Principles of Information Systems (MindTap Course List)
13th Edition
ISBN: 9781305971776
Author: Ralph Stair, George Reynolds
Publisher: Cengage Learning
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Chapter 7, Problem 12RQ
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Market Segmentation:
- Market segmentation is a method of dividing the market or of customers into different segments. Here, the segmentation is performed according to their characters...
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Purpose of market segmentation:
The purpose of market segmentation is to divide the pool of potential custom...
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1. Unsigned Integers
If we have an n-digit unsigned numeral dn-1d n-2...do in radix (or base) r, then the value of that
numeral is
n−1
r² di
Σi=0
which is basically saying that instead of a 10's or 100's place we have an r's or
r²'s place. For binary, decimal, and hex r equals 2, 10, and 16, respectively.
Just a reminder that in order to write down a large number, we typically use the IEC or SI
prefixing system:
IEC: Ki = 210, Mi = 220, Gi = 230, Ti = 240, Pi = 250, Ei = 260, Zi = 270, Yi = 280;
SI: K=103, M = 106, G = 109, T = 10¹², P = 1015, E = 10¹8, Z = 1021, Y = 1024.
1.1 Conversions
a. (15 pts) Write the following using IEC prefixes: 213, 223, 251, 272, 226, 244
21323 Ki8 Ki
223 23 Mi 8 Mi
b. (15 pts) Write the following using SI prefixes: 107, 10¹7, 10¹¹, 1022, 1026, 1015
107 10¹ M = 10 M
=
1017102 P = 100 P
c. (10 pts) Write the following with powers of 10: 7 K, 100 E, 21 G
7 K = 7*10³
answer shoul avoid using AI and should be basic and please explain
Chapter 7 Solutions
Principles of Information Systems (MindTap Course List)
Ch. 7.1 - Prob. 1RQCh. 7.1 - Prob. 2RQCh. 7.1 - Prob. 1CTQCh. 7.1 - Prob. 2CTQCh. 7.2 - Prob. 1RQCh. 7.2 - Prob. 2RQCh. 7.2 - Prob. 1CTQCh. 7.2 - Prob. 2CTQCh. 7.3 - Prob. 1RQCh. 7.3 - Prob. 2RQ
Ch. 7.3 - Prob. 1CTQCh. 7.3 - Prob. 2CTQCh. 7.4 - Prob. 1RQCh. 7.4 - Prob. 2RQCh. 7.4 - Prob. 1CTQCh. 7.4 - Prob. 2CTQCh. 7.5 - Prob. 1RQCh. 7.5 - Prob. 2RQCh. 7.5 - Prob. 1CTQCh. 7.5 - Prob. 2CTQCh. 7 - Prob. 1SATCh. 7 - Prob. 2SATCh. 7 - Prob. 3SATCh. 7 - Prob. 4SATCh. 7 - Prob. 5SATCh. 7 - Prob. 6SATCh. 7 - Prob. 7SATCh. 7 - Prob. 8SATCh. 7 - Prob. 9SATCh. 7 - Prob. 10SATCh. 7 - Prob. 11SATCh. 7 - Prob. 12SATCh. 7 - Prob. 13SATCh. 7 - Prob. 14SATCh. 7 - Prob. 15SATCh. 7 - Prob. 16SATCh. 7 - Prob. 17SATCh. 7 - Prob. 1RQCh. 7 - Prob. 2RQCh. 7 - Prob. 3RQCh. 7 - Prob. 4RQCh. 7 - Prob. 5RQCh. 7 - Prob. 6RQCh. 7 - Prob. 7RQCh. 7 - Prob. 8RQCh. 7 - Prob. 9RQCh. 7 - Prob. 10RQCh. 7 - Prob. 11RQCh. 7 - Prob. 12RQCh. 7 - Prob. 13RQCh. 7 - Prob. 14RQCh. 7 - Prob. 15RQCh. 7 - Prob. 16RQCh. 7 - Prob. 17RQCh. 7 - Prob. 18RQCh. 7 - Prob. 1DQCh. 7 - Prob. 2DQCh. 7 - Prob. 3DQCh. 7 - Prob. 4DQCh. 7 - Prob. 5DQCh. 7 - Prob. 6DQCh. 7 - Prob. 7DQCh. 7 - Prob. 8DQCh. 7 - Prob. 9DQCh. 7 - Prob. 10DQCh. 7 - Prob. 11DQCh. 7 - Prob. 12DQCh. 7 - Prob. 2PSECh. 7 - Prob. 3PSECh. 7 - Prob. 1TACh. 7 - Prob. 2TACh. 7 - Prob. 3TACh. 7 - Prob. 2WECh. 7 - Prob. 1CECh. 7 - Prob. 2CECh. 7 - Prob. 3CECh. 7 - Prob. 1CTQ1Ch. 7 - Prob. 2CTQ1Ch. 7 - Prob. 3CTQ1Ch. 7 - Prob. 1CTQ2Ch. 7 - Prob. 2CTQ2Ch. 7 - Prob. 3CTQ2
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- answer should avoid using AI (such as ChatGPT), do not any answer directly copied from AI would and explain codearrow_forwardWrite a c++ program that will count from 1 to 10 by 1. The default output should be: 1, 2, 3, 4, 5, 6 , 7, 8, 9, 10 There should be only a newline after the last number. Each number except the last should be followed by a comma and a space. To make your program more functional, you should parse command line arguments and change behavior based on their values. Argument Parameter Action -f, --first yes, an integer Change place you start counting -l, --last yes, an integer Change place you end counting -s, --skip optional, an integer, 1 if not specified Change the amount you add to the counter each iteration -h, —help none Print a help message including these instructions. -j, --joke none Tell a number based joke. So, if your program is called counter, counter -f 10 --last 4 --skip 2 should produce 10, 8, 6, 4 Please use the last supplied argument. If your code is called counter, counter -f 4 -f 5 -f 6 should count from 6. You should…arrow_forwardshow workarrow_forward
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