Explanation Work is defined as the amount of energy needed to perform any physical task. If constant force is applied, then the work is simply given by the following equation W = F × d Where W = W o r k d o n e F = C o n s t a n t F o r c e d = d i s t a n c e t h r o u g h w h i c h t h e f o r c e a c t s If the force applied is not constant and changes over time, then integral equation is used to calculate the work done. W = ∫ x = a x = b f ( x ) d x Where, W = W o r k d o n e f ( x ) = f o r c e a s a f u n c t i o n o f d i s t a n c e x = d i s t a n c e t h r o u g h w h i c h t h e f o r c e a c t s Given: Given a stone of density 2000 k g / m 3 out of which a pyramid of height 146 m and a square base of side 230 m is needed to be built. Formula Used: We know that force or weight is given as F = m a or F = m g , where is acceleration due to gravity. Also, Mass, m = V D , where V is the volume of the object and d is the density...

4th Edition

ISBN: 9781319050733

Author: Rogawski

Publisher: MAC HIGHER

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Question

Chapter 6.5, Problem 15E

To determine

The work done against the gravity to build a pyramid of height $146 m$ and a square base of side $230 m$ from the stone of density $2000 k g / m^{3}$

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Chapter 6.5, Problem 14E

Chapter 6.5, Problem 16E

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Chapter 6 Solutions

CALCULUS (CLOTH)

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The work done against the gravity to build a pyramid of height 146 m and a square base of side 230 m from the stone of density 2000 k g / m 3

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The work done against the gravity to build a pyramid of height 146 m and a square base of side 230 m from the stone of density 2000 kg/m3

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Chapter 6 Solutions

The work done against the gravity to build a pyramid of height $146 m$ and a square base of side $230 m$ from the stone of density $2000 k g / m^{3}$