Chapter 7, Problem 105AE

Consider the following equations:

$\begin{array}{lllll}3\text{A}\hfill & +6\text{B}\hfill & \to 3\text{D}\hfill & \Delta H\hfill & =-403\text{KJ/mol}\hfill \\ \text{E}\hfill & +2\text{F}\hfill & \to \text{A}\hfill & \Delta H\hfill & =-105.2\text{KJ/mol}\hfill \\ \hfill & C\hfill & \to \text{E+3D}\hfill & \Delta H\hfill & =64.8KJ/mol\hfill \end{array}$

Suppose the first equation is reversed and multiplied by $\frac{1}{6}$, the second and third equations are divided by 2, and the three adjusted equations are added. What is the net reaction and what is the overall heat of this reaction?