Explanation Given: The solid whose base is the semicircle y = 9 − x 2 and cross section perpendicular to x -axis is square. Calculation: For each x , the base of the square cross section extends from the semicircle y = 9 − x 2 to the x -axis. Therefore, the side (s) length of the square is given by; ⇒ s = 9 − x 2 So, the area (let us consider, A) of square is given by; ⇒ A = ( s ) 2 = ( 9 − x 2 ) 2 ∴ A = 9 − x 2 Finally, the volume V of the solid is given by; ⇒ V = ∫ − 3 3

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ISBN: 9781319050733

Author: Rogawski

Publisher: MAC HIGHER

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Chapter 6.2, Problem 11E

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Find the volume $V$ of solid whose base is the semicircle $y = \sqrt{9 - x^{2}}$ , where $- 3 \leq x \leq 3$ .The cross section perpendicular to $x$ -axis is square.

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Chapter 6.2, Problem 10E

Chapter 6.2, Problem 12E

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Find the volume V of solid whose base is the semicircle y = 9 − x 2 , where − 3 ≤ x ≤ 3 .The cross section perpendicular to x -axis is square.

Solution Summary: The author calculates the volume V of a solid whose base is the semicircle y = 9 x 2 and the cross section perpendicular to X -axis is square.

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Find the volume $V$ of solid whose base is the semicircle $y = \sqrt{9 - x^{2}}$ , where $- 3 \leq x \leq 3$ .The cross section perpendicular to $x$ -axis is square.

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Chapter 6 Solutions

Find the volume V of solid whose base is the semicircle y = 9 − x 2 , where − 3 ≤ x ≤ 3 .The cross section perpendicular to x -axis is square.

Solution Summary: The author calculates the volume V of a solid whose base is the semicircle y = 9 x 2 and the cross section perpendicular to X -axis is square.

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Find the volume V of solid whose base is the semicircle y=9−x2, where −3≤x≤3.The cross section perpendicular to x-axis is square.

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Chapter 6 Solutions

Find the volume $V$ of solid whose base is the semicircle $y = \sqrt{9 - x^{2}}$ , where $- 3 \leq x \leq 3$ .The cross section perpendicular to $x$ -axis is square.