

Expert Solution & Answer

Answer to Problem 1P

Answer: Fig.1 represents the structure of glyceraldehyde.

Pictorial representation: Fig.1 represents the structure of glyceraldehyde.

Loose-leaf Version for Lehninger Principles of Biochemistry 7E & SaplingPlus for Lehninger Principles of Biochemistry 7E (Six-Month Access), Chapter 7, Problem 1P

Fig.1: Structure of glyceraldehyde.

Explanation of Solution

Explanation:

Glyceraldehyde belongs to a group of monosaccharide and chemical formula for glyceraldehyde is C₃H₆O₃. The carbonyl group present at 1^st position of glyceraldehyde gets reduced into hydroxyl group. This reduction of carbonyl group results in the formation of glycerol structure. Fig.1 represents the structure of glyceraldehyde.

If the central carbon atom of a compound is bonded with four different functional groups, then the compound is said to be non-super imposable. On the basis of the arrangement of H and OH group present in chiral carbon atom, the compound is designated as D or L forms. L-form of glyceraldehyde has the -OH groups at the chiral center present far from carbonyl on the left side of the molecule. In D-form, glyceraldehyde has the -OH groups at the chiral center present far from carbonyl on the right side of the molecule. In glycerol, there is no chiral carbon is present. Thus, the sugar alcohol is no longer designated as D or L-form.

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Students have asked these similar questions

The beta-lactamase hydrolyzes the lactam-ring in penicillin. Describe the mechanism of hydrolysis, insuring to include the involvement of S, D, & K in the reaction sequence. Please help

To map the active site of beta-lactamase, the enzyme was hydrolyzed with trypsin to yield a hexapeptide (P1) with the following amino acids. Glu, Lys, Leu, Phe, Met, and Ser. Treatment of P1 with phenyl isothiocyanate yielded a PTH derivative of phenylalanine and a peptide (P2). Treatment of P1 with cyanogenbromide gave an acidic tetrapeptide (P3) and a dipeptide (P4).Treatment of P2 with 1-fluoro-2,4-dinitrobenzene, followed by complete hydrolysis, yields N-2,4-dinitrophenyl-Glu. P1, P2, and P3 contain the active site serine. Why doesn't D in this hexapeptide not participate in the hydrolysis of the beta-lactam ring even though S, K, and D are involved in the catalyst?

To map the active site of -lactamase, the enzyme was hydrolyzed with trypsin to yield a hexapeptide (P1) with the following amino acids. Glu, Lys, Leu, Phe, Met, and Ser. Treatment of P1 with phenyl isothiocyanate yielded a PTH derivative of phenylalanine and a peptide (P2). Treatment of P1 with cyanogenbromide gave an acidic tetrapeptide (P3) and a dipeptide (P4).Treatment of P2 with 1-fluoro-2,4-dinitrobenzene, followed by complete hydrolysis, yields N-2,4-dinitrophenyl-Glu. P1, P2, and P3 contain the active site serine. Using the experimental results described above derive the primary sequence of the active site hexapeptide. Please help!

Answer 2

Question

Chapter 7, Problem 1P

Summary Introduction

To explain: The reason behind the sugar alcohol (monosaccharide derivatives) is no longer designated as D or L.

Introduction:

Monosaccharide having five carbons is known as pentose. The molecular formula of carbohydrate is C_n(H₂O)_n where n represents a whole number like 3 or higher. Monosaccharide contains various functional groups like alcohol, aldehyde or ketone groups.

Expert Solution & Answer

Answer to Problem 1P

Answer: Fig.1 represents the structure of glyceraldehyde.

Pictorial representation: Fig.1 represents the structure of glyceraldehyde.

Loose-leaf Version for Lehninger Principles of Biochemistry 7E & SaplingPlus for Lehninger Principles of Biochemistry 7E (Six-Month Access), Chapter 7, Problem 1P

Fig.1: Structure of glyceraldehyde.

Explanation of Solution

Explanation:

Glyceraldehyde belongs to a group of monosaccharide and chemical formula for glyceraldehyde is C₃H₆O₃. The carbonyl group present at 1^st position of glyceraldehyde gets reduced into hydroxyl group. This reduction of carbonyl group results in the formation of glycerol structure. Fig.1 represents the structure of glyceraldehyde.

If the central carbon atom of a compound is bonded with four different functional groups, then the compound is said to be non-super imposable. On the basis of the arrangement of H and OH group present in chiral carbon atom, the compound is designated as D or L forms. L-form of glyceraldehyde has the -OH groups at the chiral center present far from carbonyl on the left side of the molecule. In D-form, glyceraldehyde has the -OH groups at the chiral center present far from carbonyl on the right side of the molecule. In glycerol, there is no chiral carbon is present. Thus, the sugar alcohol is no longer designated as D or L-form.

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Answer 3

Question

Chapter 7, Problem 1P

Summary Introduction

To explain: The reason behind the sugar alcohol (monosaccharide derivatives) is no longer designated as D or L.

Introduction:

Monosaccharide having five carbons is known as pentose. The molecular formula of carbohydrate is C_n(H₂O)_n where n represents a whole number like 3 or higher. Monosaccharide contains various functional groups like alcohol, aldehyde or ketone groups.

Expert Solution & Answer

Answer to Problem 1P

Answer: Fig.1 represents the structure of glyceraldehyde.

Pictorial representation: Fig.1 represents the structure of glyceraldehyde.

Loose-leaf Version for Lehninger Principles of Biochemistry 7E & SaplingPlus for Lehninger Principles of Biochemistry 7E (Six-Month Access), Chapter 7, Problem 1P

Fig.1: Structure of glyceraldehyde.

Explanation of Solution

Explanation:

Glyceraldehyde belongs to a group of monosaccharide and chemical formula for glyceraldehyde is C₃H₆O₃. The carbonyl group present at 1^st position of glyceraldehyde gets reduced into hydroxyl group. This reduction of carbonyl group results in the formation of glycerol structure. Fig.1 represents the structure of glyceraldehyde.

If the central carbon atom of a compound is bonded with four different functional groups, then the compound is said to be non-super imposable. On the basis of the arrangement of H and OH group present in chiral carbon atom, the compound is designated as D or L forms. L-form of glyceraldehyde has the -OH groups at the chiral center present far from carbonyl on the left side of the molecule. In D-form, glyceraldehyde has the -OH groups at the chiral center present far from carbonyl on the right side of the molecule. In glycerol, there is no chiral carbon is present. Thus, the sugar alcohol is no longer designated as D or L-form.

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Answer 4

Question

Chapter 7, Problem 1P

Summary Introduction

To explain: The reason behind the sugar alcohol (monosaccharide derivatives) is no longer designated as D or L.

Introduction:

Monosaccharide having five carbons is known as pentose. The molecular formula of carbohydrate is C_n(H₂O)_n where n represents a whole number like 3 or higher. Monosaccharide contains various functional groups like alcohol, aldehyde or ketone groups.

Expert Solution & Answer

Answer to Problem 1P

Answer: Fig.1 represents the structure of glyceraldehyde.

Pictorial representation: Fig.1 represents the structure of glyceraldehyde.

Loose-leaf Version for Lehninger Principles of Biochemistry 7E & SaplingPlus for Lehninger Principles of Biochemistry 7E (Six-Month Access), Chapter 7, Problem 1P

Fig.1: Structure of glyceraldehyde.

Explanation of Solution

Explanation:

Glyceraldehyde belongs to a group of monosaccharide and chemical formula for glyceraldehyde is C₃H₆O₃. The carbonyl group present at 1^st position of glyceraldehyde gets reduced into hydroxyl group. This reduction of carbonyl group results in the formation of glycerol structure. Fig.1 represents the structure of glyceraldehyde.

If the central carbon atom of a compound is bonded with four different functional groups, then the compound is said to be non-super imposable. On the basis of the arrangement of H and OH group present in chiral carbon atom, the compound is designated as D or L forms. L-form of glyceraldehyde has the -OH groups at the chiral center present far from carbonyl on the left side of the molecule. In D-form, glyceraldehyde has the -OH groups at the chiral center present far from carbonyl on the right side of the molecule. In glycerol, there is no chiral carbon is present. Thus, the sugar alcohol is no longer designated as D or L-form.

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Answer 5

Chapter 7, Problem 1P

Summary Introduction

To explain: The reason behind the sugar alcohol (monosaccharide derivatives) is no longer designated as D or L.

Introduction:

Monosaccharide having five carbons is known as pentose. The molecular formula of carbohydrate is C_n(H₂O)_n where n represents a whole number like 3 or higher. Monosaccharide contains various functional groups like alcohol, aldehyde or ketone groups.

Expert Solution & Answer

Answer to Problem 1P

Answer: Fig.1 represents the structure of glyceraldehyde.

Pictorial representation: Fig.1 represents the structure of glyceraldehyde.

Loose-leaf Version for Lehninger Principles of Biochemistry 7E & SaplingPlus for Lehninger Principles of Biochemistry 7E (Six-Month Access), Chapter 7, Problem 1P

Fig.1: Structure of glyceraldehyde.

Explanation of Solution

Explanation:

Glyceraldehyde belongs to a group of monosaccharide and chemical formula for glyceraldehyde is C₃H₆O₃. The carbonyl group present at 1^st position of glyceraldehyde gets reduced into hydroxyl group. This reduction of carbonyl group results in the formation of glycerol structure. Fig.1 represents the structure of glyceraldehyde.

If the central carbon atom of a compound is bonded with four different functional groups, then the compound is said to be non-super imposable. On the basis of the arrangement of H and OH group present in chiral carbon atom, the compound is designated as D or L forms. L-form of glyceraldehyde has the -OH groups at the chiral center present far from carbonyl on the left side of the molecule. In D-form, glyceraldehyde has the -OH groups at the chiral center present far from carbonyl on the right side of the molecule. In glycerol, there is no chiral carbon is present. Thus, the sugar alcohol is no longer designated as D or L-form.

Answer 6

Chapter 7, Problem 1P

Summary Introduction

To explain: The reason behind the sugar alcohol (monosaccharide derivatives) is no longer designated as D or L.

Introduction:

Monosaccharide having five carbons is known as pentose. The molecular formula of carbohydrate is C_n(H₂O)_n where n represents a whole number like 3 or higher. Monosaccharide contains various functional groups like alcohol, aldehyde or ketone groups.

Expert Solution & Answer

Answer to Problem 1P

Answer: Fig.1 represents the structure of glyceraldehyde.

Pictorial representation: Fig.1 represents the structure of glyceraldehyde.

Loose-leaf Version for Lehninger Principles of Biochemistry 7E & SaplingPlus for Lehninger Principles of Biochemistry 7E (Six-Month Access), Chapter 7, Problem 1P

Fig.1: Structure of glyceraldehyde.

Explanation of Solution

Explanation:

Glyceraldehyde belongs to a group of monosaccharide and chemical formula for glyceraldehyde is C₃H₆O₃. The carbonyl group present at 1^st position of glyceraldehyde gets reduced into hydroxyl group. This reduction of carbonyl group results in the formation of glycerol structure. Fig.1 represents the structure of glyceraldehyde.

If the central carbon atom of a compound is bonded with four different functional groups, then the compound is said to be non-super imposable. On the basis of the arrangement of H and OH group present in chiral carbon atom, the compound is designated as D or L forms. L-form of glyceraldehyde has the -OH groups at the chiral center present far from carbonyl on the left side of the molecule. In D-form, glyceraldehyde has the -OH groups at the chiral center present far from carbonyl on the right side of the molecule. In glycerol, there is no chiral carbon is present. Thus, the sugar alcohol is no longer designated as D or L-form.

Answer 7

Chapter 7, Problem 1P

Summary Introduction

To explain: The reason behind the sugar alcohol (monosaccharide derivatives) is no longer designated as D or L.

Introduction:

Monosaccharide having five carbons is known as pentose. The molecular formula of carbohydrate is C_n(H₂O)_n where n represents a whole number like 3 or higher. Monosaccharide contains various functional groups like alcohol, aldehyde or ketone groups.

Answer 8

Expert Solution & Answer

Answer to Problem 1P

Answer: Fig.1 represents the structure of glyceraldehyde.

Pictorial representation: Fig.1 represents the structure of glyceraldehyde.

Loose-leaf Version for Lehninger Principles of Biochemistry 7E & SaplingPlus for Lehninger Principles of Biochemistry 7E (Six-Month Access), Chapter 7, Problem 1P

Fig.1: Structure of glyceraldehyde.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Explanation of Solution

Explanation:

Glyceraldehyde belongs to a group of monosaccharide and chemical formula for glyceraldehyde is C₃H₆O₃. The carbonyl group present at 1^st position of glyceraldehyde gets reduced into hydroxyl group. This reduction of carbonyl group results in the formation of glycerol structure. Fig.1 represents the structure of glyceraldehyde.

If the central carbon atom of a compound is bonded with four different functional groups, then the compound is said to be non-super imposable. On the basis of the arrangement of H and OH group present in chiral carbon atom, the compound is designated as D or L forms. L-form of glyceraldehyde has the -OH groups at the chiral center present far from carbonyl on the left side of the molecule. In D-form, glyceraldehyde has the -OH groups at the chiral center present far from carbonyl on the right side of the molecule. In glycerol, there is no chiral carbon is present. Thus, the sugar alcohol is no longer designated as D or L-form.

Answer 12

Ch. 7 - Prob. 1P Ch. 7 - Prob. 2P Ch. 7 - Prob. 3P Ch. 7 - Prob. 4P Ch. 7 - Prob. 5P Ch. 7 - Prob. 6P Ch. 7 - Prob. 7P Ch. 7 - Prob. 8P Ch. 7 - Prob. 9P Ch. 7 - Prob. 10P

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