Explanation Work is referred to as the amount of energy that is required to perform any substantial task. If constant force is applied, then the work is simply given by the following equation W = F × d Where W = W o r k d o n e F = C o n s t a n t F o r c e d = d i s t a n c e t h r o u g h w h i c h t h e f o r c e a c t s If the force applied is not constant and changes over time, then integral equation is used to calculate the work done. W = ∫ x = a x = b f ( x ) d x Where, W = W o r k d o n e f ( x ) = f o r c e a s a f u n c t i o n o f d i s t a n c e x = d i s t a n c e t h r o u g h w h i c h t h e f o r c e a c t s Given: The tank is full Formula Used: We know that force is given as F = m a or F = m g , where is acceleration due to gravity. Also, Mass, m = V D , where V is the volume of the object and d is the density. Thus, force is given as F = D V g Calculation: First determine the level H at which the water in the tank is equal to one-half of the total capacity of the water...

4th Edition

ISBN: 9781319050733

Author: Rogawski

Publisher: MAC HIGHER

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Chapter 6.5, Problem 25E

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Work done required to pump out half of the water, given that the tank is full.

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Chapter 6.5, Problem 24E

Chapter 6.5, Problem 26E

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Work done required to pump out half of the water, given that the tank is full.

Solution Summary: The author explains that the work required to pump out half of the water is approximately 3.79 10 6 J o u l e

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Work done required to pump out half of the water, given that the tank is full.

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Chapter 6 Solutions