Explanation Given: p ( r ) = 4 ( 1 + r 2 ) 1 3 (in thousands per square mile) Calculation: We have been given that, radius considered=10 mile and radial population density = p ( r ) = 4 ( 1 + r 2 ) 1 3 which varies from centre of city 0 to radius considered 10. To calculate the population in the given circle, thin rings inside the circle are considered, as shown below, Now, if we straightened out each ring we get rectangular strips, with length as the circumference of that ring 2πr (r is radius of the ring) and breadth as the difference in radius dr Therefore, area of ring = 2πr*dr square miles Therefore, Population of ring = area of ring* radial population density Therefore, total population, P in thousands = sum of (area of ring*radial population density) = integral of 2πrdr* radial population density p(r) (in thousands per square mile) P = ∫ 0 10 2 π r p ( r ) d r P = 2 π ∫ 0 10 r p ( r ) d r ∴ P = 2 π ∫ 0 10 r 4 ( 1 + r 2 ) 1 3 d r ∴ P = 2 π × 4 ∫ 0 10 r ( 1 + r 2 ) 1 3 d r ∴ P = 8 π ∫ 0 10 r ( 1 + r 2 ) 1 3 d r L e t , u = 1 + r 2 d u = 2 r d r ∴ r d r = d u 2 ∴ P = 8 π ∫ 0 10 u 1 3 d u 2 ∴ P = 8 π × 1 2 ∫ 0 10 u 1 3 d u ∴...

4th Edition

ISBN: 9781319050733

Author: Rogawski

Publisher: MAC HIGHER

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Question

Chapter 6.2, Problem 29E

To determine

To calculate: the total population within a 10-mile radius of the city centre if the radial population density is $p (r) = 4 {(1 + r^{2})}^{\frac{1}{3}}$ (in thousands per square mile)

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Chapter 6.2, Problem 28E

Chapter 6.2, Problem 30E

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Chapter 6 Solutions

CALCULUS (CLOTH)

Ch. 6.1 - Prob. 1PQ Ch. 6.1 - Prob. 2PQ Ch. 6.1 - Prob. 3PQ Ch. 6.1 - Prob. 4PQ Ch. 6.1 - Prob. 5PQ Ch. 6.1 - Prob. 6PQ Ch. 6.1 - Prob. 1E Ch. 6.1 - Prob. 2E Ch. 6.1 - Prob. 3E Ch. 6.1 - Prob. 4E

Ch. 6.1 - Prob. 5E Ch. 6.1 - Prob. 6E Ch. 6.1 - Prob. 7E Ch. 6.1 - Prob. 8E Ch. 6.1 - Prob. 9E Ch. 6.1 - Prob. 10E Ch. 6.1 - Prob. 11E Ch. 6.1 - Prob. 12E Ch. 6.1 - Prob. 13E Ch. 6.1 - Prob. 14E Ch. 6.1 - Prob. 15E Ch. 6.1 - Prob. 16E Ch. 6.1 - Prob. 17E Ch. 6.1 - Prob. 18E Ch. 6.1 - Prob. 19E Ch. 6.1 - Prob. 20E Ch. 6.1 - Prob. 21E Ch. 6.1 - Prob. 22E Ch. 6.1 - Prob. 23E Ch. 6.1 - Prob. 24E Ch. 6.1 - Prob. 25E Ch. 6.1 - Prob. 26E Ch. 6.1 - Prob. 27E Ch. 6.1 - Prob. 28E Ch. 6.1 - Prob. 29E Ch. 6.1 - Prob. 30E Ch. 6.1 - Prob. 31E Ch. 6.1 - Prob. 32E Ch. 6.1 - Prob. 33E Ch. 6.1 - Prob. 34E Ch. 6.1 - Prob. 35E Ch. 6.1 - Prob. 36E Ch. 6.1 - Prob. 37E Ch. 6.1 - Prob. 38E Ch. 6.1 - Prob. 39E Ch. 6.1 - Prob. 40E Ch. 6.1 - Prob. 41E Ch. 6.1 - Prob. 42E Ch. 6.1 - Prob. 43E Ch. 6.1 - Prob. 44E Ch. 6.1 - Prob. 45E Ch. 6.1 - Prob. 46E Ch. 6.1 - Prob. 47E Ch. 6.1 - Prob. 48E Ch. 6.1 - Prob. 49E Ch. 6.1 - Prob. 50E Ch. 6.1 - Prob. 51E Ch. 6.1 - Prob. 52E Ch. 6.1 - Prob. 53E Ch. 6.1 - Prob. 54E Ch. 6.1 - 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Prob. 48E Ch. 6.4 - Prob. 49E Ch. 6.4 - Prob. 50E Ch. 6.4 - Prob. 51E Ch. 6.4 - Prob. 52E Ch. 6.4 - Prob. 53E Ch. 6.4 - Prob. 54E Ch. 6.4 - Prob. 55E Ch. 6.4 - Prob. 56E Ch. 6.4 - Prob. 57E Ch. 6.4 - Prob. 58E Ch. 6.4 - Prob. 59E Ch. 6.4 - Prob. 60E Ch. 6.4 - Prob. 61E Ch. 6.4 - Prob. 62E Ch. 6.4 - Prob. 63E Ch. 6.4 - Prob. 64E Ch. 6.5 - Prob. 1PQ Ch. 6.5 - Prob. 2PQ Ch. 6.5 - Prob. 3PQ Ch. 6.5 - Prob. 4PQ Ch. 6.5 - Prob. 1E Ch. 6.5 - Prob. 2E Ch. 6.5 - Prob. 3E Ch. 6.5 - Prob. 4E Ch. 6.5 - Prob. 5E Ch. 6.5 - Prob. 6E Ch. 6.5 - Prob. 7E Ch. 6.5 - Prob. 8E Ch. 6.5 - Prob. 9E Ch. 6.5 - Prob. 10E Ch. 6.5 - Prob. 11E Ch. 6.5 - Prob. 12E Ch. 6.5 - Prob. 13E Ch. 6.5 - Prob. 14E Ch. 6.5 - Prob. 15E Ch. 6.5 - Prob. 16E Ch. 6.5 - Prob. 17E Ch. 6.5 - Prob. 18E Ch. 6.5 - Prob. 19E Ch. 6.5 - Prob. 20E Ch. 6.5 - Prob. 21E Ch. 6.5 - Prob. 22E Ch. 6.5 - Prob. 23E Ch. 6.5 - Prob. 24E Ch. 6.5 - Prob. 25E Ch. 6.5 - Prob. 26E Ch. 6.5 - Prob. 27E Ch. 6.5 - Prob. 28E Ch. 6.5 - Prob. 29E Ch. 6.5 - Prob. 30E Ch. 6.5 - Prob. 31E Ch. 6.5 - Prob. 32E Ch. 6.5 - Prob. 33E Ch. 6.5 - Prob. 34E Ch. 6.5 - Prob. 35E Ch. 6.5 - Prob. 36E Ch. 6.5 - Prob. 37E Ch. 6.5 - Prob. 38E Ch. 6.5 - Prob. 39E Ch. 6.5 - Prob. 40E Ch. 6.5 - Prob. 41E Ch. 6.5 - Prob. 42E Ch. 6.5 - Prob. 43E Ch. 6 - Prob. 1CRE Ch. 6 - Prob. 2CRE Ch. 6 - Prob. 3CRE Ch. 6 - Prob. 4CRE Ch. 6 - Prob. 5CRE Ch. 6 - Prob. 6CRE Ch. 6 - Prob. 7CRE Ch. 6 - Prob. 8CRE Ch. 6 - Prob. 9CRE Ch. 6 - Prob. 10CRE Ch. 6 - Prob. 11CRE Ch. 6 - Prob. 12CRE Ch. 6 - Prob. 13CRE Ch. 6 - Prob. 14CRE Ch. 6 - Prob. 15CRE Ch. 6 - Prob. 16CRE Ch. 6 - Prob. 17CRE Ch. 6 - Prob. 18CRE Ch. 6 - Prob. 19CRE Ch. 6 - Prob. 20CRE Ch. 6 - Prob. 21CRE Ch. 6 - Prob. 22CRE Ch. 6 - Prob. 23CRE Ch. 6 - Prob. 24CRE Ch. 6 - Prob. 25CRE Ch. 6 - Prob. 26CRE Ch. 6 - Prob. 27CRE Ch. 6 - Prob. 28CRE Ch. 6 - Prob. 29CRE Ch. 6 - Prob. 30CRE Ch. 6 - Prob. 31CRE Ch. 6 - Prob. 32CRE Ch. 6 - Prob. 33CRE Ch. 6 - Prob. 34CRE Ch. 6 - Prob. 35CRE Ch. 6 - Prob. 36CRE Ch. 6 - Prob. 37CRE Ch. 6 - Prob. 38CRE Ch. 6 - Prob. 39CRE Ch. 6 - Prob. 40CRE Ch. 6 - Prob. 41CRE Ch. 6 - Prob. 42CRE Ch. 6 - Prob. 43CRE Ch. 6 - Prob. 44CRE Ch. 6 - Prob. 45CRE Ch. 6 - Prob. 46CRE Ch. 6 - Prob. 47CRE Ch. 6 - Prob. 48CRE Ch. 6 - Prob. 49CRE Ch. 6 - Prob. 50CRE Ch. 6 - Prob. 51CRE Ch. 6 - Prob. 52CRE Ch. 6 - Prob. 53CRE Ch. 6 - Prob. 54CRE

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the total population within a 10-mile radius of the city centre if the radial population density is p ( r ) = 4 ( 1 + r 2 ) 1 3 (in thousands per square mile)

Solution Summary: The author calculates the total population within a 10-mile radius of the city centre if the radial population density is p (r) = 4 ( 1 + r 2 ) 1 3 which varies from centre of

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To calculate: the total population within a 10-mile radius of the city centre if the radial population density is $p (r) = 4 {(1 + r^{2})}^{\frac{1}{3}}$ (in thousands per square mile)

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Chapter 6 Solutions

the total population within a 10-mile radius of the city centre if the radial population density is p ( r ) = 4 ( 1 + r 2 ) 1 3 (in thousands per square mile)

Solution Summary: The author calculates the total population within a 10-mile radius of the city centre if the radial population density is p (r) = 4 ( 1 + r 2 ) 1 3 which varies from centre of

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Chapter 6 Solutions

To calculate: the total population within a 10-mile radius of the city centre if the radial population density is $p (r) = 4 {(1 + r^{2})}^{\frac{1}{3}}$ (in thousands per square mile)