Mark 10 The program below uses pointer arithmetic to determine the size of a 'char' variable. By using pointer arithmetic we can find out the value of 'cp' and the value of 'cp+1'. Since cp is a pointer, this addition involves pointer arithmetic: adding one to a pointer makes the pointer point to the next element of the same type. For a pointer to a char, adding 1 really just means adding 1 to the address, but this is only because each char is 1 byte. 1. 2. Compile and run the program and see what it does. (2 Marks) Write some code that does pointer arithmetic with a pointer to an int and determine how big an int is before and after adding a 1. (4 Marks) 3. Same idea figure out how big a double is, by using pointer arithmetic and printing out the value of the pointer before and after adding a 1. (4 Marks) #include int main() { char c='2'; char *cp = &c; printf("cp is 0x%08x\n", cp); printf("The character at cp is %c\n", *cp); /* Pointer arithmetic see what cp+1 is */ cp = cp+1; printf("cp is 0x%08x\n", cp); /* Do not print *cp, because it points to memory not allocated to your program */ return 0; }
Mark 10 The program below uses pointer arithmetic to determine the size of a 'char' variable. By using pointer arithmetic we can find out the value of 'cp' and the value of 'cp+1'. Since cp is a pointer, this addition involves pointer arithmetic: adding one to a pointer makes the pointer point to the next element of the same type. For a pointer to a char, adding 1 really just means adding 1 to the address, but this is only because each char is 1 byte. 1. 2. Compile and run the program and see what it does. (2 Marks) Write some code that does pointer arithmetic with a pointer to an int and determine how big an int is before and after adding a 1. (4 Marks) 3. Same idea figure out how big a double is, by using pointer arithmetic and printing out the value of the pointer before and after adding a 1. (4 Marks) #include int main() { char c='2'; char *cp = &c; printf("cp is 0x%08x\n", cp); printf("The character at cp is %c\n", *cp); /* Pointer arithmetic see what cp+1 is */ cp = cp+1; printf("cp is 0x%08x\n", cp); /* Do not print *cp, because it points to memory not allocated to your program */ return 0; }
C++ for Engineers and Scientists
4th Edition
ISBN:9781133187844
Author:Bronson, Gary J.
Publisher:Bronson, Gary J.
Chapter10: Pointers
Section10.3: Pointer Arithmetic
Problem 5E
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Question
Please answer the exercise below(C programme)

Transcribed Image Text:Mark
10
The program below uses pointer arithmetic to determine the size of a 'char' variable. By
using pointer arithmetic we can find out the value of 'cp' and the value of 'cp+1'. Since cp
is a pointer, this addition involves pointer arithmetic: adding one to a pointer makes the
pointer point to the next element of the same type.
For a pointer to a char, adding 1 really just means adding 1 to the address, but this is only
because each char is 1 byte.
1.
2.
Compile and run the program and see what it does. (2 Marks)
Write some code that does pointer arithmetic with a pointer to an int and
determine how big an int is before and after adding a 1. (4 Marks)
3. Same idea figure out how big a double is, by using pointer arithmetic and
printing out the value of the pointer before and after adding a 1. (4 Marks)
#include <stdio.h>
int main()
{
char c='2';
char *cp = &c;
printf("cp is 0x%08x\n", cp);
printf("The character at cp is %c\n", *cp);
/* Pointer arithmetic see what cp+1 is */
cp = cp+1;
printf("cp is 0x%08x\n", cp);
/* Do not print *cp, because it points to
memory not allocated to your program */
return 0;
}
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